How do you output variables to Ansible? [duplicate] - ansible

Question

This question already has answers here:
How to pass terraform outputs variables into ansible as vars_files?
(5 answers)
Closed 2 years ago.
I followed the answer here in this question and
I have created a template file tf_ansible_vars_file.yml.tpl like below
tf_share_location: "${share_location}"
and a terra_render.tf like below
# Define an Ansible var_file containing Terraform variable values
data "template_file" "tf_ansible_vars_file" {
template = "${file("/home/deployment_root/app4/tf_ansible_vars_file.yml.tpl")}"
vars = {
share_location = var.share_location
# gitlab_backup_bucket_name = aws_s3_bucket.gitlab_backup.bucket
}
}
# Render the Ansible var_file containing Terrarorm variable values
resource "local_file" "tf_ansible_vars_file" {
content = data.template_file.tf_ansible_vars_file.rendered
filename = "/home/deployment_root/app4/tf_ansible_vars_file.yml"
}
I already have a variables.tf file in which i have declared that variable
variable "share_location" {
type = string
}
and in the terraform.tfvars gave the value as null
share_location = null
when i run terraform apply i get the below error
Error: failed to render : <template_file>:1,23-37: Unknown variable; There is no variable named "share_location".
on terra_render.tf line 2, in data "template_file" "tf_ansible_vars_file":
2: data "template_file" "tf_ansible_vars_file" {
My understanding is it will create a file as mentioned in that answer, but it is not working.
How do you output variables to Ansible?

Answer 1

If you are generating a supported format like YAML, you do not need a template file.
You can generate YAML directly from Terraform data structures as follows:
resource "local_file" "tf_ansible_vars_file" {
content = yamlencode(
{
tf_share_location = var.share_location
# gitlab_backup_bucket_name = aws_s3_bucket.gitlab_backup.
}
)
filename = var.ansible_vars_filename
}
variable "ansible_vars_filename" {
type = string
default = "/home/deployment_root/app4/tf_ansible_vars_file.yml"
}
Applying that with -var="share_location=example_location" will yield a file like this:
"tf_share_location": "example_location"
Whether or not the quoting the configuration variable names matters depends on Ansible. It shouldn't as it's still valid YAML. Terraform's yamlencode quotes those regardless of whether they need to be, which is regrettable.
I have extracted ansible_vars_filename to a variable as you may want to make that configurable.
I have also left in the commented out gitlab_backup_bucket_name as adding it to the YAML file is as simple as uncommenting it.
You can learn more about yamlencode here:
https://www.terraform.io/docs/configuration/functions/yamlencode.html

Answer 2

In the below code, instead of var.share_location , i need to give the variable that i used in terraform in my case
${data.azurerm_storage_account.new.name}/sharename and after that i can remove that from variables.tf as well as terraform.tfvars as i am getting the value generated. Thanks
Old code :
data "template_file" "tf_ansible_vars_file" {
template = "${file("/home/deployment_root/app4/tf_ansible_vars_file.yml.tpl")}"
vars = {
share_location = var.share_location
# gitlab_backup_bucket_name = aws_s3_bucket.gitlab_backup.bucket
}
}
New Code:
# Define an Ansible var_file containing Terraform variable values
data "template_file" "tf_ansible_vars_file" {
template = "${file("/home/deployment_root/app4/tf_ansible_vars_file.yml.tpl")}"
vars = {
share_location = "${data.azurerm_storage_account.new.name}/sharename"
# gitlab_backup_bucket_name = aws_s3_bucket.gitlab_backup.bucket
}
}