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I have the following array of hashes:
[
{"BREAD" => {:price => 1.50, :discount => true }},
{"BREAD" => {:price => 1.50, :discount => true }},
{"MARMITE" => {:price => 1.60, :discount => false}}
]
And I would like to translate this array into a hash that includes the counts for each item:
Output:
{
"BREAD" => {:price => 1.50, :discount => true, :count => 2},
"MARMITE" => {:price => 1.60, :discount => false, :count => 1}
}
I have tried two approaches to translate the array into a hash.
new_cart = cart.inject(:merge)
hash = Hash[cart.collect { |item| [item, ""] } ]
Both work but then I am stumped at how to capture and pass the count value.
Expected output
{
"BREAD" => {:price => 1.50, :discount => true, :count => 2},
"MARMITE" => {:price => 1.60, :discount => false, :count => 1}
}
We are given the array:
arr = [
{"BREAD" => {:price => 1.50, :discount => true }},
{"BREAD" => {:price => 1.50, :discount => true }},
{"MARMITE" => {:price => 1.60, :discount => false}}
]
and make the assumption that each hash has a single key and if two hashes have the same (single) key, the value of that key is the same in both hashes.
The first step is create an empty hash to which will add key-value pairs:
h = {}
Now we loop through arr to build the hash h. I've added a puts statement to display intermediate values in the calculation.
arr.each do |g|
k, v = g.first
puts "k=#{k}, v=#{v}"
if h.key?(k)
h[k][:count] += 1
else
h[k] = v.merge({ :count => 1 })
end
end
displays:
k=BREAD, v={:price=>1.5, :discount=>true}
k=BREAD, v={:price=>1.5, :discount=>true}
k=MARMITE, v={:price=>1.6, :discount=>false}
and returns:
#=> [{"BREAD" =>{:price=>1.5, :discount=>true}},
# {"BREAD" =>{:price=>1.5, :discount=>true}},
# {"MARMITE"=>{:price=>1.6, :discount=>false}}]
each always returns its receiver (here arr), which is not what we want.
h #=> {"BREAD"=>{:price=>1.5, :discount=>true, :count=>2},
# "MARMITE"=>{:price=>1.6, :discount=>false, :count=>1}}
is the result we need. See Hash#key? (aka, has_key?), Hash#[], Hash#[]= and Hash#merge.
Now let's wrap this in a method.
def hashify(arr)
h = {}
arr.each do |g|
k, v = g.first
if h.key?(k)
h[k][:count] += 1
else
h[k] = v.merge({ :count=>1 })
end
end
h
end
hashify(arr)
#=> {"BREAD"=>{:price=>1.5, :discount=>true, :count=>2},
# "MARMITE"=>{:price=>1.6, :discount=>false, :count=>1}}
Rubyists would often use the method Enumerable#each_with_object to simplify.
def hashify(arr)
arr.each_with_object({}) do |g,h|
k, v = g.first
if h.key?(k)
h[k][:count] += 1
else
h[k] = v.merge({ :count => 1 })
end
end
end
Compare the two methods to identify their differences. See Enumerable#each_with_object.
When, as here, the keys are symbols, Ruby allows you to use the shorthand { count: 1 } for { :count=>1 }. Moreover, she permits you to write :count = 1 or count: 1 without the braces when the hash is an argument. For example,
{}.merge('cat'=>'meow', dog:'woof', :pig=>'oink')
#=> {"cat"=>"meow", :dog=>"woof", :pig=>"oink"}
It's probably more common to see the form count: 1 when keys are symbols and for the braces to be omitted when a hash is an argument.
Here's a further refinement you might see. First create
h = arr.group_by { |h| h.keys.first }
#=> {"BREAD" =>[{"BREAD"=>{:price=>1.5, :discount=>true}},
# {"BREAD"=>{:price=>1.5, :discount=>true}}],
# "MARMITE"=>[{"MARMITE"=>{:price=>1.6, :discount=>false}}]}
See Enumerable#group_by. Now convert the values (arrays) to their sizes:
counts = h.transform_values { |arr| arr.size }
#=> {"BREAD"=>2, "MARMITE"=>1}
which can be written in abbreviated form:
counts = h.transform_values(&:size)
#=> {"BREAD"=>2, "MARMITE"=>1}
See Hash#transform_values. We can now write:
uniq_arr = arr.uniq
#=> [{"BREAD"=>{:price=>1.5, :discount=>true}},
#= {"MARMITE"=>{:price=>1.6, :discount=>false}}]
uniq_arr.each_with_object({}) do |g,h|
puts "g=#{g}"
k,v = g.first
puts " k=#{k}, v=#{v}"
h[k] = v.merge(counts: counts[k])
puts " h=#{h}"
end
which displays:
g={"BREAD"=>{:price=>1.5, :discount=>true}}
k=BREAD, v={:price=>1.5, :discount=>true}
h={"BREAD"=>{:price=>1.5, :discount=>true, :counts=>2}}
g={"MARMITE"=>{:price=>1.6, :discount=>false}}
k=MARMITE, v={:price=>1.6, :discount=>false}
h={"BREAD"=>{:price=>1.5, :discount=>true, :counts=>2},
"MARMITE"=>{:price=>1.6, :discount=>false, :counts=>1}}
and returns:
#=> {"BREAD"=>{:price=>1.5, :discount=>true, :counts=>2},
# "MARMITE"=>{:price=>1.6, :discount=>false, :counts=>1}}
See Array#uniq.
This did the trick:
arr = [
{ bread: { price: 1.50, discount: true } },
{ bread: { price: 1.50, discount: true } },
{ marmite: { price: 1.60, discount: false } }
]
Get the count for each occurrence of hash, add as key value pair and store:
h = arr.uniq.each { |x| x[x.first.first][:count] = arr.count(x) }
Then convert hashes into arrays, flatten to a single array then construct a hash:
Hash[*h.collect(&:to_a).flatten]
#=> {:bread=>{:price=>1.50, :discount=>true, :count=>2}, :marmite=>{:price=>1.60, :discount=>false, :count=>1}}
Combined a couple of nice ideas from here:
https://raycodingdotnet.wordpress.com/2013/08/05/array-of-hashes-into-single-hash-in-ruby/
and here:
http://carol-nichols.com/2015/08/07/ruby-occurrence-couting/
I have these hashes:
hash = {1 => "popcorn", 2 => "soda"}
other_hash = {1 => "dave", 2 => "linda", 3 => "bobby_third_wheel"}
I would like to replace the id reference with the name associated to the id in the second hash, if there is a record in other_hash that has nothing to match, it should just be dropped in the resulting hash. Like this:
the_one_hash_to_rule_them_all = {"dave" => "popcorn", "linda" => "soda"}
You can easly use this each_with_object method on "primary" hash with names.
other_hash.each_with_object({}) { |(id, name), h| h[name] = hash[id] if hash.key?(id) }
# => {"dave"=>"popcorn", "linda"=>"soda"}
hash.each_with_object({}){|(k,v), res| res[other_hash[k]] = v}
# => {"dave"=>"popcorn", "linda"=>"soda"}
First, an "array-comprehension" with the pattern enumerable.map { expr if condition }.compact and finally an Array#to_h.
h = other_hash.map { |k, v| [v, hash[k]] if hash.has_key?(k) }.compact.to_h
#=> {"dave"=>"popcorn", "linda"=>"soda"}
Also:
h = other_hash.select { |k, v| hash.has_key?(k) }.map { |k, v| [v, hash[k]] }.to_h
hash.map{|k, v| [other_hash[k], v]}.to_h
# => {"dave"=>"popcorn", "linda"=>"soda"}
I created a hash that has an array as a value.
{
"0":[0,14,0,14],
"1":[0,14],
"2":[0,11,0,12],
"3":[0,11,0,12],
"4":[0,10,0,13,0,11],
"5":[0,10,0,14,0,0,0,11,12,0],
"6":[0,0,12],
"7":[],
"8":[0,14,0,12],
"9":[0,14,0,0,11,14],
"10":[0,11,0,12],
"11":[0,13,0,14]
}
I want the sum of all values in each array. I expect to have such output as:
{
"0":[24],
"1":[14],
"2":[23],
"3":[23],
"4":[34],
"5":[47],
"6":[12],
"7":[],
"8":[26],
"9":[39],
"10":[23],
"11":[27]
}
I do not know how to proceed from here. Any pointers are thankful.
I would do something like this:
hash = { "0" => [0,14,0,14], "1" => [0,14], "7" => [] }
hash.each { |k, v| hash[k] = Array(v.reduce(:+)) }
# => { "0" => [28], "1" => [14], "7" => [] }
For hash object you as this one.
hash = {"0"=>[0,14,0,14],"1"=>[0,14],"2"=>[0,11,0,12],"3"=>[0,11,0,12],"4"=>[0,10,0,13,0,11],"5"=>[0,10,0,14,0,0,0,11,12,0],"6"=>[0,0,12],"7"=>[],"8"=>[0,14,0,12],"9"=>[0,14,0,0,11,14],"10"=>[0,11,0,12],"11"=>[0,13,0,14]}
You could change value of each k => v pair
hash.each_pair do |k, v|
hash[k] = [v.reduce(0, :+)]
end
will resolve in
hash = {"0"=>[28], "1"=>[14], "2"=>[23], "3"=>[23], "4"=>[34], "5"=>[47], "6"=>[12], "7"=>[0], "8"=>[26], "9"=>[39], "10"=>[23], "11"=>[27]}
If your string is just like you mentioned you can parse it using JSON, or jump that step if you have already an Hash.
You can check the documentation of inject here
require 'json'
json_string = '
{
"0":[0,14,0,14],
"1":[0,14],
"2":[0,11,0,12],
"3":[0,11,0,12],
"4":[0,10,0,13,0,11],
"5":[0,10,0,14,0,0,0,11,12,0],
"6":[0,0,12],
"7":[],
"8":[0,14,0,12],
"9":[0,14,0,0,11,14],
"10":[0,11,0,12],
"11":[0,13,0,14]
}
'
hash = JSON.parse json_string
result = Hash.new
hash.each do |key, value|
result[key] = value.inject(:+)
end
puts result.inspect
and the result:
{"0"=>28, "1"=>14, "2"=>23, "3"=>23, "4"=>34, "5"=>47, "6"=>12, "7"=>nil, "8"=>26, "9"=>39, "10"=>23, "11"=>27}
Classic example for map/reduce. You need to iterate on the hash keys and values (map {|k,v|}), and for each value count the sum using reduce(0) {|acc, x| acc+x}
h = {1 => [1,2,3], 2 => [3,4,5], 7 => []} #example
a = h.map {|k,v| [k ,v.reduce(0) {|acc, x| acc+x}] }
=> [[1, 6], [2, 12], [7, 0]]
Hash[a]
=> {1=>6, 2=>12, 7=>0}
I was wondering how I could insert a hash into another hash. For example, in:
{"abcd"=>{}, "hgfe"=>34567}
I want to put "hgfe" => 34567 into the "abcd" key.
output:
{"abcd"=>{"hgfe" => 34567}}
im wanting to convert this hash
"##### RUBY HASH ####
(1)
INPUT
{
'abcd.hgfe' => 34567,
'abcd.efgh.hijk' => 12345,
'abcd.efgh.ijkl' => 56789,
'wxyz.abcd' => 9876,
'wxyz.uvwx.abcd' => 23456,
}
(1)
OUTPUT
{
'abcd' => {
'efgh' => {
'hijk' => 12345,
'ijkl' => 56789
},
'hgfe' => 34567,
},
'wxyz' => {
'abcd' => 9876,
'uvwx' => {'abcd' => 23456}
}
}
"
my currrent code:
def method1(hash)
result = {}
array2 = []
hash.each_pair do|k, v|
array1 = k.split('.')
count = array1.length
hash2 = {}
array1.each_with_index do |str, index|
if (index + 1) == count
hash2[str] = v
else
hash2[str] = {}
end
end
puts hash2.inspect
puts "--------------"
end
result
end
hash_result = method1(h2c)
Do as below
hash = {"abcd"=>{}, "hgfe"=>34567}
hash['abcd']['hgfe'] = hash.delete('hgfe')
hash # => {"abcd"=>{"hgfe"=>34567}}
You can write something like below :
def delete_key_and_add_to_another_key(hash, update_key, del_key)
hash[update_key][del_key] = hash.delete(del_key)
hash
end
hash = {"abcd"=>{}, "hgfe"=>34567}
delete_key_and_add_to_another_key(hash, 'abcd', 'hgfe')
h = {"abcd"=>{}, "hgfe"=>34567}
f, l = h.partition { |_,v| v =={} }.flatten(1)
{ f.first=> { l.first => l.last } }
#=> {"abcd"=>{"hgfe"=>34567}}
I have a Ruby hash which looks like:
{ "id" => "123", "name" => "test" }
I would like to convert it to:
{ :id => "123", :name => "test" }
hash = {"apple" => "banana", "coconut" => "domino"}
Hash[hash.map{ |k, v| [k.to_sym, v] }]
#=> {:apple=>"banana", :coconut=>"domino"}
#mu is too short: Didn't see word "recursive", but if you insist (along with protection against non-existent to_sym, just want to remind that in Ruby 1.8 1.to_sym == nil, so playing with some key types can be misleading):
hash = {"a" => {"b" => "c"}, "d" => "e", Object.new => "g"}
s2s =
lambda do |h|
Hash === h ?
Hash[
h.map do |k, v|
[k.respond_to?(:to_sym) ? k.to_sym : k, s2s[v]]
end
] : h
end
s2s[hash] #=> {:d=>"e", #<Object:0x100396ee8>=>"g", :a=>{:b=>"c"}}
If you happen to be in Rails then you'll have symbolize_keys:
Return a new hash with all keys converted to symbols, as long as they respond to to_sym.
and symbolize_keys! which does the same but operates in-place. So, if you're in Rails, you could:
hash.symbolize_keys!
If you want to recursively symbolize inner hashes then I think you'd have to do it yourself but with something like this:
def symbolize_keys_deep!(h)
h.keys.each do |k|
ks = k.to_sym
h[ks] = h.delete k
symbolize_keys_deep! h[ks] if h[ks].kind_of? Hash
end
end
You might want to play with the kind_of? Hash to match your specific circumstances; using respond_to? :keys might make more sense. And if you want to allow for keys that don't understand to_sym, then:
def symbolize_keys_deep!(h)
h.keys.each do |k|
ks = k.respond_to?(:to_sym) ? k.to_sym : k
h[ks] = h.delete k # Preserve order even when k == ks
symbolize_keys_deep! h[ks] if h[ks].kind_of? Hash
end
end
Note that h[ks] = h.delete k doesn't change the content of the Hash when k == ks but it will preserve the order when you're using Ruby 1.9+. You could also use the [(key.to_sym rescue key) || key] approach that Rails uses in their symbolize_keys! but I think that's an abuse of the exception handling system.
The second symbolize_keys_deep! turns this:
{ 'a' => 'b', 'c' => { 'd' => { 'e' => 'f' }, 'g' => 'h' }, ['i'] => 'j' }
into this:
{ :a => 'b', :c => { :d => { :e => 'f' }, :g => 'h' }, ['i'] => 'j' }
You could monkey patch either version of symbolize_keys_deep! into Hash if you really wanted to but I generally stay away from monkey patching unless I have very good reasons to do it.
If you are using Rails >= 4 you can use:
hash.deep_symbolize_keys
hash.deep_symbolize_keys!
or
hash.deep_stringify_keys
hash.deep_stringify_keys!
see http://apidock.com/rails/v4.2.1/Hash/deep_symbolize_keys
Just in case you are parsing JSON, from the JSON docs you can add the option to symbolize the keys upon parsing:
hash = JSON.parse(json_data, symbolize_names: true)
Victor Moroz provided a lovely answer for the simple recursive case, but it won't process hashes that are nested within nested arrays:
hash = { "a" => [{ "b" => "c" }] }
s2s[hash] #=> {:a=>[{"b"=>"c"}]}
If you need to support hashes within arrays within hashes, you'll want something more like this:
def recursive_symbolize_keys(h)
case h
when Hash
Hash[
h.map do |k, v|
[ k.respond_to?(:to_sym) ? k.to_sym : k, recursive_symbolize_keys(v) ]
end
]
when Enumerable
h.map { |v| recursive_symbolize_keys(v) }
else
h
end
end
Try this:
hash = {"apple" => "banana", "coconut" => "domino"}
# => {"apple"=>"banana", "coconut"=>"domino"}
hash.tap do |h|
h.keys.each { |k| h[k.to_sym] = h.delete(k) }
end
# => {:apple=>"banana", :coconut=>"domino"}
This iterates over the keys, and for each one, it deletes the stringified key and assigns its value to the symbolized key.
If you're using Rails (or just Active Support):
{ "id" => "123", "name" => "test" }.symbolize_keys
Starting with Ruby 2.5 you can use the transform_key method.
So in your case it would be:
h = { "id" => "123", "name" => "test" }
h.transform_keys!(&:to_sym) #=> {:id=>"123", :name=>"test"}
Note: the same methods are also available on Ruby on Rails.
Here's a Ruby one-liner that is faster than the chosen answer:
hash = {"apple" => "banana", "coconut" => "domino"}
#=> {"apple"=>"banana", "coconut"=>"domino"}
hash.inject({}){|h,(k,v)| h[k.intern] = v; h}
#=> {:apple=>"banana", :coconut=>"domino"}
Benchmark results:
n = 100000
Benchmark.bm do |bm|
bm.report { n.times { hash.inject({}){|h,(k,v)| h[k.intern] = v; h} } }
bm.report { n.times { Hash[hash.map{ |k, v| [k.to_sym, v] }] } }
end
# => user system total real
# => 0.100000 0.000000 0.100000 ( 0.107940)
# => 0.120000 0.010000 0.130000 ( 0.137966)
I'm partial to:
irb
ruby-1.9.2-p290 :001 > hash = {"apple" => "banana", "coconut" => "domino"}
{
"apple" => "banana",
"coconut" => "domino"
}
ruby-1.9.2-p290 :002 > hash.inject({}){ |h, (n,v)| h[n.to_sym] = v; h }
{
:apple => "banana",
:coconut => "domino"
}
This works because we're iterating over the hash and building a new one on the fly. It isn't recursive, but you could figure that out from looking at some of the other answers.
hash.inject({}){ |h, (n,v)| h[n.to_sym] = v; h }
You can also extend core Hash ruby class placing a /lib/hash.rb file :
class Hash
def symbolize_keys_deep!
new_hash = {}
keys.each do |k|
ks = k.respond_to?(:to_sym) ? k.to_sym : k
if values_at(k).first.kind_of? Hash or values_at(k).first.kind_of? Array
new_hash[ks] = values_at(k).first.send(:symbolize_keys_deep!)
else
new_hash[ks] = values_at(k).first
end
end
new_hash
end
end
If you want to make sure keys of any hash wrapped into arrays inside your parent hash are symbolized, you need to extend also array class creating a "array.rb" file with that code :
class Array
def symbolize_keys_deep!
new_ar = []
self.each do |value|
new_value = value
if value.is_a? Hash or value.is_a? Array
new_value = value.symbolize_keys_deep!
end
new_ar << new_value
end
new_ar
end
end
This allows to call "symbolize_keys_deep!" on any hash variable like this :
myhash.symbolize_keys_deep!
def symbolize_keys(hash)
new={}
hash.map do |key,value|
if value.is_a?(Hash)
value = symbolize_keys(value)
end
new[key.to_sym]=value
end
return new
end
puts symbolize_keys("c"=>{"a"=>2,"k"=>{"e"=>9}})
#{:c=>{:a=>2, :k=>{:e=>9}}}
Here's my two cents,
my version of symbolize_keys_deep! uses the original symbolize_keys! provided by rails and just makes a simple recursive call to Symbolize sub hashes.
def symbolize_keys_deep!(h)
h.symbolize_keys!
h.each do |k, v|
symbolize_keys_deep!(v) if v.is_a? Hash
end
end
Facets' Hash#rekey is also a worth mentioning.
Sample:
require 'facets/hash/rekey'
{ "id" => "123", "name" => "test" }.deep_rekey
=> {:id=>"123", :name=>"test"}
There is also a recursive version:
require 'facets/hash/deep_rekey'
{ "id" => "123", "name" => {"first" => "John", "last" => "Doe" } }.deep_rekey
=> {:id=>"123", :name=>{:first=>"John", :last=>"Doe"}}
Here's a little recursive function to do a deep symbolization of the keys:
def symbolize_keys(hash)
Hash[hash.map{|k,v| v.is_a?(Hash) ? [k.to_sym, symbolize_keys(v)] : [k.to_sym, v] }]
end