TypeGraphql - #inputtype on typeorm - graphql

Question

Hello I need to check if there is an email in the database already:
with this:
return User.findOne({ where: { email } }).then((user) => {
if (user) return false;
return true;
});
I have the following inputtypes:
#InputType()
export class RegisterInput {
#Field()
#IsEmail({}, { message: 'Invalid email' })
email: string;
#Field()
#Length(1, 255)
name: string;
#Field()
password: string;
}
I would like to know if there is any way for me to validate the email in the inputtype? or just in my resolve:
#Mutation(() => User)
async register(
#Arg('data')
{ email, name, password }: RegisterInput,
): Promise<User> {
const hashedPassword = await bcrypt.hash(password, 12);
const user = await User.create({
email,
name,
password: hashedPassword,
}).save();
return user;
}

Answer 1

Actually you can register your own decorator for class-validator
For example it can look something like this:
isEmailAlreadyExists.ts
import {
registerDecorator,
ValidationOptions,
ValidatorConstraint,
ValidatorConstraintInterface,
} from 'class-validator';
import { UserRepo } from '../../repositories/UserRepo';
import { InjectRepository } from 'typeorm-typedi-extensions';
#ValidatorConstraint({ async: true })
export class isEmailAlreadyExist
implements ValidatorConstraintInterface {
#InjectRepository()
private readonly userRepo: UserRepo;
async validate(email: string) {
const user = await this.userRepo.findOne({ where: { email } });
if (user) return false;
return true;
}
}
export function IsEmailAlreadyExist(validationOptions?: ValidationOptions) {
return function (object: Object, propertyName: string) {
registerDecorator({
target: object.constructor,
propertyName: propertyName,
options: validationOptions,
constraints: [],
validator: isEmailAlreadyExist,
});
};
}
If you're injecting dependencies than you should in inject it in class-validator too. Simply add to your main file this:
import { Container } from 'typedi';
import * as classValidator from 'class-validator';
classValidator.useContainer(Container);
...
const schema = await buildSchema({
resolvers: [...],
container: Container,
});
Then you can use decorator in your InputType
import { InputType, Field } from 'type-graphql';
import { IsEmailAlreadyExist } from '../../../utils/validators/isEmailAlreadyExist';
#InputType()
export class YourInput {
#Field()
#IsEmailAlreadyExist()
email: string;
}

Answer 2

I actually just figured this out myself for my own project.
You can simply add a validation on the email from RegisterInput argument and throw an error if the email already exists.
import { Repository } from 'typeorm'
import { InjectRepository } from 'typeorm-typedi-extensions'
...
// Use dependency injection in the resolver's constructor
constructor(
#InjectRepository(User) private readonly userRepository: Repository<User>
) {}
...
// Your mutation
#Mutation(() => User)
async register(
#Arg('data')
{ email, name, password }: RegisterInput,
): Promise<User> {
const hashedPassword = await bcrypt.hash(password, 12);
const userWithEmail = this.userRepository.find({ email: email })
// If a user with the email was found
if (userWithEmail) {
throw new Error('A user with that email already exists!')
}
const user = await User.create({
email,
name,
password: hashedPassword,
}).save();
return user;
}
To use the InjectRepository make sure you add a "container" to your buildSchema function:
import { Container } from 'typedi'
...
const schema = await buildSchema({
resolvers: [...],
container: Container
})
Let me know if this works out for you? Thanks!