I am using guzzle to post data to the api as below. When i post, the api returns Error: Pass content as json or plain text. Is it possible to convert content to JSON or Plain Text in the code below
How can I resolve this?
Controller
$headers = [
'Content-Type' => 'application/x-www-form-urlencoded',
];
$client = new \GuzzleHttp\Client([
'headers' => $headers
]);
$body = '{
"item" : Summer-Jacket,
"content" : Hi
}';
$url = "https://api.com";
$request = $client->post($url,
[
'body' => $body
] );
$response = $request->send();
Firstly your body is not even valid JSON. Strings needs to have "string" around them
To post JSON with guzzle, you can instead use the RequestOptions for exactly that.
$result = $client->post("https://api.com", [
RequestOptions::JSON => [
'item' => 'Summer-Jacket',
'content' => 'hi',
]
)->getBody();
Related
i'm running graphql query through array in Laravel postAsyn. any solution for that. below i added graphql query.
$client = new Client([
// Base URI is used with relative requests
'base_uri' => $url,
// You can set any number of default request options.
'timeout' => 300.0,
]);
foreach($arr as $value){
$graphQLquery = '{'.
'"query": "query viewer {'.
'repositories(last: '. $value . ') {'.
'nodes {'.
'name'.
'id'.
'isPrivate'.
'nameWithOwner'.
'}'.
'}'.
'}",'.
'"variables": { "name": "'.$name.'", "id": "1", "isPrivate ": "True", "nameWithOwner": "VimDiesel"}'.
'}';'
}
$params = [
'query' => [
'access_token' => $token,
'query' => $query[0]
]
];
$promises = [
'image' => $client->postAsync('POST', 'graphql', json_encode($params))
];
$responses = Promise\Utils::unwrap($promises);
if anyone have solution for that please add. i need run this all queries concurrent processing. i'm using guzzelhttp.
Laravel project 1 controller how to forward file to API-2
Input::file('songFile')->move("/tmp", $newname);
i used this function and store tmp location then how to use this tmp location file and forward?
In order to post a file to API endpoint, you can follow the following code.
try{
$path = 'var/www/html/myproject/public/file.txt';//your file path
if (!empty($path) && file_exists($path)) {
$guzzleResponse = $client->post($api_url, [
'multipart' => [
[
'name' => 'file',// it is the name as specfied in the payload of api_url
'contents' => fopen($path, 'r')// or you can use file_get_contents()
]
],
'headers' => $headers
]);
}
if ($guzzleResponse->getStatusCode() == 200) {
$response = json_decode($guzzleResponse->getBody());// whatever you want to do with response
}
}catch(RequestException $e){
return $e; //You can also handle specific status codes here using eg $e->getResponse()->getStatusCode() == '400'
}
Also $headers can be like this
[
'Accept' => 'application/json',
'Authorization' => 'Bearer '. $userToken,
]
See more information in Guzzle
Im trying to upload a file to sharepoint
Successful try with just axios is the following
Failure if i upload using Guzzle
Uploaded file at the end is corrupted
There are a few things you need to modify to get this working (tested on my end):
To get the contents of the file, you need $request->file('file') and then use file_get_contents() on it. You can lose the get() part.
Make sure you're sending the header to accept multipart/form-data too:
"Accept" => "multipart/form-data"
Fields name and filename in a form are two different things. Former is the name of the field while the latter is the name of the file. You need to send both.
Try this:
protected function uploadFile(Request $request){
$file = $request->file('file');
$body = [
"headers" => [
"Accept" => "multipart/form-data",
"Authorization" => "Bearer {$this->token}"
],
"multipart" => [
"name" => "file",
"contents" => file_get_contents($file),
"filename" => $file->getClientOriginalName()
]
];
return (new Client)->request('POST', 'https://.sharepoint.com/...', $body);
}
P.S. - You can check whether a file is valid or not using isValid():
if ($request->file('file')->isValid()) {
//
}
Official docs on this: https://laravel.com/docs/7.x/requests#retrieving-uploaded-files
When providing content to be uploaded to Guzzle client as string,
Guzzle tries to infer necessary information about the file such as filename, content-type.
You can help Guzzle to infer these information correctly to build the multipart request by passing information about about the filename and content-type in the multipart payload.
[
//...
'multipart' => [
[
'name' => 'fileName',
'contents' => $request->file('file')->get(),
'filename' => $request->file('file')->getName(),
'headers' => [
'content-type' => $request->file('file')->getMimeType(),
]
]
]
]
Add content-type as blob.
axios.post(
'https://sharepoint....'
,data.get('file')
{
'headers' {
'Authorization': `Bearer ${this.token}`
,'Content-Type': 'blob',
}
}
)
Try something like this.
Remove the ->get() of your $request->file()
//Get the file object from the request.
$file = $request->file('file');
//Make the request
return (new Client)->request('POST', 'https://.sharepoint.com/sites....', [
'headers' => [ 'Authorization' => "Bearer {$this->token}" ],
'multipart' => [
[
'name' => 'FileContents',
'contents' => $file,
'filename' => $file->getClientOriginalName()
],
],
]);
In my opinion, you should store it somewhere in your local server temporarily first, and then you sent that file to sharepoint, deleted the temporary file, I think if you send it right away without storing it, the file will be corrupted. Please try the way below
$file = $request->file('logo');
$original_name = $file->getClientOriginalName(); // get original file
$name = time() . '_' . $original_name; // store it in different name so it would not be duplicated
$path = base_path() .'/public_html/your_project/public/temporary/'; // full path of file folder
// store the uploaded file
$file->move($path, $name);
$body = [
"headers" => [
"Authorization" => "Bearer {$this->token}"
],
"multipart" => [
"name" => "logo",
"contents" => fopen($path . $name, 'r')
]
];
$response = (new Client)->request('POST', 'https://.sharepoint.com/...', $body);
// remove the file after done
unlink($path . $name);
return $response;
Hope this would work for you! Please correct me if I was wrong
I have an API get list user. postmen
and Headers Content-Type = application/json
- In laravel, I use guzzle to call api
code demo:
$client = new Client();
$headers = ['Content-Type' => 'application/json'];
$body = [
'json' => [
"filter" => "{}",
"skip" => 0,
"limit" => 20,
"sort" => "{\"createAt\": 1}",
"select" => "fullname username",
"populate" => "'right', 'group'",
]
];
\Debugbar::info($body);
$response = $client->get('http://sa-vn.com:2020/api/users/user', [
'form_params' => $body
]);
echo $response->getBody();
But it does not working! please help me
form_params and body both are different params in guzzle. check json
$json = [
"filter" => json_encode((object)[]),
"skip" => 0,
"limit" => 20,
"sort" => json_encode((object)['createAt'=>1]),
"select" => "fullname username",
"populate" => "'right', 'group'"
];
$response = $client->request('get', 'http://sa-vn.com:2020/api/users/user', [
'json' => $json,
]);
If any error occur try without json_encode as well.
$json = [
"filter" => (object)[],
"skip" => 0,
"limit" => 20,
"sort" => (object)['createAt'=>1],
"select" => "fullname username",
"populate" => "'right', 'group'"
];
As per Guzzle doucmentation
form_params
Used to send an application/x-www-form-urlencoded POST request.
json
The json option is used to easily upload JSON encoded data as the body of a request. A Content-Type header of application/json will be added if no Content-Type header is already present on the message.
You are passing json data in postman. So you can use json instead of form_params
Change
$response = $client->get('http://sa-vn.com:2020/api/users/user', [
'form_params' => $body
]);
to
$response = $client->get('http://sa-vn.com:2020/api/users/user', [
'json' => $body
]);
I have a controller through which I send data to my local environment of the api platform (which is running fine)
/**
* Creates a new Location entity.
*
*/
public function createAction(Request $request)
{
$this->get("suvya_breadcrumbs.factory")->update('New Hub');
$form = $this->createForm(HubType::class);
$form->handleRequest($request);
$new_url = $this->generateUrl('new_hub');
$redirect_url = $this->generateUrl('home');
if ($form->isSubmitted() && $form->isValid()) {
$client = new Client([
'base_uri' => 'http://127.0.0.1:8000',
]);
$response = $client->request('POST', '/hubs', [
'form_params'=> $form->getData(),
'headers' => [
'Accept' => 'application/ld+json',
'Content-Type'=> 'application/json',
'Authorization'=> 'eyJhbGciOiJSUzI1NiJ9.eyJyb2xlcyI6WyJST0xFX1VTRVIiXSwidXNlcm5hbWUiOiJhZG1pbiIsImlhdCI6MTUxNzg3NjE1NCwiZXhwIjoxNTE3ODc5NzU0fQ.gIG9lueJJZxzkOl8qblhHWwiJvW97m4gz1-1mYeM9SgMzMW35Wh6XamOOYiISDN99yJ6Ovo-wKk6whpE5UGMDVw_wGek003Dd6r-Y7Ql3kVLHksn2JFzhAN3GwlXFcOI4MIjmq5qBhkzv21pHymO0yn1SlzWBwb0O7WygywefMu5p09zGuvAiP9I2ShyQLZhjj8bB_odf3dI-Ql0ZbRmn_JDkDoPcm5U11i-3S1oMikBmFq0WtTcWo7vezt3QdA3bY4_bgaISINAiYRR-_cvjpBSqFSE6n1ZYtHvKFn-98wXXsBGxEAoZw6iQL4iRgOI8F_uaiCo0eRHC7q0_xQ_V_W0-5XDIQXWDwoiVaUXnjO6xo2Fldp7PLO1ueJz1e4wiOy2-TunZdc8UCtw2BdFIQtWatPLi_v_rsNvF2H-6hwa9UOKEi9Z4tH4KkuATbXAxxfkCbSOyY1SAWP0riooPQi_AI2J7L2Ly86eAuKo1Hix3EuEogo19GSyBz_cCWczyERQWM9gikuUs8E22SIAdxTl8ZLFaXgiZIibDvb8pqcN8izFjywWbF2CkyWC58WxrVd6Bfmfnm7k9T6oZqwIZ-TQR-SbRnUHN1hpWUjFCk-tHhgvh7osHXmxe3grzA8M3LPBpQGQiTeqBZFMjF4Tx8zW2tuiEn6TwhV14Lj24Vc'
]
]);
die();
}
return $this->render('SuvyaFabricsCloudBundle:Common:basic.html.twig', array(
'form' => $form->createView(),
'page_title'=> 'Hub aanmaken',
'action_path' => $new_url,
'cancel_path'=> $redirect_url,
'submit_button_title' => 'Opslaan',
));
}
But unfortunately i'm getting an error in my dev.log of the api environment:
[2018-02-06 02:32:37] request.INFO: Matched route "api_hubs_post_collection". {"route":"api_hubs_post_collection","route_parameters":{"_controller":"api_platform.action.post_collection","_format":null,"_api_resource_class":"AppBundle\\Entity\\Hub","_api_collection_operation_name":"post","_route":"api_hubs_post_collection"},"request_uri":"http://127.0.0.1:8000/hubs","method":"POST"} []
[2018-02-06 02:32:37] request.CRITICAL: Uncaught PHP Exception Symfony\Component\Serializer\Exception\UnexpectedValueException: "Syntax error" at /Users/myname/Sites/suvyalogistics-api/vendor/symfony/symfony/src/Symfony/Component/Serializer/Encoder/JsonDecode.php line 78 {"exception":"[object] (Symfony\\Component\\Serializer\\Exception\\UnexpectedValueException(code: 0): Syntax error at /Users/myname/Sites/suvyalogistics-api/vendor/symfony/symfony/src/Symfony/Component/Serializer/Encoder/JsonDecode.php:78)"} []
The output of form->getData():
array (size=4)
'postalCode' => string 'sdfdsf' (length=6)
'streetName' => string 'sdfsdf' (length=6)
'doorNumber' => string 'sdfsfd' (length=6)
'city' => string 'sdfsfd' (length=6)
Running the endpoint at the api platform with the same values goes fine as well.
Does anyone of you has an idea why this goes wrong?
You're sending a payload encoded in application/x-www-form-urlencoded (HTML form like) to the API Platform API, while, according to the headers you've set, it excepts data encoded in JSON.
To encode the data of the form in JSON, you can use the following Guzzle snippet:
$client = new Client([
'base_uri' => 'http://127.0.0.1:8000',
]);
$response = $client->request('POST', '/hubs', [
'json' => $form->getData(),
'headers' => [
'Accept' => 'application/ld+json',
'Authorization'=> '...'
]
]);
Alternatively, you can configure API Platform to accept form data, but I would not recommend going this way (it's better to only deal with JSON API-side).