Enclose text after equals with double quotes - bash

Question

I am getting some data and putting that into a file with a sed command
awk '/name_of_the_person/{getline; print}' file_name | cut -d '>' -f 2 | cut -f 1 -d'<' |sed 's/^/export FIRST_NAME=/' >> /tmp/source
awk '/clan_of_the_person/{getline; print}' file_name | cut -d '>' -f 2 | cut -f 1 -d'<' |sed 's/^/export LAST_NAME=/' >> /tmp/source
and then I finally source this file to export the variables.
The problem that I am facing is that sometimes some people have multiple first names and last names and my file ends up like this
export FIRST_NAME=JEAN PAUL
export LAST_NAME=SMITH
This ends up breaking my export statement. Is there a way I can add quotes after the = till the end of the line so that it becomes
export FIRST_NAME="JEAN PAUL"

Answer 1

With GNU sed and a back-reference:
echo 'export FIRST_NAME=JEAN PAUL' | sed -E 's/=(.*)/="\1"/'
Output:
export FIRST_NAME="JEAN PAUL"

Answer 2

You could use a subshell to isolate the match. This has an added advantage of taking out the sed:
echo "export FIRST_NAME=\"$(awk '/name_of_the_person/{getline; print}' file_name | cut -d '>' -f 2 | cut -f 1 -d'<')\"" >> /tmp/source
echo "export LAST_NAME=\"$(awk '/clan_of_the_person/{getline; print}' file_name | cut -d '>' -f 2 | cut -f 1 -d'<')\"" >> /tmp/source
It might look cleaner with separate variables:
fname="$(awk '/name_of_the_person/{getline; print}' file_name | cut -d '>' -f 2 | cut -f 1 -d'<')"
lname="$(awk '/clan_of_the_person/{getline; print}' file_name | cut -d '>' -f 2 | cut -f 1 -d'<')"
{
echo "export FIRST_NAME=\"$fname\""
echo "export LAST_NAME=\"$lname\""
} >> /tmp/source