Data:
ID PARENT_ID
1 [null]
2 1
3 1
4 2
Desired result:
ID CHILD_AT_ANY_LEVEL
1 2
1 3
1 4
2 4
I've tried SYS_CONNECT_BY_PATH, but I don't understand how to convert it result into "inline view" which I can use for JOIN with main table.
select connect_by_root(id) id, id child_at_any_level
from table
where level <> 1
connect by prior id = parent_id;
Related
image
image2
Now I have like this
image3
but I want have more categories
like this
How to select many category?
Let’s say in your case, we need to define the category for every features. So feature can have many categories and inverse category can have many features. Thus, it will be a Many To Many relationships.
To accomplish this we need to create 3 tables features, categories, and intermediate table feature_category. The feature_category table will have the feature_id and category_id column which connects both feature and category table and this intermediate table called the pivot table.
Here are the table structures:
features
id - integer
name - string
categories
id - integer
name - string
feature_category
feature_id - integer
category_id - integer
=> category
id name
-- -------
1 Category 1
2 Category 2
3 Category 3
4 Category 4
=> features
id name
-- -------
1 Feature 1
2 Feature 2
3 Feature 3
4 Feature 4
=> feature_category
id feature_id category_id
-- ------- -------
1 1 1
2 2 2
3 3 2
4 3 3
4 3 4
===============================
Our feature_category table before sync() operation:
id feature_id category_id
-- ------- -------
1 1 1
2 2 2
3 2 3
4 2 4
5 3 2
6 4 3
Laravel Sync() example:
<?php
use App\Models\Feature;
$user = Feature::find(2);
// Want to keep only "Category 2" (Id 2) category
$user->category()->sync([2]);
After performing the above operation, our feature_category table will look like below:
id feature_id category_id
-- ------- -------
1 1 1
2 2 2
5 3 2
6 4 3
Checkboxes or dropdowns can be used from the frontend to select multiple categories for features and sync() method can be used to update feature cards accordingly.
First you need to create new table feature_category with two fields :
(same type of features.id) feature_id
(same type of categories.id) category_id
Second create belongsToMany relationship directly in Voyager.
Example :
I have a table that contains one or more records for each item. Each item can contain multiple sub-items (boards) and so the Itemid is often replicated with each record showing the division category (a number) that the Item/sub-item combo resides in:
ItemId Board# Division
142585109 0 6
142585114 0 3
142585116 0 1
142585120 0 4
142585197 0 5
142585197 2 4
142585197 3 3
142585197 5 6
142585197 8 1
142585294 0 4
142585317 0 1
I want to update the table and aggregate all of the division values (as a comma separated string) in a new field in this table, something like:
ItemId Board# AggDivisions
142585109 0 6
142585114 0 3
142585116 0 1
142585120 0 4
142585197 0 1,3,4,5,6
142585294 0 4
142585317 0 1
I used a ListAgg query to do the aggregation which works correctly but when I tried to incorporate this into an update query, I end up with multiple duplicates in the aggregated field for each record.
Here is my update attempt:
update itemtable dd
set aggregateddivisions = (SELECT Listagg(division, ',') within GROUP (ORDER BY division)
FROM itemtable ev
WHERE ev.itemid = dd.itemid
)
where exists (select 1
from itemtable ev
where ev.itemid = dd.itemid
);
How can I update the table with the aggregated list of values from the same table without ending up with duplicates?
I have one table scores where I have saving users scores. It's looks like this
table `scores`
id | points | user_id
1 5 1
2 2 1
3 4 1
4 1 3
5 10 2
I want to select each user, sum his points and show as a ranking. The result from above should be
user_id | points
1 11
2 10
3 1
The query with which I came up is
$sumPoints = Scores::select( \DB::raw("sum(points) as numberOfPoints"), \DB::raw("count(id) as numberId"))->groupBy("user_id")->first();
The problem is in ->first() because it's return only one result.. it is working as must. If I try to use ->get() instead I've got Undefined property error. How should I use this?
The query which is working in phpmyadmin
SELECT count(id) as numberId, sum(points) as numberOfPoints FROM `points` GROUP BY `user_id`
You can use something like this
$sumPoints = Scores::select( \DB::raw("sum(points) as numberOfPoints"), \DB::raw("count(id) as numberId"))->groupBy("user_id")->get();
foreach($sumPoints as $point){
dd($point); //OR dd($point->numberOfPoints)
}
Problem is in left outer join, when there are no rows in right side table then it does not display null values, it displays previous values....
Like this....
1 st Table contains
PGMTX_CODE PGMTX_MARKS PGMTX_TOTQSTN
-------------------------------------------
EE 1 5
EE 2 5
EE 3 0
EE 4 0
2 nd Table contains
PGMTX_CODE PGMTX_MARKS PGMTX_ACTUSEDQST
-------------------------------------------
EE 1 5
So I want result like...
PGMTX_MARKS PGMTX_TOTQSTN PGMTX_ACTUSEDQST
--------------------------------------------------
1 5 5
2 5 blank
3 0 blank
4 0 blank
I use query like this...
SELECT m.PGMTX_MARKS,
m.PGMTX_TOTQSTN,
tlm.PGMTX_ACTUSEDQST,
from PAPERGEN_MTL_OEX m
left OUTER JOIN PAPERGEN_TLMTL_OEX tlm
ON m.PGMTX_CODE=tlm.PGMTX_CODE
where m.PGMTX_CODE='EE'
order by m.PGMTX_MARKS
But I got result like
PGMTX_MARKS PGMTX_TOTQSTN PGMTX_ACTUSEDQST
--------------------------------------------------
1 5 5
2 5 5
3 0 5
4 0 5
Your join condition is wrong, should be
ON m.PGMTX_CODE=tlm.PGMTX_CODE AND m.PGMTX_MARKS = tlm.PGMTX_MARKS
I need return a query where all the unique page numbers are returned with the max version number of each page.
Here is the an example of the data that I'd query
DocumentID PageNumber Version
1 1 1
1 2 1
1 2 2
1 3 1
1 3 2
1 3 3
And here is what I would need to get returned in my query
DocumentID PageNumber Version
1 1 1
1 2 2
1 3 3
Not sure how to finish this:
var pages = from p in dc.Pages where p.DocumentID == 1 && ...
I think this is what you're trying to achieve:
var results =
from p in dc.Pages
where p.DocumentID == 1
group p by p.PageNumber into g
select new
{
PageNumber = g.Key,
MaxVersion = g.Max(x => x.Version)
};
This query may help you:
Select DocumentID ,Distinct PageNumber, max(version) from table
group by DocumentID, Distinct PageNumber