we have an element on our booking page ".ItineraryDate [datetime]:last" which displays the date of the last flight in the itinerary (e.g. Tue 7 Jul). For the purpose of a Cypress test, I need to extract the day (e.g. 7) and the month (e.g. Jul).
cy.get(".ItineraryDate [datetime]:last").then($span => {
const lastLegDate = $span.text()
})
This code creates const Tue 7 Jul, but I need to use only the day and the month. Do you know how could I extract it?
Cypress automatically includes moment.js and exposes it as Cypress.moment.
Refer moment formats
You can extract the month and day in anyway you want using Cypress.moment.
Markup:
<div class="date">Tue 7 Jul</div>
Test:
cy.get('.date').then(($el) => {
cy.log('original: ' + $el.text());
const dateString = Cypress.moment($el.text(), 'ddd D MMM')
const month = Cypress.moment(dateString, 'ddd D MMM').format('MMMM');
const day = Cypress.moment(dateString, 'ddd D MMM').format('D');
cy.log(`After formatting month = ${month}`);
cy.log(`After formatting day = ${day}`);
expect(month).to.equal('July');
expect(day).to.equal('7');
});
Screenshot:
Related
Actually I'm trying to to shift the time, the application I'm working on is in UTC and I'm working in IST.
I've used both BEAN Shell pre processor and shiftTime function
import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;
int AddSeconds= 00; //this variable needs to be customized as per your need
int AddMinutes= 392; //this variable needs to be customized as per your need
int AddHours= 00; //this variable needs to be customized as per your need
Date now = new Date();
Calendar c = Calendar.getInstance();
c.setTime(now);
c.add(Calendar.SECOND, AddSeconds);
c.add(Calendar.MINUTE, AddMinutes);
c.add(Calendar.HOUR, AddHours);
Date NewTime = c.getTime();
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
String mytime = df.format(NewTime);
vars.put("NewTime",mytime);
Shift Time :
"${__timeShift(yyyy-MM-dd'T'HH:mm:ss.SSS'Z',,PT393M,,)}"
Bun when I run the HTTP Request in Jmeter the time format is coming in 12Hrs only instead of 24 Hr
Also Time shift is taking in weird manner, I've tried all options from Stackoverflow from last 2 days and unable to achieve my task to convert IST to UTC.
This is what I'm using in Jmeter Post body
enter image description here
And this is what I'm getting as result
enter image description here
Time formats are getting totally mismatched here, can someone please help me to convert IST to UTC correctly while playing with these time formats and functions.
I don't think you can use __timeShift() function for getting the date in the different timezone, it will return you the current (default) one
So if you need to add 392 minutes to the current time in the time zone different from yours - you will have to go for __groovy() function and use TimeCategory class
Example code:
${__groovy(def now = new Date(); use(groovy.time.TimeCategory) { def nowPlusOneYear = now + 392.minute; return nowPlusOneYear.format("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'"\,TimeZone.getTimeZone('IST')) },)}
Demo:
If you need to get the time in UTC just change IST to UTC
${__groovy(def now = new Date(); use(groovy.time.TimeCategory) { def nowPlusOneYear = now + 392.minute; return nowPlusOneYear.format("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'"\,TimeZone.getTimeZone('UTC')) },)}
More information: Creating and Testing Dates in JMeter - Learn How
Also be informed that since JMeter 3.1 you're supposed to be using JSR223 Test Elements and Groovy language for scripting
Just adding one more way to do this via bean shell preprocessor and it worked for me pretty well.
Here is the code to use... here -325 minutes is the difference between IST and UTC
import java.text.SimpleDateFormat;
import java.util.Calendar;
import java.util.Date;
int AddSeconds= 00; //this variable needs to be customized as per your need
int AddMinutes= -325; //this variable needs to be customized as per your need
int AddHours= 00; //this variable needs to be customized as per your need
Date now = new Date();
Calendar c = Calendar.getInstance();
c.setTime(now);
c.add(Calendar.SECOND, AddSeconds);
c.add(Calendar.MINUTE, AddMinutes);
c.add(Calendar.HOUR, AddHours);
Date NewTime = c.getTime();
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
String mytime = df.format(NewTime);
vars.put("NewTime",mytime);
// NewTime is your jmeter variable
I am trying to create a simple script that prompts the user for their birthday, formatted as 10.02.20, then takes that string and turns it into text, such as October 2nd 2020. I have the following code:
Dim bd, message, title ' define variables
title = "What is your birthday?" ' set variable
message = "Format like so: 12.15.07; 3.03.05" ' set variable
bd = InputBox(message, title) ' prompt user
Dim year
year = bd.Substring(6, 2)
Dim month
month = bd.Substring(0, 2)
Dim day
day = bd.Substring(3, 2)
msgbox bd ' for testing
call msgbox(year + month + day) 'also testing
And I am getting an error after the prompt, ...\Desktop\test.vbs(8, 1) Microsoft VBScript runtime error: Object required: '12.23.03' and I am not sure what it means, Object Required.
Any fixes or suggestions would be very much appreciated.
You cannot use Substring in VBScript. You can use Mid instead:
Dim year
year = Mid(bd, 7, 2)
The first character in a string is at position 1, not 0, so I adjusted your parameter from 6 to 7.
Also, to concatenate strings, although + works, you can also use &:
call msgbox(year & month & day)
You can use this function in vbscript : FormatDateTime(date,format)
Parameter Description
date Required.
Any valid date expression (like Date() or Now())
format Optional.
A value that specifies the date/time format to use can take the following values:
0 = vbGeneralDate - Default. Returns date: mm/dd/yyyy and time if specified: hh:mm:ss PM/AM.
1 = vbLongDate - Returns date: weekday, monthname, year
2 = vbShortDate - Returns date: mm/dd/yyyy
3 = vbLongTime - Returns time: hh:mm:ss PM/AM
4 = vbShortTime - Return time: hh:mm
Dim Title,Input
Title = "format date"
Input = InputBox("Enter your date of Birthday !",Title,"10.02.20")
Input = FormatDateTime(Replace(Input,".","/"),1)
MsgBox Input
Lets assume we have the following date: 2019, 11, 1.
I want to display only the month's name, but MMMM formatting results into "ноября", when I expect to get "ноябрь".
It works OK in moment.js (locale: ru):
// if format starts with month name
moment([2019, 11, 1]).format('MMMM') => 'ноябрь'
// if format doesn't start with month name
moment([2019, 11, 1]).format('DD MMMM') => '1 ноября'
I would like to switch to moment.js, although I am already utilizing the library which strictly depends on date-fns. How can I achieve the format to show the month's name correctly in Russian language?
date-fns's GitHub repo
My workaround for this problem in use case for react-datepicker was to pass month name in cyrilic as format.
const getMonthName = (date) => {
const months = ['Январь', 'Февраль', 'Март', 'Апрель', 'Май', 'Июнь', 'Июль', 'Август', 'Сентябрь', 'Октябрь', 'Ноябрь', 'Декабрь'];
return months[date.getMonth()];
};
<DatePicker dateFormatCalendar={ getMonthName(new Date()) } />
format(new Date(2014, 1, 11), getMonthName(new Date(2014, 1, 11)))
Worked under my limited use case
You need to change MMMM to LLLL
I would like to know what could be the best way to obtain the starting date values for each month based on the date range.
For example: If I am given a year range of 2015-11-10 and 2018-01-15(format YYYY-mm-dd). Then I would like to extract following dates:
2015-12-01
2016-01-01
.
.
2018-01-01
You can try to use this flow for generating the first day of each month in the provided date range.
Overall flow
Step 1 Configuration: Start
Step 2 Configuration: Configure Date Range
Provide the start and end dates as configuration parameters via this step.
Step 3 Configuration: Generate First Dates For Months
This uses a Groovy script, which is provided below
Groovy script
flowFile = session.get();
if(!flowFile)
return;
DATE_FORMAT = 'yyyy-MM-dd';
startDate = Date.parse(DATE_FORMAT, flowFile.getAttribute("start_date"));
endDate = Date.parse(DATE_FORMAT, flowFile.getAttribute("end_date"));
allFirstDates = "";
Calendar calendar = Calendar.getInstance();
Set firstDaysOfMonths = new LinkedHashSet();
for (int i = 0; i <= endDate-startDate; i++) {
calendar.setTime(startDate.plus(i));
calendar.set(Calendar.DAY_OF_MONTH, 1);
firstDayOfMonth = calendar.getTime();
if (firstDayOfMonth.compareTo(startDate) >= 0) {
firstDaysOfMonths.add(calendar.getTime().format(DATE_FORMAT));
}
}
firstDaysOfMonths.each {
firstDayOfMonth -> allFirstDates = allFirstDates + firstDayOfMonth + "\n";
}
flowFile = session.putAttribute(flowFile,"all_first_dates", allFirstDates );
session.transfer(flowFile,REL_SUCCESS)
Step 4 Configuration: View Result
Output of run:
When the flow is run, the attribute all_first_dates will be populated with the first dates of each month in the date range.
I am in requirement for solution where I have one Admin posts application for an Android app. I have placed a delete button for post. The requirement is that delete button must be shown for 5 minutes from time of posting.
Here is the ngif condition which I have used..
*ngIf="((((post.CreatedDate | date:'dd/MM/yyyy') == (PresentDate | date:'dd/MM/yyyy')) && ((post.CreatedDate | date:'HH') == (post.CreatedDate | date:'HH')))&&((post.CreatedDate | date:'mm')< (time)))"
Code in TS page for present time + 5 minutes
const d: Date = new Date();
this.PresentDate = d;
var x = new Date();
d.getHours(); // => 9
d.getMinutes(); // => 30
this.time = d.getMinutes() +5;
this.hours = d.getHours();
Please help with the solution
Long expression in html is not good practice.
*ngIf="canDeletePost(post)"
canDeletePost(post) {
return Date.now() - post.CreatedDate.getTime() < 5 * 60 * 1000;
}
If CreatedDate is Js date. 5 * 60 * 1000 - 5 min in milliseconds. Actually, have a method in ngIf is not good practice also.
Anyway, you don't need date pipe. Pipes is used for changing view.