how to read NON-ASCII Char in the file as ASCII using AWK - bash

Question

My input file:
000000000 vélIstine IOBAN 00000004960
000000000 shankargu kumar 00000000040
TTTTTTTTT 0000000200000000050000000000000000000000
whenever I have non Ascii character in the file like above,
my below code snippet not calculating the sum (d_amt_sum+=substr($0,27,10)) properly sometimes its skiping that row and sometime its giving incorrect value instead of 496 its returning 49 for substr($0,27,10)?
besides I want to know how to add print statement inside AWK, example i need to print the value of "substr($0,27,10)" inside the if block how to do that?
set -A out_result -- `LC_ALL=en_US.UTF-8 awk 'BEGIN{
d_amt_sum=d_rec_count=d_trailer_out_amt_sum=d_trailer_rec_count=0;
}
{
if(substr($0,1,9) != "TTTTTTTTT")
{
d_amt_sum+=substr($0,27,10); d_rec_count+=1
}
else if(substr($0,1,9) == "TTTTTTTTT")
{
d_trailer_out_amt_sum+=substr($0,39,12);
d_trailer_rec_count+=substr($0,31,8);
}
}
END{print d_amt_sum, d_rec_count,d_trailer_out_amt_sum,d_trailer_rec_count}' ${OUTDIR}/${OUT_FILE}
Expected output
500,2,500,2

Answer 1

you have a logic error on the ordering of the if/else statements, another error on checking 1 char length against 9 char length. Fixing both gives...
awk '{k=substr($0,1,9)
if(k=="TTTTTTTTT")
{d_trailer_out_amt_sum+=substr($0,39,12)
d_trailer_rec_count+=substr($0,31,8)}
else if(k!="999999999")
{d_amt_sum+=substr($0,27,10);
d_rec_count+=1}}
END {print d_amt_sum, d_rec_count,d_trailer_out_amt_sum,d_trailer_rec_count}' file
500 2 500 2