Saving image from imagepicker into a different view controller - xcode

Question

I want to push a UIImagePickerViewController with a button in my parent view controller, but I want to display the image in a different view, not the parent view. I've tried
Pushing a new view and calling the image picker from a button there. However, because I have this view embedded inside a navigation view, I have a problem of 2 navigation bars. I can't hide navigation bar because then, I can't go back to the parent view.
Pushing a new view and calling the image picker directly (with no button). However, the image picker is not closing on its own and I can't go back to my parent view controller.

Answer 1

How about something like this:
Have an observed object to be the main object (your enviornmentObject).
Add a UIImage property to it or any property you want to share between views (after all that's the job of an environmentObject
Share the enviornmentObject
This is your class
class AppState: ObservableObject {
#Published var selectedImage: UIImage? = nil // default it to nil in case nothing is selected
}
This is your main view
struct ContentView: View {
#EnviornmentObject var appState: AppState
#State var presentModal: Bool = false
var body: some View {
VStack {
// Image can now easily be accessed by calling self.appState.selectedImage in any view that has #EnviornmentObject var appState: AppState
if(self.appState.selectedImage != nil) {
Image(uiImage: self.appState.selectedImage!)
} else {
// Image doesn't exist, add a placeholder
Text("No image selected")
}
Button("Show Modal") {
self.presentModal.toggle()
}
}.sheet(isPresented: self.$presentModal) {
ModalView(presentModal: self.$presentModal)
}
}
}
// Your ImagePicker view or any other view that will change the selected Image
struct ModalView: View {
#EnviornmentObject var appState: AppState
#Binding var presentModal: Bool = false
var body: some View {
// Your logic to pick image goes here, I will simulate a button click
Button("I will set an image") {
self.appState.selectedImage = UIImage(named: "test.jpg")
self.presentModal.toggle()
}
}
}
In your SceneDelegate (VERY IMPORTANT)
func scene(_ scene: UIScene, willConnectTo session: UISceneSession, options connectionOptions: UIScene.ConnectionOptions) {
// Use this method to optionally configure and attach the UIWindow `window` to the provided UIWindowScene `scene`.
// If using a storyboard, the `window` property will automatically be initialized and attached to the scene.
// This delegate does not imply the connecting scene or session are new (see `application:configurationForConnectingSceneSession` instead).
// Create the SwiftUI view that provides the window contents.
let contentView = ContentView().environmentObject(AppState()) // <- The important part
// Use a UIHostingController as window root view controller.
if let windowScene = scene as? UIWindowScene {
let window = UIWindow(windowScene: windowScene)
window.rootViewController = UIHostingController(rootView: contentView)
self.window = window
window.makeKeyAndVisible()
}
}
Your modal view (or your image picker view, really anything)
EDIT: I agree it should be presented as a modal; however, it is not 100% necessary. Presenting it as a modal or not this should work though.

Answer 2

As the docs for UIUmagePickerController will tell you, it must be presented modally, not pushed. You are also responsible for dismissing it via the delegate.