JPA Hibernate - Set value of a specific column as null - spring

I have column in one of my Entity like below:
#Column(name = "lockedby",nullable = true)
private String lockedby;
And I have this in the Repository:
#Modifying
#Transactional
#Query("UPDATE MyEntity ac set ac.lockedby = ?1 where ac.myentityuuid = ?2")
void unlockMyEntity(String useremailid, String myentityuuid);
And from my Service I am trying to do this:
myEntityRepository.unlockMyEntity(null, myEntityObject.getMyentityuuid());
I am getting NO exceptions and NO messages/warnings WHATSOEVER. And the value remains as is. Doesnt get nullified.
Whats going on here? Am I missing something here?
Update:
Situation seems even worse. Not just null, I cant update this entity with any other String value too. But yeah, my priority/requirement is to set the value as - null as stated in original question.

Related

How to Encrypt A Certain Column automatically with ColumnTransformer?

#ColumnTransformer(forColumn = "description", read = "pgp_sym_decrypt(description, current_setting('encrypt.key'))", write = "pgp_sym_encrypt(?, current_setting('encrypt.key'))")
#Column(name = "description", length=6000)
#Lob
#Type(type = "org.hibernate.type.TextType")
private String description;
I have this column transform where I encrypt the column before saving to the database.
Sometiems it works but most of the time it shows this error. The database not just this, and it works for other columns. Only on this particular column, it wont work. Do you have ideas? Could this be server related issue? As the application works on the test and local machines
column "description" is of type bytea but expression is of type character varying. Hint: You will need to rewrite or cast the expression.
Remove the #Lob annotation, unless the DDL type is oid. Other than that, the mapping looks good to me. Share the stack trace of the error and the failing SQL in case this doesn't help.

Spring data query not working properly, because the field is having Or in the name. Field name is - approvedOrRejectedBy

Spring data query not working properly, because the field is having Or in it.
The field is String approvedOrRejectedBy. So while writing the query it is confusing with the default Or.
The query I wrote is:
List<Object> findAllByTimeStampBetweenAndCameraSlugInAndApprovedOrRejectedBy(long startTime, long endTime, List<String> cameraSlugs, String id);
Because of Or present in the field name, it's throwing an error. Any suggestions or workaround on how to solve this issue, other than updating the filed name and DB mapping.
The query by method-name will interpret certain keywords from the name:
Subject Keywords like here findAllBy
Predicate Keywords like here And, Or, Between together with the property names
Since your field/property seems named as approvedOrRejectedBy you could work around by naming the object property differently and annotate it with the mapped DB-column name as given, e.g. #Column(name "ApprovedOrRejectedBy").
#Column(name "approvedOrRejectedBy")
String reviewedBy;
Then your query-method can be rewritten as
List<Object> findAllByTimeStampBetweenAndCameraSlugInAndReviewedBy(long startTime, long endTime, List<String> cameraSlugs, String id);
Alternatively, since the method name becomes hard to read, you could shorten the name and specify the SELECT on #Query annotation like this:
#Query("SELECT * FROM entityOrTable x WHERE x.timeStamp BETWEEN ?1 AND ?2 AND x.cameraSlug IN ?3 AND x.approvedOrRejectedBy = ?4")
List<Object> findByIntervalCameraSlugInAndReviewedBy(long startTime, long endTime, List<String> cameraSlugs, String id);
See also:
Spring-Data-Jpa Repository - Underscore on Entity Column Name
Spring Data JPA repository methods don't recognize property names with underscores
Try writing custom query using JPQL, like #Query annotation. Please see
https://www.baeldung.com/spring-data-jpa-query

Spring Data / Hibernate save entity with Postgres using Insert on Conflict Update Some fields

I have a domain object in Spring which I am saving using JpaRepository.save method and using Sequence generator from Postgres to generate id automatically.
#SequenceGenerator(initialValue = 1, name = "device_metric_gen", sequenceName = "device_metric_seq")
public class DeviceMetric extends BaseTimeModel {
#Id
#GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "device_metric_gen")
#Column(nullable = false, updatable = false)
private Long id;
///// extra fields
My use-case requires to do an upsert instead of normal save operation (which I am aware will update if the id is present). I want to update an existing row if a combination of three columns (assume a composite unique) is present or else create a new row.
This is something similar to this:
INSERT INTO customers (name, email)
VALUES
(
'Microsoft',
'hotline#microsoft.com'
)
ON CONFLICT (name)
DO
UPDATE
SET email = EXCLUDED.email || ';' || customers.email;
One way of achieving the same in Spring-data that I can think of is:
Write a custom save operation in the service layer that
Does a get for the three-column and if a row is present
Set the same id in current object and do a repository.save
If no row present, do a normal repository.save
Problem with the above approach is that every insert now does a select and then save which makes two database calls whereas the same can be achieved by postgres insert on conflict feature with just one db call.
Any pointers on how to implement this in Spring Data?
One way is to write a native query insert into values (all fields here). The object in question has around 25 fields so I am looking for an another better way to achieve the same.
As #JBNizet mentioned, you answered your own question by suggesting reading for the data and then updating if found and inserting otherwise. Here's how you could do it using spring data and Optional.
Define a findByField1AndField2AndField3 method on your DeviceMetricRepository.
public interface DeviceMetricRepository extends JpaRepository<DeviceMetric, UUID> {
Optional<DeviceMetric> findByField1AndField2AndField3(String field1, String field2, String field3);
}
Use the repository in a service method.
#RequiredArgsConstructor
public class DeviceMetricService {
private final DeviceMetricRepository repo;
DeviceMetric save(String email, String phoneNumber) {
DeviceMetric deviceMetric = repo.findByField1AndField2AndField3("field1", "field", "field3")
.orElse(new DeviceMetric()); // create new object in a way that makes sense for you
deviceMetric.setEmail(email);
deviceMetric.setPhoneNumber(phoneNumber);
return repo.save(deviceMetric);
}
}
A word of advice on observability:
You mentioned that this is a high throughput use case in your system. Regardless of the approach taken, consider instrumenting timers around this save. This way you can measure the initial performance against any tunings you make in an objective way. Look at this an experiment and be prepared to pivot to other solutions as needed. If you are always reading these three columns together, ensure they are indexed. With these things in place, you may find that reading to determine update/insert is acceptable.
I would recommend using a named query to fetch a row based on your candidate keys. If a row is present, update it, otherwise create a new row. Both of these operations can be done using the save method.
#NamedQuery(name="getCustomerByNameAndEmail", query="select a from Customers a where a.name = :name and a.email = :email");
You can also use the #UniqueColumns() annotation on the entity to make sure that these columns always maintain uniqueness when grouped together.
Optional<Customers> customer = customerRepo.getCustomersByNameAndEmail(name, email);
Implement the above method in your repository. All it will do it call the query and pass the name and email as parameters. Make sure to return an Optional.empty() if there is no row present.
Customers c;
if (customer.isPresent()) {
c = customer.get();
c.setEmail("newemail#gmail.com");
c.setPhone("9420420420");
customerRepo.save(c);
} else {
c = new Customer(0, "name", "email", "5451515478");
customerRepo.save(c);
}
Pass the ID as 0 and JPA will insert a new row with the ID generated according to the sequence generator.
Although I never recommend using a number as an ID, if possible use a randomly generated UUID for the primary key, it will qurantee uniqueness and avoid any unexpected behaviour that may come with sequence generators.
With spring JPA it's pretty simple to implement this with clean java code.
Using Spring Data JPA's method T getOne(ID id), you're not querying the DB itself but you are using a reference to the DB object (proxy). Therefore when updating/saving the entity you are performing a one time operation.
To be able to modify the object Spring provides the #Transactional annotation which is a method level annotation that declares that the method starts a transaction and closes it only when the method itself ends its runtime.
You'd have to:
Start a jpa transaction
get the Db reference through getOne
modify the DB reference
save it on the database
close the transaction
Not having much visibility of your actual code I'm gonna abstract it as much as possible:
#Transactional
public void saveOrUpdate(DeviceMetric metric) {
DeviceMetric deviceMetric = metricRepository.getOne(metric.getId());
//modify it
deviceMetric.setName("Hello World!");
metricRepository.save(metric);
}
The tricky part is to not think the getOne as a SELECT from the DB. The database never gets called until the 'save' method.

how to update select column in Spring data?

Please check the below query I am trying to update a row by the composite key
my key combination is like:
int id
int versionId
String languageId
and query is:
#Transactional
#Modifying
#Query("update languageEntity l set l.language = :language where l.languageId = :languageId")
int UpdateProcessLanguage(#Param("language ") String processDesTranslation, #Param("languageId ") UserLanguageId languageId);
I am not getting any exception. function is returning 0, means no row effected.
please check what is worng.
It's hard to say without knowing the data. As a first step I would log the generated SQL statements (see how to log sql statements in spring-boot) and check if they look right.
Why you dont wan't to use save() method for that? Just change language property on your object and pass it to the save method. It will update the row.

Spring JPA with native query and data projection mapping the wrong columns into the projected interface

I've got a bit of a bizarre problem that I can't figure out why it's happening. I'm sure I did something wrong, because this is my first time using a data projection and I've never had such problems using DTOs.
Pretty much I have a SELECT statemen that is returning certain columns of various data types. And I have an interface that I'm passing to the JPA Repository so it can do the interface mapping. But instead of mapping the results based on the column name (eg. 'accountnum' -> getAccountnumber()), it's mapping the columns in alphabetical order. So if 'date_of_order' is the first in the SELECT statement, its value will be returned by getAccountnumber().
I have a projected interface that looks something like this:
public interface FlatSearchResult {
String getAccountnumber();
UUID getTrackingId;
Date getDateOfOrder;
}
My model has three tables something like this:
ACCOUNT
- account_id : uuid (pkey)
- accountnumber : string
ORDERS
- order_id : uuid (pkey)
- date_of_order : timestamp
- account_id : uuid (fkey)
TRACKING
- tracking_id : uuid (pkey)
- order_id : uuid (fkey)
There's other columns in each of those tables, but they're not relevant.
I have a repository defined with a simple query:
public interface OrderTrackingRepository extends JpaRepository<Account, UUID> {
#Query( nativeQuery = true,
value = "SELECT o.date_of_order, a.accountnumber, t.tracking_id " +
"FROM account as a " +
"INNER JOIN orders as o USING (account_id) " +
"INNER JOIN tracking as t USING (tracking_id) " +
"WHERE a.accountnumber = :acctnum")
<T> Collection<T> findOrderInfoForAccount(#Param("acctnum") acctNumber, Class<T> type);
}
When I call this method, the correct rows are returned by the query. But instead of mapping using the column name (eg. date_of_order to getDateOfOrder()), it is mapping based on the order of the columns in the SELECT statement to the alphabetically-ordered methods in the interface.
So:
SELECT date_of_order, accountnumber, tracking_id
Results in:
getAccountNumber() -> date_of_order
getDateOfOrder() -> accountnumber
getTrackingId() -> tracking_id
It will consistently return in this fashion, so it's not a transient issue.
As a temporary workaround, I've reordered the columns in my SELECT statement. But I would rather not have to do this since it's like iterating through a result set and relying on column position, which just makes me twitchy....
How can I get Spring JPA to map from the result set to my interface? Do I need to annotate my projection interface's methods with something to tell Spring what column name it's referring to?
My database is Postgres. I'm using Spring 5.0.2.RELEASE and Spring-Boot 2.0.0.M7. I can adjust either of those to newer versions if needed, but nothing older. I'm using C3P0 0.9.5.2 for my connection pooling, and postgres-9.2-1002.jdbc4. All my other dependencies (hibernate, etc) are what is pulled in by this version of Spring-Boot.
Not sure if this is the correct solution because it only fits 80% of the description. But it is too long for a comment. So here we go.
I think you misunderstood #osamayaccoub or the documentation. Your property name is fine. But the columns in your select should match the java convention.
So the first attempt to fix that would be
value = "SELECT o.date_of_order as dateOfOrder, a.accountnumber as accountNumber, t.tracking_id as trackingId "
Note: This might actually work, but might break later, so read on, even if it does work
But Postgres converts everything that isn't double quoted into lower case (Oracle and MySql do similar stuff though details vary, don't know about other DBs yet). So you really should use:
value = "SELECT o.date_of_order as \"dateOfOrder\", a.accountnumber as \"accountNumber\", t.tracking_id as \"trackingId\" "
This probably doesn't work, because the Hibernate version you are using has a bug in that it converted everything to lower case.
So you should upgrade to the latest Hibernate version 5.3.13 which has the issue fixed.
This bug fix interestingly might break the version without the double quotes.
But it should work again with this PR for this Spring Data JPA issue.
The part I don't understand is, why stuff gets assigned using the column order.
I had the same problem and i solved by odering the query columns alphabetically.
In you case:
public interface OrderTrackingRepository extends JpaRepository<Account, UUID> {
#Query( nativeQuery = true,
value = "SELECT a.accountnumber, o.date_of_order, t.tracking_id " +
"FROM account as a " +
"INNER JOIN orders as o USING (account_id) " +
"INNER JOIN tracking as t USING (tracking_id) " +
"WHERE a.accountnumber = :acctnum")
<T> Collection<T> findOrderInfoForAccount(#Param("acctnum") acctNumber, Class<T> type);
}
So you will get:
getAccountNumber() -> accountnumber
getDateOfOrder() -> date_of_order
getTrackingId() -> tracking_id
Hibernate sorts the query in alphabetic order so you have to change the select to: "SELECT a.accountnumber, o.date_of_order, t.tracking_id ..." and the interface's getters should follow the same alphabetic order.

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