i'm currnetly working on a BO project for a company in the health care field.
Basically, the user is prompted to enter an arrival and departure date, then a table is generated with all the patients that had a stay for at least one day within the arrival/departure date interval.
Then, I want to be able to count how many days the patient stayed during the interval.
For example :
Arrival date : 01/02/2019
Departure date : 10/02/2019
Patient A : from 01/01/2019 to 02/03/2019 will return 10 days (because arrival date =< prompted arrival date and departure date >= prompted departure date so we calculate the days between 01/02/2019 and 10/02/2019)
Patient B : from 05/02/2019 to 15/02/2019 will return 5 days (because arrival date >= prompted arrival date and departure date >= prompted departure date so we calculate the days between 05/02/2020 and 10/02/2019)
Patient C : from 25/01/2019 to 02/02/2019 will return 2 days (because arrival date =< prompted arrival date and 02/02/2020 =< prompted departure date so we calculate the days between 01/02/2019 and 02/02/2019)
Here is my BO table :
I'm pretty sure my explanations are confusing, if you need any clarifications do not hesitate!
I think you should be able to create two variables.
AdjustedArrivalDate=If([PatientArrivalDate]>=[PromptArrivalDate];[PatientArrivalDate];[PromptArrivalDate])
AdjustedDepartureDate=If([PatientDepartureDate]<=[PromptDepartureDate];[PatientDepartureDate];[PromptDepartureDate])
Then find the difference using the DaysBetween function.
StayDurationWithinPromptedRange=DaysBetween([AdjustedArrivalDate]; [AdjustedDepartureDate]) + 1
Related
I need to handle specific scenario in StorProc where I need to do date calculation excluding Sat & Sun. Weekends are holiday I need to handle the data within working days.
I have implemented below code
if (purchase_date = (trunc(sysdate)-2) or purchase_date = (trunc(sysdate)-1)) Then
specific operation
As I have to exclude Sat & Sun by above implementation is giving wrong results obliviously . For example if today is Monday it has to give me back the date of Friday, my implementation is giving me Saturday or Sunday. I need to calculation with dates for weekdays only. Any help would be appreciated.
Thanks
To compare it to the previous week day, you can use:
IF purchase_date = TRUNC(SYSDATE)
- CASE TRUNC(SYSDATE) - TRUNC(SYSDATE, 'IW')
WHEN 0 THEN 3
WHEN 6 THEN 2
ELSE 1
END
THEN
-- Do something
NULL;
END IF;
TRUNC(date_value) - TRUNC(date_value, 'IW') will count the number of days since the start of the ISO week (which is always midnight on Monday).
Note: Do not use TO_CHAR(date_value, 'D') in an international setting as it will give a different result depending on which country you run it in (the week starts on Friday in Bangladesh, Saturday in some Middle-Eastern countries, Sunday in America and Monday in most of Europe).
I have rows of dates with tasks measured in hours. These tasks are assigned to different team leaders whose names are also included on each row. I would like create a multiple criteria Google sheet formula that returns the sum of hours based on the date range and the name of the team leader.
These are the data input cells I would be entering to produce the sum:
Date Start:
Date End:
Team Leader Name:
Ideally if the Team Leader name was not entered, the formula would sum the hours for all of the rows selected by the date range.
Here are some sample rows:
Job Date
Hours
Team Leader
03/25/2022
8
John
04/22/2022
7
Hannah
04/23/2022
6
John
05/01/2022
6
Hannah
Thank you in advance for your help with this!
Assuming you have the following
A:C - Job Date, Hours, Team Leader
D1 - Start Date
D2 - End Date
D3 - Team Leader
=QUERY(
{A1:C},
"select Sum(Col2)
where
Col1 >= date '"&TEXT(IF(ISBLANK(D1),DATE(1970,1,1),D1),"yyyy-mm-dd")&"' and
Col1 <= date '"&TEXT(IF(ISBLANK(D2),DATE(3000,1,1),D2),"yyyy-mm-dd")&"' and
Col3 matches '"&IF(ISBLANK(D3),".*",D3)&"'
label Sum(Col2) ''")
If the start or end dates are blank, it reverts to extreme dates. For Col3 it is using REGEX -- if D3 is blank, it reverts to a wildcard and will return everything summed up.
You can use SUMIFS() function like-
=SUMIFS(B2:B,A2:A,">="&E2,A2:A,"<="&F2,C2:C,IF(G2="","*",G2))
Can someone explain me what does the below oracle query do and what is it's output?
select unique trunc(sysdate-370 + level, 'IW') AS datetime from dual
connect by level <= 360 order by datetime;
select sysdate-370 + level AS datetime
from dual
connect by level <= 360;
Will generate 360 rows starting with the current date/time minus 370 days plus one day per row. So rows between 369 and 10 days before the current date/time.
TRUNC( datetime, 'IW' ) will truncate the date to the start of the ISO week (midnight on Monday of that week - irrespective of the NLS settings for date language and/or territory that affect some other options for truncating dates). So you will end up with duplicate rows for each generated row that is in the same week.
The UNIQUE keyword will get rid of those duplicate rows.
The order by datetime will order the results in ascending date order - however, the rows are generated in ascending order so this clause is unnecessary.
So the output will be 52 or 53 rows (depending on what the current day of the week is) starting with Monday midnight of each week containing the date 369 days before the current day up until the week containing 10 days before the current date.
The output (when run on 13th September 2017) is 52 rows (I skipped a few):
05-SEP-2016
12-SEP-2016
19-SEP-2016
26-SEP-2016
03-OCT-2016
...
31-JUL-2017
07-AUG-2017
14-AUG-2017
21-AUG-2017
28-AUG-2017
According to documentation trunc(dateval, 'IW') truncates to:
Same day of the week as the first day of the calendar week as defined by the ISO 8601 standard, which is Monday
connect by level <= N is a trick for producing a set of N rows with level values from 1 to N.
It's for a school project. I got a table Consultation with the following data :
DoctorId integer,
PatientFile varchar2(20),
visitDate date,
Diagnostic varchar2(20) and
Prescription varchar2(20).
I want to create a query that will show the average number of consultation by month. I try :
SELECT AVG(count(*)) AS count, MONTH(dateVisit) as month
FROM consultation
GROUP BY month
I doesn't work : I can't use the month fonction on dateVisit.
My questions : how would you do a query that will show the average number of consultation by month ?
Many thanks in advance for your help
I found the solution :
select avg (distinct (extract(month from visitDate))) as month from
consultation;
So here's how it's working :
1- extract(month from table_name) as month from table_name. You can
also put year or day instead of month.
2- distinct = will count the total for each month (instead of showing every record).
3- avg = average of each month.
I need to aggregate the values at weekly interval. My date range is dynamic means i can give any start date and end date. Every sunday should be the starting week of every month. say if i have two columns and my start and end date is 07/11/2016 to 13/11/2016
column A column B
07/11/2016 23
08/11/2016 20
09/11/2016 10
10/11/2016 05
11/11/2016 10
12/11/2016 20
13/11/2016 10
My result should come like taking the average of column B
Column A Column B
13/11/2016 14.00
It means i should consider the past value and aggregate it to the day Sunday of that week. Also if my start and end date is like 07/11/2016 to 10/11/2016 then I should not aggregate the value as my week is not complete. I am able to aggregate the values but if my week is not complete i m not able to restrict the aggregation.
Is there any way to do this in PL/SQL??
Thank you in advance.
select to_char(columnA, 'iw') as weeknumber, avg(columnB)
from table
group by to_char(columnA, 'iw');
This will aggregate by number of week. If you need to show last day of week as a label you can get it as max(columnA) over (partition by to_char(columnA, 'iw'))