How can I process date strings in bash? - bash

Question

Does anyone have any idea how I could process input like this with bash? I would like to convert absolute time to relative time. My approach works but is VERY messy. Can anyone do better? Is there a cleaner way to do this?
Input:
| 2020-08-01 15:35:47.446 | message 1 |
| 2020-08-01 15:35:48.446 | hi these |
| 2020-08-01 15:31:47.446 | do stuff now! |
Output: Shows the time difference in milliseconds
0 message 1
1000 hi these
60000 do stuff now!
Working (very dirty) approach:
while read line;
do echo $(echo "$(echo "$line" | cut -d' ' -f3 | cut -d':' -f2 | head -1) * 60000 + $(echo "$line" | cut -d' ' -f3 | cut -d':' -f3 | head -1) * 1000 - $baseval" | bc) $(echo "$line" | cut -d'|' -f3) ;
done < file.log

Answer 1

Looks like the question ask to move a series of abs timestamp to relative timestamp, using 'baseval' as the zero point in time.
It is possible to use date command (using the '+%S' to get seconds past epoch) to simplify calcualtion. If the file has many lines, this solution might not be ideal, as it calls the 'date' process for each line.
Worth noting some of the complexities is with parsing the input format - combination of fixed + delimited column. Code uses bash 'IFS' to split the line into components.
#! /bin/bash
function relative_time_ms {
# Convert inputinto two tokens - relative seconds + nanoseconds
local dd=($(date '+%s %N' -d "$1"))
echo $((dd[0]*1000 + dd[1]/1000000 - baseval))
}
while IFS='|' read x ts msg ; do
rel_time=$(relative_time_ms "$ts")
echo "$rel_time | $msg"
done < file.log
Output:
0 | message 1
1000 | hi these
-240000 | do stuff now!