I am executing one shell script, which contains the following curl command.
FIRST=`curl -k -X POST -H 'Content-Type: application/json' -H 'Accept: application/json' -H 'How-Many: 1' -d '{"filters": { "jobstreamFilter": { "jobStreamName":"'$JOBSTREAM_NAME'","workstationName": "'$WORKSTATION_NAME'"}}}' https://$IWA_HOST:31116/twsd/model/jobstream/header/query -H "Authorization: Basic $CREDS"`
When I execute the shell script from CLI it works fine, but when I call the script from the application, this curl command is not executed. The rest of all the echo statements in the script are printing except FIRST.
Related
I am trying to get the response code of the curl command to a variable and output of the same curl command in a file. Another curl command within a different function will run and the output should append to the same output file.
response=$(curl -i -H "content-type: application/json" -w "%{http_code}" -u "$id:$cred" -H "Accept: application/json" -X POST http://sitename -d '{'<input>'}' >> out.txt
This is giving me neither the response nor the curl output in the file.
Below is working and gives me response as the desired http code though.
response=$(curl -i -H "content-type: application/json" -w "{http_code}" -u "$id:$cred" -H "Accept: application/json" -X POST http://sitename -d '{'<input>'}'
Echo $response
I am using AWX curl for update template in bash script. Somehow this curl command is not able to run
curl --insecure -v -X PATCH https://somedomain.corp.com/api/v2/job_templates/\"$test_2_template\"/ -H 'Authorization: Basic keys==' -H 'Content-Type: application/json' -d '{"extra_vars":"{\"module_name\": \"$module_name\", \"env\": \"$appenv\", \"host_group_name\": \"$host_group_name\", \"rolename\": \"$rolename\", \"app_artifact_url\": \"$app_artifact_url\"}"}'
Looks like there is some issue in passing variables to curl command via bash
However if i run this from my terminal , it's working fine.
curl --insecure -v -X PATCH https://somedomain.com/api/v2/job_templates/279/ -H 'Authorization: Basic keys==' -H 'Content-Type: application/json' -d '{"extra_vars":"{\"module_name\": \"myservice\", \"env\": \"test\", \"host_group_name\": \"env2\", \"rolename\": \"myservice\", \"artifact_version\": \"2.1.0-SNAPSHOT\"}"}'
Please suggest some solution.
You can't substitute variables inside a single quoted string.
For terrible long commands like this, breaking them up into pieces is essential for readability and maintainability:
data=$(printf \
'{"extra_vars": "{\"module_name\": \"%s\", \"env\": \"%s\", \"host_group_name\": \"%s\", \"rolename\": \"%s\", \"app_artifact_url\": \"%s\"}"}' \
"$module_name" "$appenv" "$host_group_name" "$rolename" "$app_artifact_url"
)
curl_args=(
--insecure
-v
-X PATCH
-H 'Authorization: Basic keys=='
-H 'Content-Type: application/json'
-d "$data"
)
url="https://somedomain.example.com/api/v2/job_templates/$test_2_template/"
curl "${curl_args[#]}" "$url"
I am getting authentication failure error while using curl command in bash shell which password has ! char.
Below is curl command i am trying.
curl -D- -u 'some_user:somename#2019!' -X POST --data #data.txt -H 'Content-Type: application/json' https://help.myjira.com/rest/api/2/issue
I have also tried escaping ! char using \, as below, but no luck.
curl -D- -u 'some_user:somename#2019''\!' -X POST --data #data.txt -H 'Content-Type: application/json' https://help.myjira.com/rest/api/2/issue
can any one suggest.
You can try with entity code for ! = %21 (and # = %40). So:
curl -D- -u 'some_user:somename%402019%21' -X POST --data #data.txt -H 'Content-Type: application/json' https://help.myjira.com/rest/api/2/issue
I have a simple bash script that call cURL with several params.
I need to write the output in a file (also overwriting). But I cannot do.
The call itself works, but I have only an empty file (and the answer is a json, I can read on the shell with that echo)
Thank you in advance for your help
1st try
curl -X POST "https://www.example.com"\
-H "X-Auth-Email: $email"\
-H "X-Auth-Key: $auth_key"\
-H "Content-Type: application/json"\
--data '{"name":"'$name'","surname":"'$surname'"}'
>> id.txt
echo
2nd try
curl -X POST "https://www.example.com"\
-H "X-Auth-Email: $email"\
-H "X-Auth-Key: $auth_key"\
-H "Content-Type: application/json"\
--data '{"name":"'$name'","surname":"'$surname'"}'
o id.txt
echo
curl -X POST "https://www.example.com"\
-H "X-Auth-Email: $email"\
-H "X-Auth-Key: $auth_key"\
-H "Content-Type: application/json"\
--data '{"name":"'$name'","surname":"'$surname'"}'\
-o id.txt
I have a bunch of these to test my RESTful API
$CURL \
-v \
-H 'Content-Type: application/json' \
-H 'Accept: application/json' \
-X POST \
-d '{"user":{"email":"user#example.com","password":"secret"}}' \
$URL/$PATH/sessions
I kinda want to shorten it to something like
CURLOPTS="-v -H 'Content-Type: application/json' -H 'Accept: application/json'"
$CURL \
$CURLOPTS \
-X POST \
-d '{"user":{"email":"user#example.com","password":"secret"}}' \
$URL/$PATH/sessions
but the options don't seem to be passed in. Any clues?
Short answer: see BashFAQ #50:'m trying to put a command in a variable, but the complex cases always fail!.
Long answer: Putting commands (or parts of commands) into variables and then getting them back out intact is complicated. The reason your script doesn't work is because of the order in which the shell parses the command line: it parses (and removes) quotes and escapes, then replaces variable values. By the time $CURLOPTS gets replaced, it's too late for the quotes to have their intended effect; instead, they're passed to curl as part of the arguments, which confuses curl greatly.
The solution: store the options in an array rather than a plain string:
CURLOPTS=(-v -H 'Content-Type: application/json' -H 'Accept: application/json')
$CURL \
"${CURLOPTS[#]}" \
-X POST \
-d '{"user":{"email":"user#example.com","password":"secret"}}' \
"$URL/$PATH/sessions"
You can use an array and trigger word splitting
$ set -x
$ CURLOPTS=(-v -H 'Content-Type: application/json' -H 'Accept: application/json')
$ : curl "${CURLOPTS[#]}"
+ : curl -v -H 'Content-Type: application/json' -H 'Accept: application/json'