How to pass multiple parameters in oracle stored procedure - oracle

Question

i am trying to execute like exec print_emp(1010,1111) but it will showing error.
create or replace
procedure print_emp(
P_empno NUMBER
)
IS
begin
for c in ( SELECT *
from emp
where empno in p_empno)
loop
dbms_output.put_line( c.empno||' '||c.ename||' '||c.job||' '||c.sal);
end loop;
END;

Answer 1

You'll need to create a type that is a collection of numbers, and then a procedure that accepts that collection.
Rather than use the IN operator, you should use MEMBER OF to test whether a scalar value is in a collection.
create or replace type tab_number is table of number
/
create or replace procedure print_nums
(p_nums in tab_number)
is
cursor c_main is
select column_value
from table(p_nums)
order by 1;
begin
for r_main in c_main loop
dbms_output.put_line(r_main.column_value);
end loop;
--
if 33 member of p_nums then
dbms_output.put_line('In the list');
end if;
end;
/
exec print_nums(tab_number(10,20,50));
exec print_nums(tab_number(10,20,33));

Answer 2

Obviously, if all parameters you'd like to pass represent the same column value, you can't just list them as if they were two different parameters. If that was the case, procedure should actually name them all, e.g.
create procedure print_emp(par_emp_1 in number, par_emp_2 in number)
but - what if there are 3 or 4 EMPNOs you'd like to pass? You can't modify the procedure every time (not just while declaring it, but also in SELECT statements, as you'd have to add new parameters there as well).
Therefore, one option might be this (as far as I understood the question):
one parameter, whose datatype is varchar2
it means that you'd have to enclose list of EMPNOs into single quotes and separate them with the same separator every time; let it be a comma , sign
cursor's query would contain a subquery (lines #6 - 9) which splits that comma-separated values list of EMPNO values into rows
the rest is simple
Here you go:
SQL> create or replace procedure print_emp(par_empno in varchar2)
2 is
3 begin
4 for c in (select *
5 from emp
6 where empno in (select to_number(regexp_substr(par_empno, '[^,]+', 1, level))
7 from dual
8 connect by level <= regexp_count(par_empno, ',') + 1
9 )
10 )
11 loop
12 dbms_output.put_line(c.empno||' '||c.ename||' '||c.job||' '||c.sal);
13 end loop;
14 end;
15 /
Procedure created.
Scott's EMP sample table:
SQL> select * from emp where deptno = 20;
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
---------- ---------- --------- ---------- ------------------- ---------- ---------- ----------
7369 SMITH CLERK 7902 17.12.1980 00:00:00 1000 20
7566 JONES MANAGER 7839 02.04.1981 00:00:00 2975 20
7788 SCOTT ANALYST 7566 09.12.1982 00:00:00 3000 20
7876 ADAMS CLERK 7788 12.01.1983 00:00:00 1100 20
7902 FORD ANALYST 7566 03.12.1981 00:00:00 3000 20
Testing:
SQL> set serveroutput on
SQL> exec print_emp('7369,7566,7788');
7566 JONES MANAGER 2975
7788 SCOTT ANALYST 3000
7369 SMITH CLERK 1000
PL/SQL procedure successfully completed.
SQL>