My spring boot app starts correctly, but tests fails. I've just added to my pom.xml
<dependency>
<groupId>org.flywaydb</groupId>
<artifactId>flyway-core</artifactId>
<version>6.5.2</version>
</dependency>
My spring boot version: 2.3.1.RELEASE
I spent 5 hours on looking for information but I can't resolve it.
I get this error: Constraint "ANIMAL_PROFILE_PK" already exists;
Migration:
(
id varchar not null
constraint user_auth_data_pk
primary key,
email varchar not null unique,
pass varchar,
token varchar,
confirm boolean not null
);
create table animal_profile
(
id varchar not null
constraint animal_profile_pk
primary key
references user_auth_data(id),
name varchar not null,
type varchar not null,
photo_url varchar unique not null,
active boolean not null
);
Related
I am switching from MYSQL to ORACLE.
I have JPA Authentication setup like this:
#Override
#Transactional(readOnly = true)
public UserDetails loadUserByUsername(String email) throws UsernameNotFoundException {
AppUser user = userRepository.findByUseremailIgnoreCase(email);
With MySQL all works fine. But for Oracle, during login using JPA authentication I am getting this exception.
org.springframework.security.authentication.InternalAuthenticationServiceException: Unable to extract JDBC value for position `3`
Followed by these exceptions:
Caused by: org.springframework.orm.jpa.JpaSystemException: Unable to extract JDBC value for position `3`
Caused by: java.sql.SQLException: Invalid conversion requested
Caused by: java.lang.IllegalArgumentException: Timestamp format must be yyyy-mm-dd hh:mm:ss[.fffffffff]
Any clue what I am missing and where to debug?
My table structure is as per below:
create table CONTENTPLUSPLUS.app_user (
id NUMBER GENERATED ALWAYS as IDENTITY(START with 1 INCREMENT by 1) NOT NULL,
useremail VARCHAR(150) NOT NULL,
userpassword VARCHAR(150) NOT NULL,
useruuid VARCHAR(50) NOT NULL,
userfirstname VARCHAR(150) NOT NULL,
userlastname VARCHAR(150) NOT NULL,
userenabled NUMBER(1) DEFAULT 0 NOT NULL,
created_by VARCHAR(150) NOT NULL,
created_date VARCHAR(150) NOT NULL,
modified_by VARCHAR(150) NOT NULL,
modified_date VARCHAR(150) NOT NULL,
CONSTRAINT appuser_pk PRIMARY KEY (id), UNIQUE (useremail, useruuid));
create table CONTENTPLUSPLUS.app_role(
id NUMBER GENERATED ALWAYS as IDENTITY(START with 1 INCREMENT by 1) NOT NULL,
name VARCHAR(150) NOT NULL,
CONSTRAINT approle_pk PRIMARY KEY (id),UNIQUE (name));
CREATE TABLE CONTENTPLUSPLUS.app_department (
id NUMBER GENERATED ALWAYS as IDENTITY(START with 1 INCREMENT by 1) NOT NULL,
departmentuuid VARCHAR(150),
departmentheadname varchar(255) NOT NULL,
departmentheademail varchar(255) NOT NULL,
departmentname varchar(255) NOT NULL,
userid NUMBER NOT NULL,
created_by VARCHAR(150) NOT NULL,
created_date VARCHAR(150) NOT NULL,
modified_by VARCHAR(150) NOT NULL,
modified_date VARCHAR(150) NOT NULL,
CONSTRAINT appdepartment_pk PRIMARY KEY (id),UNIQUE (departmentname, departmentuuid));
CREATE TABLE CONTENTPLUSPLUS.app_user_department (
userid NUMBER NOT NULL,
departmentid NUMBER NOT NULL
);
ALTER TABLE CONTENTPLUSPLUS.app_user_department ADD CONSTRAINT FK_AUSERDEPTUSERID FOREIGN KEY (userid) REFERENCES app_user (id);
ALTER TABLE CONTENTPLUSPLUS.app_user_department ADD CONSTRAINT FK_AUSERDEPTDEPTID FOREIGN KEY (departmentid) REFERENCES app_department (id);
ALTER TABLE CONTENTPLUSPLUS.app_department ADD CONSTRAINT FK_AUSERUSERID FOREIGN KEY (userid) REFERENCES app_user (id);
CREATE TABLE CONTENTPLUSPLUS.app_user_role (
id NUMBER GENERATED ALWAYS as IDENTITY(START with 1 INCREMENT by 1) NOT NULL,
userid NUMBER NOT NULL,
roleid NUMBER NOT NULL,
CONSTRAINT appuserrole_pk PRIMARY KEY (id));
ALTER TABLE CONTENTPLUSPLUS.app_user_role ADD CONSTRAINT FK_AURUSERID FOREIGN KEY (userid) REFERENCES app_user (id);
ALTER TABLE CONTENTPLUSPLUS.app_user_role ADD CONSTRAINT FK_AURROLEID FOREIGN KEY (roleid) REFERENCES app_role (id);
Below is the query which gets fired during the login operation (shows up only for MySQL):
Hibernate:
select
a1_0.id,
a1_0.created_by,
a1_0.created_date,
a1_0.modified_by,
a1_0.modified_date,
a1_0.useremail,
a1_0.userenabled,
a1_0.userfirstname,
a1_0.userlastname,
a1_0.userpassword,
a1_0.useruuid
from
app_user a1_0
where
upper(a1_0.useremail)=upper(?)
Hibernate:
select
r1_0.userid,
r1_1.id,
r1_1.name
from
app_user_role r1_0
join
app_role r1_1
on r1_1.id=r1_0.roleid
where
r1_0.userid=?
You map Date in Java with VARCHAR2 in SQL: bad idea. You probably get lucky with the default conversion format of TS and the locale in MySQL: back to my first comment... look at the SQL Office Hours session code...
Currently, I'm using:
Spring boot 2.2.2
Spring jdbc 2.5.0
Spring core 2.5.0
Sometimes, I got errors when accessing my endpoints, here is the stack trace, this happen after upgrading my library from:
spring boot 2.1.7
spring jdbc 2.1.8
spring core 2.1.8
Handle DataIntegrityViolationException: PreparedStatementCallback;
SQL [INSERT INTO SPRING_SESSION_ATTRIBUTES(SESSION_PRIMARY_ID, ATTRIBUTE_NAME, ATTRIBUTE_BYTES) SELECT PRIMARY_ID, ?, ? FROM SPRING_SESSION WHERE SESSION_ID = ?];
ERROR: duplicate key value violates unique constraint \"spring_session_attributes_pk\"
Detail: Key (session_primary_id, attribute_name)=(a9427ef5-92a4-4845-8769-e034c3b50b70, SPRING_SECURITY_CONTEXT) already exists.; nested exception is org.postgresql.util.PSQLException:
ERROR: duplicate key value violates unique constraint \"spring_session_attributes_pk\"
Detail: Key (session_primary_id, attribute_name)=(a9427ef5-92a4-4845-8769-e034c3b50b70, SPRING_SECURITY_CONTEXT) already exists.
org.springframework.dao.DuplicateKeyException: PreparedStatementCallback; SQL [INSERT INTO SPRING_SESSION_ATTRIBUTES(SESSION_PRIMARY_ID, ATTRIBUTE_NAME, ATTRIBUTE_BYTES) SELECT PRIMARY_ID, ?, ? FROM SPRING_SESSION WHERE SESSION_ID = ?];
ERROR: duplicate key value violates unique constraint \"spring_session_attributes_pk\"
Detail: Key (session_primary_id, attribute_name)=(a9427ef5-92a4-4845-8769-e034c3b50b70, SPRING_SECURITY_CONTEXT) already exists.; nested exception is org.postgresql.util.PSQLException:
ERROR: duplicate key value violates unique constraint \"spring_session_attributes_pk\"
Detail: Key (session_primary_id, attribute_name)=(a9427ef5-92a4-4845-8769-e034c3b50b70, SPRING_SECURITY_CONTEXT) already exists.
at org.springframework.jdbc.support.SQLErrorCodeSQLExceptionTranslator.doTranslate(SQLErrorCodeSQLExceptionTranslator.java:243)
Here is my session tables:
CREATE TABLE APP_SPRING_SESSION (
PRIMARY_ID CHAR(36) NOT NULL,
SESSION_ID CHAR(36) NOT NULL,
CREATION_TIME BIGINT NOT NULL,
LAST_ACCESS_TIME BIGINT NOT NULL,
MAX_INACTIVE_INTERVAL INT NOT NULL,
EXPIRY_TIME BIGINT NOT NULL,
PRINCIPAL_NAME VARCHAR(100),
CONSTRAINT APP_SPRING_SESSION_PK PRIMARY KEY (PRIMARY_ID)
);
CREATE UNIQUE INDEX APP_SPRING_SESSION_IX1 ON APP_SPRING_SESSION (SESSION_ID);
CREATE INDEX APP_SPRING_SESSION_IX2 ON APP_SPRING_SESSION (EXPIRY_TIME);
CREATE INDEX APP_SPRING_SESSION_IX3 ON APP_SPRING_SESSION (PRINCIPAL_NAME);
CREATE TABLE APP_SPRING_SESSION_ATTRIBUTES (
SESSION_PRIMARY_ID CHAR(36) NOT NULL,
ATTRIBUTE_NAME VARCHAR(200) NOT NULL,
ATTRIBUTE_BYTES BYTEA NOT NULL,
CONSTRAINT APP_SPRING_SESSION_ATTRIBUTES_PK PRIMARY KEY (SESSION_PRIMARY_ID, ATTRIBUTE_NAME),
CONSTRAINT APP_SPRING_SESSION_ATTRIBUTES_FK FOREIGN KEY (SESSION_PRIMARY_ID) REFERENCES APP_SPRING_SESSION(PRIMARY_ID) ON DELETE CASCADE
);
Does anyone know how to fix the problem?
These errors mean that there are already records with such keys in your database.
You can clear the database or change the keys and the Insert queries.
My environment is HSQLDB, Maven and spring-boot.
I have created 2 entity POJOs. I do see the CREATE TABLE command under testedb.log file. But when I open Data Source Explorer in Eclipse, I can`t see my tables, albeit I do see all the system tables.
I have looked at this question too, but no vail: Where can I see the HSQL database and tables
Here is my partial pom.xml:
<dependency>
<groupId>org.hsqldb</groupId>
<artifactId>hsqldb</artifactId>
<version>2.4.0</version>
<scope>runtime</scope>
</dependency>
Here is my partial application.properties:
# DataSource
#spring.datasource.driverClassName=org.hsqldb.jdbc.JDBCDriver
spring.datasource.url=jdbc:hsqldb:file:resources/db/testedb;DATABASE_TO_UPPER=false
#spring.datasource.url=jdbc:hsqldb:mem:memTestdb
spring.datasource.username=sa
spring.datasource.password=
# Hibernate
spring.jpa.show-sql=true
#spring.jpa.hibernate.ddl-auto=create-drop
spring.jpa.hibernate.ddl-auto=create
And below is my HSQLDB created on disk:
HSQLDB folder in my workspace
Here is my partial testedb.script:
SET FILES LOG SIZE 50
CREATE USER SA PASSWORD DIGEST 'd41d8cd98f00b204e9800998ecf8427e'
ALTER USER SA SET LOCAL TRUE
CREATE SCHEMA PUBLIC AUTHORIZATION DBA
SET SCHEMA PUBLIC
CREATE SEQUENCE PUBLIC.HIBERNATE_SEQUENCE AS INTEGER START WITH 1
CREATE MEMORY TABLE PUBLIC.ENQUIRY_HISTORY(ID BIGINT NOT NULL PRIMARY KEY,FROM_AMOUNT DOUBLE NOT NULL,FROM_CURRENCY VARCHAR(255) NOT NULL,QUERY_DATE TIMESTAMP NOT NULL,TO_AMOUNT DOUBLE NOT NULL,TO_CURRENCY VARCHAR(255) NOT NULL,USER_ID BIGINT NOT NULL,VERSION INTEGER NOT NULL)
CREATE MEMORY TABLE PUBLIC.USERS(ID BIGINT NOT NULL PRIMARY KEY,EMAIL VARCHAR(255) NOT NULL,LAST_LOGIN TIMESTAMP NOT NULL,PASSWORD VARCHAR(255) NOT NULL,VERSION VARCHAR(255) NOT NULL)
ALTER SEQUENCE SYSTEM_LOBS.LOB_ID RESTART WITH 1
ALTER SEQUENCE PUBLIC.HIBERNATE_SEQUENCE RESTART WITH 1
SET DATABASE DEFAULT INITIAL SCHEMA PUBLIC
GRANT USAGE ON DOMAIN INFORMATION_SCHEMA.SQL_IDENTIFIER TO PUBLIC
Please see above that the CREATE TABLE contains the word MEMORY even though I have created file DB.
And by testsdb.log:
/*C12*/SET SCHEMA PUBLIC
drop table enquiry_history if exists
drop table users if exists
drop sequence hibernate_sequence if exists
create sequence hibernate_sequence start with 1 increment by 1
create table enquiry_history (id bigint not null, from_amount float not null, from_currency varchar(255) not null, query_date timestamp not null, to_amount float not null, to_currency varchar(255) not null, user_id bigint not null, version integer not null, primary key (id))
create table users (id bigint not null, email varchar(255) not null, last_login timestamp not null, password varchar(255) not null, version varchar(255) not null, primary key (id))
/*C14*/SET SCHEMA PUBLIC
DISCONNECT
/*C17*/SET SCHEMA PUBLIC
And Finally here is my screen shot of Database
Data Source Explorer
Any pointer will be awesome, thanks for your time.
file and mem are in-process modes. For testing/debugging, if you need concurrent access to data from another process, start database in Server mode.
Check various available modes here.
I was able to see the tables using in build HSQLDB interface, now a fancy one but it still works for me.
I used the following [listed in this answer https://stackoverflow.com/a/35240141/8610216]
java -cp /path/to/hsqldb.jar org.hsqldb.util.DatabaseManager
And then specify path your database:
jdbc:hsqldb:file:mydb
There was one more thing that I was doing incorrect; it was the path of the db. The correct path is spring.datasource.url=jdbc:hsqldb:file:src/main/resources/db/userx;DATABASE_TO_UPPER=falsein application.properties.
I am new to h2.I just using h2 in spring embedded mode with hibernate.I am trying to execute the following scripts using h2.
CREATE TABLE acct_authority (
id bigint(20) NOT NULL auto_increment,
name varchar(255) NOT NULL default '',
value varchar(255) NOT NULL,
PRIMARY KEY (id),
UNIQUE KEY name (name)
);
The table acct_authority is created without any error.But if i create another table with the following script.
CREATE TABLE acct_role (
id bigint(20) NOT NULL auto_increment,
name varchar(255) NOT NULL default '',
PRIMARY KEY (id),
UNIQUE KEY name (name)
);
It shows error as constraint name allready exists.What mistake i did.
You tried to create two constraints with same name. As you see, both CREATE TABLE statements contain following:
UNIQUE KEY name (name)
Result is that first one creates constraint named name, and second one fails because constraint name already exists. Problem can be solved by using unique names. Also in general it makes sense have little bit more descriptive names for database objects. Maybe you can use for example something like following:
UNIQUE KEY acct_authority_name_UNIQUE (name)
...
UNIQUE KEY acct_role_name_UNIQUE (name)
What can I do if I need to create entity for
a table in production DB (Oracle 10g) with composite primary key.
For example:
[CODE]
CREATE TABLE TACCOUNT
(
BRANCHID NUMBER(3) NOT NULL,
ACC VARCHAR2(18 BYTE) NOT NULL,
DATE_OPEN DATE NOT NULL,
DATE_CLOSE DATE,
NOTE VARCHAR2(38 BYTE)
);
CREATE UNIQUE INDEX PK_TACCOUNT ON TACCOUNT
(BRANCHID, ACC);
I don't want to change the structure of this table.
Is it possible to create an "id" field using roo commands?
I use Spring Roo 1.0.2.RELEASE [rev 638]