I have a column that l need to order in a Matrix but my problem is that the column has a mixture of numbers and characters as it's a range field and the range differs on each grouping parent.
an example of the grouping looks like
Create Table #temp
(
range Varchar(30)
)
Insert into #temp (range)
select '[0-501]' Union
select '[13001-17001]' Union
select '[17001-999999]' Union
select '[8501-13001]' Union
select '[501-8501]'
SELECT *
FROM #temp order by range
drop table #temp
[17001-999999]
[0-501]
[13001-17001]
[8501-13001]
[501-8501]
Preferred result after ordering is as below
[0-501]
[501-8501]
[8501-13001]
[13001-17001]
[17001-999999]
It would be better to design your table so that is has some kind of "Sort Order" column.
But you could use this:
SELECT *,TRY_CAST(SUBSTRING(range,2,CHARINDEX('-',range)-2) AS INT) as SortOrder
FROM #temp
Then use this column to order your matrix.
Try this below query it will give desired output
SELECT *
FROM #temp
order by cast(replace(replace(replace(range,'-',''),'[',''),']','') as bigint)
Related
How can I achieve this to Select to one row only dynamically since
the objective is to get the uniqueness even on multiple columns
select distinct
coalesce(least(ColA, ColB),cola,colb) A1, greatest(ColA, ColB) B1
from T
The best solution is to use UNION
select colA from your_table
union
select colB from your_table;
Update:
If you want to find the duplicate then use the EXISTS as follows:
SELECT COLA, COLB FROM YOUR_TABLE T1
WHERE EXISTS (SELECT 1 FROM YOUR_tABLE T2
WHERE T2.COLA = T1.COLB OR T2.COLB = T1.COLA)
If I correctly understand words: objective is to get the uniqueness even on multiple columns, number of columns may vary, table can contain 2, 3 or more columns.
In this case you have several options, for example you can unpivot values, sort, pivot and take unique values. The exact code depends on Oracle version.
Second option is listagg(), but it has limited length and you should use separators not appearing in values.
Another option is to compare data as collections. Here I used dbms_debug_vc2coll which is simple table of varchars. Multiset except does main job:
with t as (select rownum rn, col1, col2, col3,
sys.dbms_debug_vc2coll(col1, col2, col3) as coll
from test )
select col1, col2, col3 from t a
where not exists (
select 1 from t b where b.rn < a.rn and a.coll multiset except b.coll is empty )
dbfiddle with 3-column table, nulls and different test cases
I have multiple columns in a table in hive having around 80 columns. I need to apply the distinct clause on some of the columns and get the first values from the other columns also. Below is the representation of what I am trying to achieve.
select distinct(col1,col2,col3),col5,col6,col7
from abc where col1 = 'something';
All the columns mentioned above are text columns. So I cannot apply group by and aggregate functions.
You can use row_number function to solve the problem.
create table temp as
select *, row_number() over (partition by col1,col2,col3) as rn
from abc
where col1 = 'something';
select *
from temp
where rn=1
You can also sort the table while partitioning.
row_number() over (partition by col1,col2,col3 order by col4 asc) as rn
DISTINCT is the most overused and least understood function in SQL. It's the last thing that is executed over your entire result set and removes duplicates using ALL columns in your select. You can do a GROUP BY with a string, in fact that is the answer here:
SELECT col1,col2,col3,COLLECT_SET(col4),COLLECT_SET(col5),COLLECT_SET(col6)
FROM abc WHERE col1 = 'something'
GROUP BY col1,col2,col3;
Now that I re-read your question though, I'm not really sure what you are after. You might have to join the table to an aggregate of itself.
Hello I need a formula in column ‘C’ which calculates/adds the amount of B Column based on the column A ID. If there are several amounts in same ID it should add the total amount and would show the result in column ‘C’ as a single row.
the output can be obtained from Oracle SQL query or an Excel formula.your help would be appreciated.
You can get the same output from Oracle itself, using analytical functions like below.
SUM() OVER(PARTITION BY ... ) -> This actually do the cumulative sum
WITH MYTABLE(ID,AMT) AS
(SELECT '2UF2', '500' FROM DUAL
UNION ALL
SELECT '2TC6', '300' FROM DUAL
UNION ALL
SELECT '2TC6', '200' FROM DUAL
UNION ALL
SELECT '2TC6', '800' FROM DUAL
)
SELECT ID,
AMT,
CASE ROW_NUMBER() OVER(PARTITION BY ID ORDER BY NULL)
WHEN 1
THEN SUM(AMT) OVER(PARTITION BY ID ORDER BY NULL)
END AS FORMULA
FROM MYTABLE
ORDER BY ID, FORMULA NULLS LAST;
SQL Fiddle Demo
You can use rollup in oracle
Select id,amt,sum (amt) nullFrom table nullGroup by rollup (id,amt)
For more details see below link
https://oracle-base.com/articles/misc/rollup-cube-grouping-functions-and-grouping-sets
In SQL you need an aggregation function, in this case sum, and a group by clause. The generic query should look like the following:
Select sum(b) from table group by a
I hope this helps.
Is there is a way to order by the order of the values in an IN() clause?
I have a select query:
Select * from abc where xyz in (a list of values).
I want the result to be sorted in the same order as the list inside the bracket.
One way is that I can put the values in a temp table with an increasing sequence and then join the 2 tables, and then order by the sequence, but this is not a good way.
Is there a way to do this?
No need for a temp table (but not really pretty either)
with list_values (seqnr, id) as (
select 1, 42 from dual
union all
select 2, 43 from dual
union all
select 3, 44 from dual
-- you get the picture
)
select *
from abc
join list_values lv on abc.xyz = lv.id
order by lv.seqnr
One ugly option is to use DECODE:
Select * from abc
WHERE xyz in (a list of values)
ORDER BY DECODE(xyz, 'val1', 1, 'val2', 2, ...)
Thanks for all the answers.
There is another approach, similar to a_horse_with_no_name's approach:
with t as
(select t.*, rownum r from table (sys.odcinumberlist(val1, val2, val3...)) t)
select * from abc ac, t where ac.id = column_value and is_active = 'Y' order by r
This should work too. Which one do you guys think is the best and optimal way to do this?
I have a complex query with group by and order by clause and I need a sorted row number (1...2...(n-1)...n) returned with every row. Using a ROWNUM (value is assigned to a row after it passes the predicate phase of the query but before the query does any sorting or aggregation) gives me a non-sorted list (4...567...123...45...). I cannot use application for counting and assigning numbers to each row.
Is there a reason that you can't just do
SELECT rownum, a.*
FROM (<<your complex query including GROUP BY and ORDER BY>>) a
You could do it as a subquery, so have:
select q.*, rownum from (select... group by etc..) q
That would probably work... don't know if there is anything better than that.
Can you use an in-line query? ie
SELECT cols, ROWNUM
FROM (your query)
Assuming that you're query is already ordered in the manner you desire and you just want a number to indicate what row in the order it is:
SELECT ROWNUM AS RowOrderNumber, Col1, Col2,Col3...
FROM (
[Your Original Query Here]
)
and replace "Colx" with the names of the columns in your query.
I also sometimes do something like:
SELECT * FROM
(SELECT X,Y FROM MY_TABLE WHERE Z=16 ORDER BY MY_DATE DESC)
WHERE ROWNUM=1
If you want to use ROWNUM to do anything more than limit the total number of rows returned in a query (e.g. AND ROWNUM < 10) you'll need to alias ROWNUM:
select *
(select rownum rn, a.* from
(<sorted query>) a))
where rn between 500 and 1000