when i use
echo -n "$str" |sha224sum
it gets me the checksum ends with "-"
how to get the checksum without it ?
Thanks
Cut the first field:
$ echo -n "$str" | sha224sum | cut -d' ' -f1
23097d223405d8228642a477bda255b32aadbce4bda0b3f7e36c9da7
Related
Right Now I am trying to parse the values from my get time and date and break it down by each number
Format of the date/time
#!/bin/bash
prevDateTime=$(date +'%Y-%m-%d-%H:%M:%S')
echo "${prevDateTime}"
I want to be able to list it out like so
echo "${prevYear}"
echo "${prevMonth}"
echo "${prevDay}"
echo "${prevHour}"
echo "${prevMinute}"
echo "${prevSecond}"
and then like
echo "${prevDate}"
echo "${precTime}"
But I am not sure how to parse out the information any help would be great
A regular expression is probably the simplest solution, given the format of prevDateTime.
[[ $prevDateTime =~ (.*)-(.*)-(.*)-(.*):(.*):(.*) ]]
prevYear=${BASH_REMATCH[1]}
prevMonth=${BASH_REMATCH[2]}
# etc.
Technically, there's a "one"-liner to do this using declare:
declare $(date +'prevDateTime=%Y-%m-%d:%H:%M:%S
prevYear=%Y
prevMonth=%m
prevDat=%d
prevHour=%H
prevMinute=%M
prevSecond=%S')
It uses date to output a block of parameter assignments which declare instantiates. (Note that the command substitution is not quoted, so that each assignment is seen as a separate argument to declare. If there was any whitespace in the values to assign, you would have to switch to using eval with slightly different output from date.)
You can use read command with IFS to break down date components:
prevDateTime=$(date +'%Y-%m-%d-%H:%M:%S')
IFS='-:' read -ra arr <<< "$prevDateTime"
# print array values
declare -p arr
# This outputs
# declare -a arr='([0]="2015" [1]="05" [2]="21" [3]="10" [4]="24" [5]="28")'
#assign to other variables
prevYear=${arr[0]}
prevMonth=${arr[1]}
prevDay=${arr[2]}
prevHour=${arr[3]}
prevMinute=${arr[4]}
prevSecond=${arr[5]}
Fast solution using cut:
#!/bin/bash
prevDateTime=$(date +'%Y-%m-%d-%H:%M:%S')
echo "${prevDateTime}"
prevYear=`echo $prevDateTime | cut -d- -f1`
prevMonth=`echo $prevDateTime | cut -d- -f2`
prevDay=`echo $prevDateTime | cut -d- -f3`
prevHour=`echo $prevDateTime | cut -d- -f4 | cut -d: -f1`
prevMinute=`echo $prevDateTime | cut -d- -f4 | cut -d: -f2`
prevSecond=`echo $prevDateTime | cut -d- -f4 | cut -d: -f3`
echo "Year: $prevYear; Month: $prevMonth; Day: $prevDay"
echo "Hour: $prevHour; Minute: $prevMinute; Second: $prevSecond"
I have the following comand:
grep RJAVA | grep -v grep | wc -l ' | sort | cut -d':' -f2 | cut -d' ' -f2
After executing this, I get the following result :
10
0
0
10
I would like to put all these numbers into a bash array so that I can loop through
the array. I tried using xargs but couldn't make it work. Any suggestion ?
this should work:
array=($( YOUR_ENTIRE_PIPED_COMMAND ))
BTW, the command above seems broken - you are missing the input to the first grep (either filnames, or pipe into it)
you could try tr:
IN="10 0 0 10"
arr=$(echo $IN | tr " " "\n")
for x in $arr
do
echo "> [$x]"
done
Regards, Edi
My bash script contains the following line:
echo $(echo "$STRING_VAR" | cut -d' ' -f 2) >> $FILE
Here we have two echo calls, but are they really necessary ?
I wrote them, because otherwise the bash would think the string in first place is a command.
Simply echo "$STRING_VAR" | cut -d' ' -f 2 >> $FILE does the same thing.
echo "$STRING_VAR" | cut -d' ' -f 2 >> $FILE
should be all you need
Also, bash has the handy "here-string" redirection mode: you don't need echo at all:
cut -d' ' -f2 <<< "$STRING_VAR" >> "$FILE"
I have the following:
FILENAME=$1
cat $FILENAME | while read LINE
do
response="$LINE" | cut -c1-14
request="$LINE" | cut -c15-31
difference=($response - $request)/1000
echo "$difference"
done
When I run this script it returns blank lines. What am I doing wrong?
Might be simpler in awk:
awk '{print ($1 - $2)/1000}' "$1"
I'm assuming that the first 14 chars and the next 17 chars are the first two blank-separated fields.
You need to change it to:
response=`echo $LINE | cut -c1-14`
request=`echo $LINE | cut -c15-31`
difference=`expr $response - $request`
val=`expr $difference/1000`
You are basically doing everything wrong ;)
This should be better:
FILENAME="$1"
cat "$FILENAME" | while read LINE
do
response=$(echo "$LINE" | cut -c1-14) # or cut -c1-14 <<< "$line"
request=$(echo "$LINE" | cut -c15-31)
difference=$((($response - $request)/1000)
echo "$difference"
done
I'm trying to write a little script which will open a text file and give me an md5 hash for each line of text. For example I have a file with:
123
213
312
I want output to be:
ba1f2511fc30423bdbb183fe33f3dd0f
6f36dfd82a1b64f668d9957ad81199ff
390d29f732f024a4ebd58645781dfa5a
I'm trying to do this part in bash which will read each line:
#!/bin/bash
#read.file.line.by.line.sh
while read line
do
echo $line
done
later on I do:
$ more 123.txt | ./read.line.by.line.sh | md5sum | cut -d ' ' -f 1
but I'm missing something here, does not work :(
Maybe there is an easier way...
Almost there, try this:
while read -r line; do printf %s "$line" | md5sum | cut -f1 -d' '; done < 123.txt
Unless you also want to hash the newline character in every line you should use printf or echo -n instead of echo option.
In a script:
#! /bin/bash
cat "$#" | while read -r line; do
printf %s "$line" | md5sum | cut -f1 -d' '
done
The script can be called with multiple files as parameters.
You can just call md5sum directly in the script:
#!/bin/bash
#read.file.line.by.line.sh
while read line
do
echo $line | md5sum | awk '{print $1}'
done
That way the script spits out directly what you want: the md5 hash of each line.
this worked for me..
cat $file | while read line; do printf %s "$line" | tr -d '\r\n' | md5 >> hashes.csv; done