When I click the "submit" button, the form is not submitted. Why?
I got it straight from Google's sample code, all I added was one line:
document.getElementById("myform").submit();
The "thanks" message was shown.
If I click the "submit without validate" button, the form is submitted.
<html>
<head>
<script>
function onSubmit(token) {
alert('thanks ' + document.getElementById('name').value);
document.getElementById("myform").submit();
}
function validate(event) {
event.preventDefault();
if (!document.getElementById('name').value) {
alert("You must add text to the required field");
} else {
grecaptcha.execute();
}
}
function onload() {
var element = document.getElementById('submit');
element.onclick = validate;
}
</script>
<script src="https://www.google.com/recaptcha/api.js" async defer></script>
</head>
<body>
<form action="/Second/Save" method="post" id="myform">
Name: (required) <input id="name" name="name">
<div id='recaptcha' class="g-recaptcha"
data-sitekey="6LexWMMZAAAAAGpLECkk-pfZ-sYuQ9qDu7wiMJ3M"
data-callback="onSubmit"
data-size="invisible"></div>
<button id='submit'>submit</button>
<button onclick="onSubmit();">Submit Without Validate</button>
</form>
<script>onload();</script>
</body>
</html>
The issue is that you have a button in the form with the id "submit". Any element in the form with a name or an id is reflected in a form attribute with that name. So if you have the form object will have an "elephants" attribute. In this case the submit button is accessible via form.submit, but this masks the submit() function.
If a form control (such as a submit button) has a name or id of submit, this method will mask the form's submit method.
MDN Web docs
Please check your site key, this error is mainly formed when your domain does not match your site key.
You can create your own google captcha key of your domain with your google account it's free of cost from the link given below
https://www.google.com/recaptcha/admin/create
Related
Please find below my code:
Template of customer search form
<script type="text/x-kendoui-template" id="customer-search-view-template">
<div class="searchform" id="searchCustomer">
<form class="frmSearch">
<input name="searchTxt" data-bind="value: customerName" class="k-textbox" />
<button class="k-button" data-bind="click: searchClicked">Search</button>
<button class="k-button" data-bind="click: newClicked">New</button>
</form>
</div>
</script>
customer-search.js where loading above template and creating viewmodel object
$(function(){
var views = {};
templateLoader.loadExtTemplate("customer-search-view-template", "../views/customer-search-template.html");
var layout = new kendo.Layout($('#customer-search-view-template').html());
layout.render($("#main"));
// Create an observable view model object.
var customer = kendo.observable({
customerName: "John",
searchClicked: function() {
this.set("customerName", "Search clicked");
},
newClicked: function() {
this.set("customerName", "New clicked");
}
});
// Bind the view model to the personFields element.
kendo.bind($('#searchCustomer'), customer);
});
When I click the search button, the text is set in the textbox but this also refresh the page with ?searchTxt=Search+clicked in the address bar.
May I know why this button click refresh the page and how do I stop refreshing the page on button click ???
I would try and place the attribute 'type' for each like so:
<button type="button" class="k-button" data-bind="click: searchClicked">Search</button>
<button type="button" class="k-button" data-bind="click: newClicked">New</button>
The page thinks that each are performing a form submit action, but by placing the type attribute, you can access the event you intended for search. You may not need your form tags if you are not going to post any data, but rather just a js event handler. Good luck.
The reason is that you are inside a <form>, which has no settings (URL, method, etc), so the browser's default behavior is probably to perform a GET to the current URL (which is a refresh). You could just use <div> instead of <form> if you just want to execute that method.
On my website i have a button which when clicked takes you to one of two random youtube videos. However i would like to change this to a image in stead of a button.I have tried to change it to a INPUT type="image" but this doesn't work. Here is the code i am using.
<SCRIPT language="JavaScript">
<!--
function get_random()
{
var ranNum= Math.floor(Math.random()*2);
return ranNum;
}
function getaGame()
{
var whichGame=get_random();
var game=new Array(2)
game[0]= "https://www.youtube.com/watch?feature=player_detailpage&v=NcFQF3PZFRk#t=722s";
game[1]= "https://www.youtube.com/watch?v=klBAW4MQffU";
location.href = game[whichGame];
}
//-->
</SCRIPT>
<FORM name="form1">
<center>
<INPUT type="button" onClick="getaGame()" >
</center>
</FORM>
Thanks for any help
An onclick event can be fired from any element. Here are some examples!
I am having an issue where when a page is loaded via Ajax, I don't have a value in my search input. Here is my HTML:
<form id="searchForm" action="javascript:;" method="post">
<div>
<input type="search" name="search-mini" id="search-mini" value="" data-mini="true" />
<input type="submit" data-mini="true" value="Search" />
</div>
</form>
The reason we have an input button is because of a request from the client as they found people having scenarios where they would click "Done" on the IOS keyboard rather than "Search" which wouldn't submit the form. here is my Javascript that handles the submit:
$(document).on('submit', '#searchForm', function () {
var text = $("#search-mini").val();
text = encodeURIComponent(text);
window.location.href = "/Mobile/Browse/Text?text=" + text;
return true;
});
This all runs fine if I refresh the page so the content is not loaded via AJAX. It only fails when linking between pages and they are loaded by AJAX. Alerting out "text" has a blank value in this scenario.
I have read about using JQM initialization events such as 'PageInit' instead of DOM ready() I just need an example implementing this with my code if this is the correct approach?
Regards,
Danny
I have a form inserted by jQuery Ajax to a page's div (say, 'content') and when the user finishes filling the form and hits 'submit' button, the result will be shown for further verification. The html and ajax code are as follows:
HTML:
<form id="userForm" action="..." method="post">
...
...
</form>
Ajax:
$(document).ready(function() {
$('#userForm').ajaxForm({
success: function(returnData) {
$('#content').html(returnData);
}
});
});
The 'returnData' is the filled form (without input fields) for further confirmation. Now, how do I implement a 'back' button such that the user may go back and modify the previously entered data?
I am working on Google App Engine with Python. Thanks.
I wouldn't replace the form with new HTML.
I would rather hide the form with display: none and add the new HTML for viewing alongside. If you want to go back, then you can just hide the "viewing div" and show again the form, without the need to refill any input elements.
Something along these lines should work
HTML:
<div id="content">
<div id="user-form-container">
<form id="userForm" ...>...</form>
</div>
<div id="viewing-container"></div>
</div>
CSS:
#viewing-container {
display: none;
}
The viewing part contains some sort of back-button, which hides the viewing area and shows the form again
jQ:
$(document).ready(function() {
$('#userForm').ajaxForm({
success: function(returnData) {
$('#viewing-container').html(returnData);
$('#user-form-container').hide();
$('#viewing-container').show();
$('#viewing-container #back-button').click(function() {
$('#user-form-container').show();
$('#viewing-container').hide();
});
}
});
});
I have a page which uses ajax to submit a comment form, add it to a db, then redisplay the page, hopefully without reloading the page its on.
If I access the script on it's own it works great, yet when I load it into another page it doesn't add the data and also refreshes the page on submit, which I want to avoid, which is the whole point of doing things this way.
Anyway, here's how I load the page:
<div id="wall_comments" class="msgs_holder"></div>
<script type="text/javascript">
$('#wall_comments').load('/pages/comment.php', { wl_id:"<?=$wl_id?>" });
</script>
and then the page itself with jquery code:
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.0/jquery.min.js" type="text/javascript"></script>
<div style="width:100%; overflow:auto;">
<form method=post>
<input type="text" class="inp" name="comment" id="comment">
<input type=submit value="do it" name="action" onclick="update()">
<input type=hidden name="wl_id" value="<?=$_REQUEST[wl_id]?>" id="wl_id">
<input type=hidden name="user_id" value="<?=$userfromcookie?>" id="user_id">
</form>
</div>
<script type="text/javascript">
function update(){
var wl_idVal = $("#wl_id").val();
var commentVal = $("#comment").val();
var user_idVal = $("#user_id").val();
$.ajax({
type: "POST",
url: "/pages/comment.php",
cache: false,
data: { submit: "", wl_id: wi_idVal, comment: commentVal, user_id: user_idVal }
});
}
</script>
And finally enter info into db (I know this should be mysqli and it will be)
if(isset($_POST['action'])){
$wl_id = mysql_real_escape_string($_POST['wl_id']);
$comment = mysql_real_escape_string($_POST['comment']);
$user_id = mysql_real_escape_string($_POST['user_id']);
$addcomment = mysql_query("insert into list_wall (
event_id,
user_id,
comment
) VALUES (
'$wl_id',
'$user_id',
'$comment'
) ",$db);
if(!$addcomment) { echo 'result error add comment'; echo mysql_error(); exit; } // debug
}
The problem is when you click the submit button, the page is submitted and the function update couldn't work. You have to cancel the default submit mechanism by using return false;
<input type=submit value="do it" name="action" onclick="update() return false;">
Another thing.
The onclick on the submitbutton will not work as excpected if the submit is caused without clicking the button.
For example mobile safari on iPhone can submit forms directly without triggering the button.
If you add UmairP's version of the onclick to the form element as an onsubmit method you should get the same result on every platform as far as I know.
You can see more details on iPhone forms in my own question on another issue.
How can I prevent the Go button on iPad/iPhone from posting the form