I'm trying to use whereExists() on an existing Eloquent query builder (called $trips):
$trips = $trips->whereExists(function ($query) use ($filterValue) {
$query->from(DB::raw("jsonb_array_elements(passengers->'adults'->'persons') as p(person)"))
->whereRaw("p.person->>'name' LIKE '?%'", $filterValue);
});
The query I'm trying to create in raw postgres format is the following (this query works fine using pgAdmin):
SELECT *
from trips
WHERE exists (select *
from jsonb_array_elements(passengers -> 'adults' -> 'persons') as p(person)
where p.person ->> 'name' LIKE 'Prof%');
And I'm receiving this error:
Invalid parameter number: parameter was not defined
I think the problem is small, but I can't see it myself.
The parameter definition in your whereRaw() statement is not quite correct. Parameterized queries are not just string replacements. Your query as written doesn't have a parameter in it, it has a string literal of '?%'. You need to change this to a query parameter, and append the % wildcard to the string you pass in.
Try this:
->whereRaw("p.person->>'name' LIKE ?", $filterValue.'%')
Related
When I run the below query I get the following error: Invalid parameter number: mixed named and positional parameters.
$subQuery = DB::table('earliest_count')
->select('reporting_week')
->where('vendor_name', $vendorName);
$dates = DB::table('invoice')
->select('week_beginning_date', 'week_end_date')
->whereRaw(':sql BETWEEN `week_beginning_date` AND `week_end_date`', [':sql' => DB::raw("({$subQuery->toSql()})")])
->where('week_beginning_date', '<', $date)
->orderBy('week_beginning_date')
->limit(1)
->mergeBindings($subQuery)
->get();
If I replace the whereRaw with the following it works:
->whereRaw('(SELECT reporting_week FROM earliest_count WHERE vendor_name = "My Vendor") BETWEEN `week_beginning_date` AND `week_end_date`')
How can I get the subquery to work without having to write the exact query as a string?
Edit
I did try the following, and I get no errors but I don't get any results. (When I enter the subquery as a string I do get a result):
->whereRaw('? BETWEEN `week_beginning_date` AND `week_end_date`', [DB::raw("({$subQuery->toSql()})")])
Laravel doesn't use named placeholders, you should use ? for placeholders and remove the name from the parameters array.
Like this:
->whereRaw('? BETWEEN `week_beginning_date` AND `week_end_date`', [DB::raw("({$subQuery->toSql()})"])
If I have the following query built using the Query Builder:
$q = DB::table('Products')->whereExist(function ($q)
{
$q->select(DB::raw(1))
->from('tags_products')
->where('products.PorductId', '=', 'tags_products.ProductID');
});
The translated SQL using $q->toSql(); that is:
select * from `Products` where `exist` = (select 1 from `tags_products` where `products`.`ProductID` = ?)
Apparently, the Query Builder translates tags_products.ProductID to ?.
Why does it become "?" ?
As #Jared Eitnier very well pointed out, Laravel uses PDO to bind the parameters you pass to the Query Builder methods. However, because when you use where the third parameter represents the value, Laravel will not treat it as a column unless you explicitly tell it to, otherwise it will treat 'tags_products.ProductID' as a regular string value. So you have two options here:
1. Use DB::raw() to let the Query Builder know that the value is not a string that requires escaping:
->where('products.PorductId', '=', DB::raw('tags_products.ProductID'));
2. Use whereRaw() which will allow you to write a raw SQL statement:
->whereRaw('products.PorductId = tags_products.ProductID');
These are mysql prepared statements.
See What is the question mark's significance in MySQL at "WHERE column = ?"?
Laravel uses mysql's PDO.
Hello I am trying to put a query member as an filter condition and the code I am trying to do is :
Member [ThisMonth] as VBAMDX.Format(VBAMDX.Now(),"yyyyMM")
SET [currentdays] AS filter([D Date].[DAY ID].Members,
[D Date].[MONTH ID]=[ThisMonth])
But The query did not recognize the Condition
Member [ThisMonth] as VBAMDX.Format(VBAMDX.Now(),"yyyyMM")
SET [currentdays] AS filter([D Date].[DAY ID].Members,
[D Date].[MONTH ID].&[201309])
The query therefore then return the desire result. I am just wondering is there anymore dynamic way to do this?
Thank you very much!
VBAMDX.Format(VBAMDX.Now(),"yyyyMM") returns a string, not a member identifier. This is like in SQL select 'myColumn' from myTable which returns the literal string ´myColumn´ and not the contents of column mycolumn.
If you want to use the Format function, then you firstly need to construct the full unique name of the member, and secondly convert the string to a member identifier using StrToMember:
Member [ThisMonth] as '[D Date].[MONTH ID].&['
+ VBAMDX.Format(VBAMDX.Now(),"yyyyMM")
+ ']' -- this returns a string!
SET [currentdays] AS filter([D Date].[DAY ID].Members,
StrToMember([ThisMonth]))
By the way: You do not need Filter here, and it can slow down queries dramatically, you can just use
SET [currentdays] AS { StrToMember([ThisMonth]) }
In my Yii application, I have a model that represents siteconfig table and have four columns:
integer config_id,
string key,
string value,
string update_time.
I created a model using Gii (to ensure that I will not make any mistakes). I don't publish entire code here, cause this is 100% unmodified by me, standard model code generated by Gii. Since my problem is related to search, I only publish important part of generated code (the search() method):
public function search()
{
// Warning: Please modify the following code to remove attributes that
// should not be searched.
$criteria=new CDbCriteria;
$criteria->compare('config_id',$this->config_id);
$criteria->compare('key',$this->key,true);
$criteria->compare('value',$this->value,true);
$criteria->compare('update_time',$this->update_time,true);
return new CActiveDataProvider($this, array(
'criteria'=>$criteria,
));
}
I'm trying to use generated model in normal Yii ActiveRecord search like that:
$etona = new SiteConfigurationRecord();
$crit = new CDbCriteria();
$crit->select = "value";
$crit->condition = "key=:key";
$crit->params = array(":key"=>"sitename");
$etona = $etona->find($crit);
But, instead of getting expected search results, a strange (for me) error occurs:
CDbCommand failed to execute the SQL statement: SQLSTATE[42000]:
Syntax error or access violation: 1064 You have an error in your SQL
syntax; check the manual that corresponds to your MySQL server version
for the right syntax to use near 'key='sitename' LIMIT 1' at line 1.
The SQL statement executed was: SELECT value FROM siteconfig t
WHERE key=:key LIMIT 1
Where did I go wrong?
You used key for column name, which is a reserved word in MySQL. Yii uses table alias in queries, but does not take any special care in case of reserverd word used as columns names. So, you have to take care of this by yourself.
For example:
$etona = new SiteConfigurationRecord();
$crit = new CDbCriteria();
$crit->select = "value";
$crit->condition = "t.key=:key"; // 't' is default alias
$crit->params = array(":key"=>"sitename");
$etona = $etona->find($crit);
This should solve your problem.
As #Dmitry explained, SQL doesn't allow you to use the column name key. The Yii call in the code in your answer works because Yii performs parameter binding automatically, using names other than reserved words for the parameters. And it also uses fully-qualified column names (prefixes all column name references with <tablename>., regardless of what invalid column name (reserved words) you pass the findByAttributes method.
now it works.. ^^
i just use this code...
$etona = SiteConfigurationRecord::model()->findByAttributes(array('key'=>'sitename'));
maybe i need to study activerecord more somehow...
but still i don't know why the code above doesn't work
I need to get a couple of Students from the database, and I have their primary keys in a comma-separated string.
Normally using SQL it would be something like:
$cleanedStudentIdStringList = "1,2,3,4";
SELECT * FROM Student WHERE id IN ($cleanedStudentIdStringList)
Yii's ActiveRecord seems to insert a single quote around bound parameters in the resulting SQL statement which cause the query to fail when using parameter binding.
This works, but doesn't use safe parameter binding.
$students = Student::model()->findAll("id IN ({$_POST['studentIds']})");
Is there a way to still use parameter binding and get only a couple of rows in a single query?
You can do it also that way:
$criteria = new CDbCriteria();
$criteria->addInCondition("id", array(1,2,3,4));
$result = Student::model()->findAll($criteria);
and use in array any values you need.
Aleksy
You can use findAllByAttributes method also:
$a=array(1,2,3,4);
$model = Student::model()->findAllByAttributes(array("id"=>$a));