url after spring maven deployment - spring

I have a basic question about deployment but I can't seem to find an answer on google...
I am working on a jakarta project and it's the first time I do the deployment.
Since I am using Spring-boot maven, I know there is an embedded tomcat that will launch with the jar.
My issue is, I don't know what url to use to check my project is working...
Before, I used the address http://localhost:9091/contextPath/endpoint, but now, I only get a whiteScreen...
So my question is, what url should I use ? Also, is there something else to do after packaging ?
Thank you for your answers.
EDIT:
Alright, so I tried actuator but that didn't help me...
With /actuator/mappings, I could see that my endpoints are correctly configured but when I use the executable jar, http://localhost:9091/contextPath/endpoint odes not work while it does if I compile with my IDE...
I don't know what url to connect to just to see the index... I'm using a very basic spring framework (boot and mvc) and my IDE is intellij community if this helps anyone
EDIT 2:
I tried to deploy the app on a local Tomcat9 to see if something would change but the connexion is reinitialized everytime I try to deploy a war using the manager, and there was no trace of error in the logs.
I tried using ./mvnw and it did work, endpoint and all, but it implies working with IDE environment
I tried using java (openjdk 13) and it compiled, but i couldn"t acces my own endpoint. I could still access the actuator endpoints so i don't know what to make of it.
Should the url be different depending on whether we are using IDE environment or just the jar?
EDIT 3:
Ok, I think have a lead but I have no idea how to resolve this:
when I began the web part of the application, I created a WEB-INF folder where I put all my jsp. My js and css files were in the resources/static folder. I tried once to put the jsp in the resources folder but it didn't work so I didn't push too hard.
Now, when I unzip the jar, i find my css and js files, but not my jsp.
When I unzip my war file, I have everything, but when I try to deploy it on a separate tomcat server, the connexion resets and I don't know why because nothing is written in the logs.
The issue then becomes:
Right now, I have
└──src
└──main
├──java
├──resources
| ├──static
| | ├──css
| | └──js
| └──template
└──webapp
└──WEB-INF
└──classes
└──jsp
What is the standard tree in intellij with jsp ?

By default Spring Boot apps are on port 8080.
Can you try http://localhost:8080?
Port can be changed in application.properties (or application.yml, application-profile.properties etc.) via server.port property (e.g. server.port=8888).

Ok, I managed to make it work.
I'm going to describe here everything of note that I encountered.
First, when I called my app to the usual url, there was no response (whiteLabel).
I added test logs and i found that I indeed called m controller.
I unzipped the jar and war i produced and came to the conclusion that the issue was architectural. I couldn't use jar, I had to use the war file.
I tried to deploy on a local tomcat server using the manager, but it always resetted the connection, so I took the manual approach - copy pasting the war file in the webapp directory.
Finally, the web pages were accessible in the browser.
Thank you for all the tips given during my research!

`http://endpoint:{PORT}/actuator/health` or `http://endpoint:{PORT}/actuator/status`
it should help but it must require spring-boot-actuator as a dependency in your pom/gradle file.

Related

springdoc-openapi generate openapi yaml on build without server

I have a Spring boot Gradle project and I want to get it's OpenAPI spec YAML file.
As I understand the official swagger-core does not support Spring boot projects, thus I found springdoc-openapi (https://github.com/springdoc/springdoc-openapi-gradle-plugin).
It seems that in order to get the YAML/JSON files, when running the generateOpenApiDocs task, the springdoc library sets up a server with some endpoints (/v3/api-docs) to download the files.
I'm using the default configuration, and for some reason I keep getting the following error:
Execution failed for task 'generateOpenApiDocs'.
Unable to connect to http://localhost:8080/v3/api-docs waited for 30 seconds
It seems that for some reason it does not set up the server. How can I fix it?
Is it possible to skip the server part? Can I configure springdoc to simply generate files on build?
If you are deploying REST APIs with spring-boot, you are relying on a servlet container.
The necessry metadata for the OpenAPI spec are only available by spring framework on runtime, which explains the choice of generation at runtime.
You can define any embeded servlet container, during your integration tests to generate the OpenAPI Spec.
This is how I resolved the issue
Specify the path
In your properties file enter:
springdoc:
api-docs:
path: /{your path}
Configure the plugin
In your build.gradle file enter:
openApi {
apiDocsUrl.set("http://localhost:{your port}/your path)
}
This happens because sometimes embedded server took sometime to start and it has 30 sec default setting. Please add the below properties in your openAPI block and it will work fine for you. Please see the below sample:
openApi {
apiDocsUrl.set("http://localhost:9090/v3/api-docs.yaml")
outputDir.set(file("Your Directory path"))
outputFileName.set("openapi.yaml")
forkProperties.set("-Dserver.port=9090")
waitTimeInSeconds.set(60)
}
You need to add the dependency below, an updated version may exist depending on when you're seeing this - intellij would tell you and help upgrade:
implementation('org.springdoc:springdoc-openapi-ui:1.6.11')
Then add the line below to your application.properties file:
springdoc.api-docs.path=/api-docs
Perhaps also get rid of the plugin, it's not necessary as long as you have the above dependency. I got rid of mine and things work fine.
After the dependency is resolved, run the app normally with intellij run buttons or the commandline.
With the app running, visit http://localhost:8080/swagger-ui/index.html - assuming your app is running on port 8080. If not, use the right port accordingly.
Also, you can check out https://github.com/springdoc/springdoc-openapi-gradle-plugin/issues/10 and https://github.com/springdoc/springdoc-openapi-gradle-plugin/issues/10#issuecomment-594010078 - those were helpful when I faced the same issue, showed me part of what to do.

How to load a WAR module into Spring's built-in Tomcat running in a standalone?

I am having three modules in my Maven project:
parent
rest-api # Spring REST API
web-client # AngularJS web client
application # Project to bundle it all up for a standalone
I am not sure if I have here an "elegant" solution so please hit me with a stick if that is complete garbage, but this is how it works - or how it's supposed to work:
rest-api
Module rest-api does simply offer the REST API and other core functionality - basically it is pure server code. It is a jar artifact.
web-client
To separate client and server code I am having the module web-client. It is a war project that hold the client webapp.
application
This module is supposed to glue it all up. It depends on rest-api and web-client. It does two important things:
It's pom.xml uses the spring-boot-maven-plugin to build a standalone runnable jar - my ultimate goal
It provides the main(String args[]) method that starts the #SpringBootApplication with SpringApplication.run(EasyModelAccessServer.class, args);
What I am currently able to is tell Eclipse to run this in a servlet container. The server boots up and I my two resources, the rest-api and the web-client working. Everything is fine so far.
The issue
What is not fully working is the standalone. If I package up the whole thing and run the server:
$ path/to/application: mvn clean package
$ path/to/application: java -jar target/application.jar
Only the REST API will work. The reason is because the web-client is not added or introduced as a web app to the Spring built-in Tomcat.
The question
is how I can make this work. There are two options which come to my mind:
Somehow sneak in the web-client.war file into the application.jar such that it is available as a resource and programmatically call tomcat.addWebapp("/web-client", "path/to/web-client.war") (or something like that) to load the additional service
Hope that the spring-boot-maven-plugin or another Spring Maven plug-in can do that for me and find somebody that links me to an example.
I've tried it with 1. but I didn't succeed to move web-client.war into application.jar but I am also not sure if I should actually do that.
FAQ
Q: "Why do you separate everything instead of merge all those modules into a server module where the Spring Maven plug-in would do everything for you out of the box?"
A: I really want to separate the client code from the server code. I could however merge web-client into application but last time I tried that I had 10 other issues why this did not work out so I decided to keep it that way and that it actually shouldn't be so hard to load an additional server resource.
Q: "Can I take a look at the project?"
A: Yes, you can. Just take a look: https://github.com/silentsnooc/easy-model-access Please forgive me that I am currently using tabs instead of whitespaces - I am going to change that as soon as I got everything up and running.

Setting up home page in spring

I am new to spring environment. I have created small test spring project through STS.
Project name: SPTest
base package name: uk.co.ifTest
When I run and open this project browser through Eclipse. It work fine, but url, it put in the browser is xx.xx.xx.xx:8080/ifTest/, instead of //xx.xx.xx.xx:8080/SPTest/.
I guess, it is adding base package name.
Is there any way I can open project with http://xx.xx.xx.xx:8080/SPTest/.
Thanks
ish
You need to change your context path for the server to point from ifTest to SPTest.
This answer will help you identify how to do it:
Changing Tomcat context path of web project in Eclipse

How to run web applications using jersey in an easy way?

I created a web application using Jersey through this maven code:
mvn archetype:generate -DarchetypeArtifactId=jersey-quickstart-webapp \
-DarchetypeGroupId=org.glassfish.jersey.archetypes -DinteractiveMode=false \
-DgroupId=com.example -DartifactId=simple-service-webapp -Dpackage=com.example \
-DarchetypeVersion=2.4.1
And I am using Tomcat v7 as my Java server. When I finish writing some code, I use mvn's package command to generate a .war file, copy this file to the /webapps folder and then start tomcat to run my application and test it on browser. But I think I waste lots of time doing these things. So I want to ask if there is an easier way test my code on browsers. How do you guys run your web applications, especially Jersey app, on your server?
And I am using Intellij Idea, does it have some features that help me build and run Jersey apps, or other J2EE apps? how to use them?
In IntelliJ IDEA you can create a Tomcat Run/Debug configuration. In that configuration you can specify "before launch" tasks/options, including running a maven goal. So by running the Tomcat configuration, IDEA will run the maven goal, deploy your code to Tomcat, start the tomcat server, and (if desired) open you web browser to a specified page.
JetBrains has a Getting Started with Spring MVC, Hibernate and JSON tutorial. What you want to do is very similar. The main difference is you will need to remove the default "make" option in the "Before Launch" section at the bottom of the run/debug configuration and instead have it run your maven task.
There is also the Creating a simple Web application and deploying it to Tomcat tutorial. It's a little older and some of the options on the run/debug dialog have changed. But at the core, its still valid. Combined with the above, you should be in good shape.
Finally take a look at the Run/Debug Configuration: Tomcat page in the help guide (also available in the online webhelp).

How to run a project containg drools in Tomcat7?

I have created a Dynamic web project which also uses drools for providing some functionality. When i put the WAR file in Tomcat7 and the server, the drools part does not work.
KnowledgeBuilder kbuilder = KnowledgeBuilderFactory.newKnowledgeBuilder();
After this line which is first line relating to drools, nothing happens.
Is some configuration required to run my project containing drools 5.5.0 Final in the Tomcat7.
Please help me. I am badly stuck and I am new to drools.
You'll have to add some facts to the working memory and execute(fire) the rules. Check out these examples on GitHub
P.S. Probably not related to Tomcat in any way. Might be worth while to try getting the rules executed from command line app first.
You need to check all the dependencies that are added to your web application (WEB-INF/lib) make sure that drools has all the required deps there, because if not it will not be able to create the knowledge builder. Most of the time if it is failing is because that you forgot to add the deps in the web app.
The following project in GitHub is a web application, containing some REST-style endpoints for validating IBANs. It uses Drools 5.5 to perform that evaluation.
https://github.com/gratiartis/sctrcd-payment-validation-web/
It generates a .war which can be loaded into Tomcat, and could be a useful starting point. The knowledge base is wrapped within a Spring service:
https://github.com/gratiartis/sctrcd-payment-validation-web/blob/master/src/main/java/com/sctrcd/payments/validation/RuleBasedIbanValidator.java
Following through how that creates a knowledge base and session might help you see where your code is going wrong.
As a bonus, you can run it up in Tomcat using "mvn tomcat7:run" to test it out immediately.

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