I'm using linux program in windows Environment (curl and grep)
This command works fine in dos shell and get result
curl --request POST "https://somesite/access_token" --user user:pass | grep -o -P -e "(?<=\"access_token\":\").+?(?=\")"
but If I try this script in batch to save result in a variable
for /f %%a in ('curl --request POST "https://somesite/access_token" --user user:pass ^| grep -o -P -e "(?<=\"access_token\":\").+?(?=\")"') do set "TOKEN=%%a"
I got this error:
.+?(? was unexpected at this time.
any idea? Thank you in advance
Related
I trying to do execute the following script in bash
#!/bin/bash
source chaves.sh
HEAD='"X-Cachet-Token:'$CACHET_KEY'"'
SEARCH="'{"'"status"'":1,"'"id"'":"'"7"'","'"enabled"'":true}'"
echo $SEARCH
if curl -s --head --request GET http://google.com.br | grep "200 OK" > /dev/null; then
echo 'rodou'
curl -X PUT -H '"Content-Type:application/json;"' -H '"'X-Cachet-Token:$CACHET_KEY'"' -d $SEARCH $CACHET_URL/7
else
echo 'não deu'
curl -X PUT -H '"Content-Type: application/json;"' -H $x -d '{"status":1,"id":"7","enabled":true}' $CACHET_URL/7
fi
But keep receiving a 400 bad request from the server.
When i try to run the same line (echo in the script, Ctrl+c and Ctrl+v) directly in terminal, the command run without problems.
The source file have the directions to path and a variable token i need to use, but as far as i have tested is reading ok.
edit 1 - hidding some sensitive content
edit 2 - posting the exit line (grabed trought Ctrl+c, Ctrl+v)
The command i neet to input in server is:
curl -X PUT -H "Content-Type:application/json;" -H
"X-Cachet-Token:4A7ixgkU4hcCWFReQ15G" -d
'{"status":1,"id":"7","enabled":true}'
http://XXX.XXX.XXX.XXX/api/v1/components/7
And the exit i grabed trought echo comand, give me the exact exit i want, but don't run inside script, only outside.
I'm a bit new to the curl, any help can be apreciate.
Sorry for the bad english and tks in advance.
I know a similar question was posted, but I can't get it to work on my machine.
I tried the 1st answer from the mentioned question, i.e. response=$(curl --write-out %{http_code} --silent --output /dev/null servername) and when I echo $response I got 000 [Not sure if that is the desired output].
However, when trying to do so with my cURL command, I get no output.
This is my command:
curl -k --silent --ftp-pasv --ftp-ssl --user C:is_for_cookies --cert localcert_cert.pem --key certs/localcert_pkey.pem ftps://10.10.10.10:21/my_file.txt
and I use it with
x=$(curl -k --silent --ftp-pasv --ftp-ssl --user C:is_for_cookies --cert localcert_cert.pem --key certs/localcert_pkey.pem ftps://10.10.10.10:21/my_file.txt)
but when I try to echo $x all I get is a newline...
I know the cURL is failing, because when I run the same command, without --silent, I get curl: (7) Couldn't connect to server
This Q is tagged with both sh, bash because I've tried it on both with same results
I found this option which kind of helps (but I still don't know how to assign it to a variable, which should be easier than this...):
--stderr <file>
Redirect all writes to stderr to the specified file instead. If the file name is a plain '-', it is instead written to stdout.
If this option is used several times, the last one will be used.
When I use it like this:
curl -k --silent -S --stderr my_err_file --ftp-pasv --ftp-ssl --user C:is_for_cookies --cert localcert_cert.pem --key certs/localcert_pkey.pem ftps://10.10.10.10:21/my_file.txt
I can see the errors (i.e. curl: (7) Couldn't connect to server) inside that file.
I used --silent to suppress all output, and -S to un-suppress the errors, and the --stderr <file> to redirect them
I set a command line argument as below:
$TOKENARG='Authorization: Bearer 9042f9a3caacc63419be489aefec02a5eae338c33'
curl -v -X DELETE -H $(echo $TOKENARG) http://localhost:3001/api/v1/articles/3
And desired result is:
curl -v -X DELETE -H 'Authorization: Bearer 9042f9a3caacc63419be489aefec02a5eae338c33' http://localhost:3001/api/v1/articles/3
But when I run the above one it doesn't work as expected and returns the following messages:
curl: (6) Could not resolve host: Bearer
* Rebuilt URL to: 9042f9a3caacc63419be489aefec02a5eae338c33
Could not resolve host: 9042f9a3caacc63419be489aefec02a5eae338c33
How should I pass argument using a variable?
Because you don't quote your command substitution, the string is split up into three words, Authorization:, Bearer and 9042f9a3caacc63419be489aefec02a5eae338c33. To prevent that, you could quote it:
curl -v -X DELETE -H "$(echo $TOKENARG)" http://localhost:3001/api/v1/articles/3
But you don't need echo and the command substitution at all: $(command) has the same output as command, so you can use
curl -v -X DELETE -H "$TOKENARG" http://localhost:3001/api/v1/articles/3
Side note: all uppercase variable names should be used for environment variables only, see for example the POSIX spec (fourth paragraph), so better would be
$tokenarg='Authorization: Bearer 9042f9a3caacc63419be489aefec02a5eae338c33'
curl -v -X DELETE -H "$tokenarg" http://localhost:3001/api/v1/articles/3
I am having a problem with my bash script. It is producing an error of
curl (6) couldn't resolve host
What have I done wrong?
The following is my bash script.
#!/bin/bash
(set -o igncr) 2>/dev/null && set -o igncr; # this comment is needed
CookieFileName=cookies.txt
TEST="curl -k --cookie $CookieFileName --cookie-jar $CookieFileName POST -F "passUID=xxx&passUCD=xxx" https://wp1.coned.com/retailaccess/default.asp"
echo $TEST
RESPONSE=`$TEST`
echo $RESPONSE
Try this instead :
#!/bin/bash
set -o igncr
CookieFileName='cookies.txt'
curl -k \
--cookie "$CookieFileName" \
--cookie-jar "$CookieFileName" \
--data "passUID=xxx&passUCD=xxx" \
"https://wp1.coned.com/retailaccess/default.asp" # POST request
If you need to load another page after that, simply chains cURL commands with the previous line :
curl -k \
--cookie "$CookieFileName" \
--cookie-jar "$CookieFileName" \
"https://wp1.coned.com/retailaccess/another_page.asp" # GET request
Note
Command Substitution: The $(foo bar) causes the command 'foo' to be executed with the argument 'bar' and $(..) will be replaced by the output. See http://mywiki.wooledge.org/BashFAQ/002, http://mywiki.wooledge.org/CommandSubstitution, and http://mywiki.wooledge.org/BashFAQ/082
when i use bash to upload files to dropbox, it works fine but when i manually use command line it does not work.
I'm thinking it might be the & in the url.. im not sure..
Bash code:
CURL_BIN="/usr/bin/curl"
#Note: This option explicitly allows curl to perform "insecure" SSL connections and transfers.
#CURL_ACCEPT_CERTIFICATES="-k"
CURL_PARAMETERS="--progress-bar"
APPKEY="zrwv8z3bycfk3m8"
OAUTH_ACCESS_TOKEN="aaaaaaaa"
APPSECRET="aaaaaaaaaa"
OAUTH_ACCESS_TOKEN_SECRET="aaaaaaaaa"
ACCESS_LEVEL="dropbox"
API_UPLOAD_URL="https://api-content.dropbox.com/1/files_put"
RESPONSE_FILE="temp2.txt"
FILE_SRC="temp.txt"
$CURL_BIN $CURL_ACCEPT_CERTIFICATES $CURL_PARAMETERS -v -i -o "$RESPONSE_FILE" --upload-file "$FILE_SRC" "$API_UPLOAD_URL/$ACCESS_LEVEL/$FILE_DST?oauth_consumer_key=$APPKEY&oauth_token=$OAUTH_ACCESS_TOKEN&oauth_signature_method=PLAINTEXT&oauth_signature=$APPSECRET%26$OAUTH_ACCESS_TOKEN_SECRET"
Manual code:
curl --insecure --progress-bar -v -i -o temp2.txt --upload-file temp.txt https://api-content.dropbox.com/1/files_put/dropbox/attachments/temp.txt?oauth_consumer_key=aaaaaaaaaa&oauth_token=aaaaaaaaa&oauth_signature_method=PLAINTEXT&oauth_signature=aaaaaaaaa%26aaaaaaaaaa
curl --insecure --progress-bar -v -i -o temp2.txt --upload-file temp.txt "https://api-content.dropbox.com/1/files_put/dropbox/attachments/temp.txt?oauth_consumer_key=aaaaaaaaaa&oauth_token=aaaaaaaaa&oauth_signature_method=PLAINTEXT&oauth_signature=aaaaaaaaa%26aaaaaaaaaa"
The solution is to add in the inverted commas "