How to compare dynamic url? - laravel

I have stored a url in session in laravel. Now i want to compare link between session url which was stored and the url()->previous(). But the problem is url is dynamic.
THe problem i am facing
$url = url('/').'/complete-profile/*';
if(session()->get('url.intended') == $url)
{
return redirect('/home');
}
This doesn't work. how to compare /complete-profile/* with other url.. (*) this can be anything

Try something like this. Builds your URL and the rest check if it contains the word complete-profile :
$url = 'complete-profile';
if (strpos(session()->get('url.intended'), $url) !== false) {
return redirect('/home');
} else {
//
}

Related

Searching value in already cache data from database in laravel

I am learning to make caching and as I know
if(cache::has('cacheKey')) {
cache::get('cacheKey')
} else {
$data=cache::remember('cacheKey',time,function() {
return db::table('user')->get();});
return $data;
}
now question is when I am trying to search a specific data on key and then on result paginate that data for this I did use Cache::remember but how can make this fast when I am using all the time cache::remember function when I am trying to search in cache key, here is code
$page = $req->has('page') ? $req->query('page') : 1;
$keyword = $req->keyword;
if(cache::has('FileData')) {
if(!empty($keyword)) {
$file = cache::remember('FileData'.'search='.$keyword.'page='.$page,1440,function() use ($keyword) {
return File::with('callcase','lettercase','update_table','fileimages')
->where('id','Like','%'.$keyword.'%')
->orWhere('file_name','Like','%'.$keyword.'%')
->orWhere('recieved_by','Like','%'.$keyword.'%')
->orWhere('processed_by','Like','%'.$keyword.'%')
->orWhere('address','Like','%'.$keyword.'%')
->orWhere('contact_no','Like','%'.$keyword.'%')
->orWhere('show_status','Like','%'.$keyword.'%')
->orWhere('Reopen','Like','%'.$keyword.'%')
->orderBy('id','desc')
->paginate(25)
->setpath('');
});
$file->appends(['keyword'=>$keyword]);
if(count($file)>0) {
return view('home')->with('files',$file) ;
} else {
$error = "File does not found , Search another using keyword ";
return view('home')->with('filemsg',$error);
}
} else {
$file = cache::remember('FileData'.'page='.$page,1440,function () {
return File::with('callcase','lettercase','update_table','fileimages')
->orderBy('id','desc')
->paginate(25);});
return view('home')->with('files',$file) ;
}
} else {
$file = cache::remember('FileData',1440,function(){
return File::with('callcase','lettercase','update_table','fileimages')
->orderBy('id','desc')
->paginate(25);
});
return view('home')->with('files',$file);
}
My code is working fine and returning data as i wanted but i am confused on this when every time i am making remember data then how can i make that faster it would faster when i will retrieve data from already cache key and search in them and paginate them , How can i do this and help me if somehow i am doing wrong.

Is it wrong to parse the verification from Google?

I used the script from here to do the verification.
The $result === FALSE condition was being bypassed regardless of me clicking on the re-captcha validation on my form.
So I decided to manually parse it like so:
The return looks like this if a failure:
{
"success":false,
"error-codes":[
"missing-input-response"
]
}
And if it's success it looks similar but some additional things are attached, but the main thing I targeted was the string "success":true,
With this part of the script directly below the $result variable:
$result_copy = $result;
// remove white spaces everywhere
$mod_res_copy = preg_replace('/\s+/', '', $result_copy);
$success_string = '"success":true';
if(strpos($mod_res_copy, $success_string) !== false) {
$status = "ok";
}else {
$status = "not-ok";
}
if ($status == "not-ok") {
echo "Please complete the captcha to prevent spam.";
exit;
}else {
// trigger database insert of comment or whatever
}
What I want to know is, is this wrong? Can this be spoofed? I'm using PHP as my server-side scripting language.
You are doing way more work than you need, to parse $result.
It is in JSON format, so this is all you need:
$status = json_decode($result)->success ? 'ok' : 'not-ok';

How to get Response of REST API in JSON format by Default in Magento

In magento as we use the REST url to access the data,as http://localhost/magemto/api/rest/products it returns in XML format.
But as my team requirement, I should send the data in JSON format to access AJAX calls easily.. I have used REST client to include a header as 'Content-Type:appilcation/json'.. Then it returns in JSON format.. But I want it as defaultly by the magento API..
Hey, I do have a solution for this, I would like to share with you.
First go to your magento root folder then go to following path
\app\code\core\Mage\Api2\Model\Request.php
Go to the method getAccepTypes() and change with this code below it will fulfill your requirement.
public function getAcceptTypes()
{
$qualityToTypes = array();
$orderedTypes = array();
foreach (preg_split('/,\s*/', $this->getHeader('Accept')) as $definition) {
$typeWithQ = explode(';', $definition);
$mimeType = trim(array_shift($typeWithQ));
// check MIME type validity
if (!preg_match('~^([0-9a-z*+\-]+)(?:/([0-9a-z*+\-\.]+))?$~i', $mimeType)) {
continue;
}
$quality = '1.0'; // default value for quality
if ($typeWithQ) {
$qAndValue = explode('=', $typeWithQ[0]);
if (2 == count($qAndValue)) {
$quality = $qAndValue[1];
}
}
$qualityToTypes[$quality][$mimeType] = true;
}
krsort($qualityToTypes);
foreach ($qualityToTypes as $typeList) {
$orderedTypes += $typeList;
}
unset($orderedTypes);
$orderedTypes=Array
("application/json" => 1);
return array_keys($orderedTypes);
}
Hope this help you.

Whch is correct redirect('/') or redirect('') in Codeigniter?

Both are working, but I am asking if there is any difference or can I just use redirect(); ?
So from these 3 variants, which one is the one that I should stick to?
redirect('/');
or
redirect('');
or
redirect();
If you look at the source you can see that it appends the given URL to the site_url.
function redirect($uri = '', $method = 'location', $http_response_code = 302)
{
if ( ! preg_match('#^https?://#i', $uri))
{
$uri = site_url($uri);
}
switch($method)
{
case 'refresh' : header("Refresh:0;url=".$uri);
break;
default : header("Location: ".$uri, TRUE, $http_response_code);
break;
}
exit;
}
So like you said, all those options work.
But I would personally recommend to use:
redirect('/');
If you work with multiple developers this is easier to understand for those who are not familiar with CodeIgniter, since most developer know that "/" refers to the "root directory".

How can I show cookies in to codeigniter?

how can I show cookies?
i want see cookies in codeigniter.
session i see :
print_r($this->session->all_userdata());
But cookies ?
I took a look at system/core/Input.php:
function _fetch_from_array(&$array, $index = '', $xss_clean = FALSE)
{
if ( ! isset($array[$index]))
{
return FALSE;
}
if ($xss_clean === TRUE)
{
return $this->security->xss_clean($array[$index]);
}
return $array[$index];
}
function cookie($index = '', $xss_clean = FALSE)
{
return $this->_fetch_from_array($_COOKIE, $index, $xss_clean);
}
As far as I can see, you cannot show all cookies with $this->input->cookie(). Only one at a time.
If you really want to see all the cookies, just try var_dump($_COOKIE).
Or if you need show one cookie only, specify your_key: $this->input->cookie('your_key')
Hope this helps =)
Use $this->input->cookie().
For more options use the cookie helper: http://codeigniter.com/user_guide/helpers/cookie_helper.html

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