utilizing awk and making an awk script - beginner question - bash

Question

input fields are this order: lastname, firstname, section, assignment, grade.
with a list of grades from the input file grades.txt, make an awk script
which prints to match the format below.
print the avg grade and the number of failing grades (<= 60) in the specified section.
grades.txt:
Alicia, Joseph, 2, 1, 40
Alfonzo, Gary, 3, 3, 85
Albert, Tom, 2, 1, 90
Bailey, Linda, 3, 2, 76
Butcher, Stewie, 3, 1, 80
Buser, Gary, 1, 3, 59
Canyon, Nicole, 2, 5, 90
EXAMPLE OUTPUT for section 1 (for
the section number specified on the cmd-line)
Gary Buser – 59 – 3
Fails = 1
Average Grade = 59
BEGIN {
# first last - grade - assignment
# Fails = 1
# Avg Grade = grade
}
{
for(i=0; i<=NF; i++)
print($2, $1, $5, "-", $4);
total+=$5;
if ( $5 <= 60 )
fails=fails++;
else {
fails=0;
}
avg=total/i;
}
END {
print("Fails =", fails);
print("Average Grade =", avg);
}
The command line I'm trying to use but it is not working:
awk '$3==1' -f name.awk grades.txt
What am I doing wrong to achieve the desired output?

Answer 1

$ cat tst.awk
BEGIN { FS="[[:space:]]*,[[:space:]]*" }
$3 == sect {
print $2, $1, "-", $5, "-", $4
if ( $5 <= 60 ) {
fails++
}
sum += $5
cnt++
}
END {
print "Fails =", fails+0
print "Average Grade =", (cnt ? sum / cnt : 0)
}
$ awk -v sect=1 -f tst.awk grades.txt
Gary Busey - 43 - 3
Fails = 1
Average Grade = 43