Spring boot #query show parameter table - spring

Question

I just want to show first name and last name to this project
and I have this entity class and repository
but error is
#Entity
public class Customer {
private int id;
private String firstname;
private String lastname;
private String city;
private String country;
private String phone;
private Collection<Orders> ordersById;
#Id
#Column(name = "id")
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
#Basic
#Column(name = "firstname")
public String getFirstname() {
return firstname;
}
public void setFirstname(String firstname) {
this.firstname = firstname;
}
#Basic
#Column(name = "lastname")
public String getLastname() {
return lastname;
}
public void setLastname(String lastname) {
this.lastname = lastname;
}
#Basic
#Column(name = "city")
public String getCity() {
return city;
}
public void setCity(String city) {
this.city = city;
}
#Basic
#Column(name = "country")
public String getCountry() {
return country;
}
public void setCountry(String country) {
this.country = country;
}
#Basic
#Column(name = "phone")
public String getPhone() {
return phone;
}
public void setPhone(String phone) {
this.phone = phone;
}
#OneToMany(mappedBy = "customerByCustomerId",fetch = FetchType.LAZY)
public Collection<Orders> getOrdersById() {
return ordersById;
}
public void setOrdersById(Collection<Orders> ordersById) {
this.ordersById = ordersById;
}
and my repository is :
#Repository
public interface CustomerRepo extends JpaRepository<Customer, Integer> {
#Query(value = "SELECT firstname, lastname from Customer",nativeQuery = true)
List<Customer> findAllCustomer();
}
but I have this error for use this Query
I use MS DATABASE SQL Server
ERROR is :
SQL Error: 0, SQLState: S1093
The column name id is not valid.
Servlet.service() for servlet [dispatcherServlet] in context with path [] threw exception [Request processing failed; nested exception is org.springframework.orm.jpa.JpaSystemException: could not execute query; nested exception is org.hibernate.exception.GenericJDBCException: could not execute query] with root cause
Hibernate:
SELECT
firstname,
lastname
from
Customer
2020-09-25 23:13:23.634 WARN 7712 --- [nio-8080-exec-1] o.h.engine.jdbc.spi.SqlExceptionHelper : SQL Error: 0, SQLState: S1093
2020-09-25 23:13:23.634 ERROR 7712 --- [nio-8080-exec-1] o.h.engine.jdbc.spi.SqlExceptionHelper : The column name id is not valid.
2020-09-25 23:13:23.672 ERROR 7712 --- [nio-8080-exec-1] o.a.c.c.C.[.[.[/].[dispatcherServlet] : Servlet.service() for servlet [dispatcherServlet] in context with path [] threw exception [Request processing failed; nested exception is org.springframework.orm.jpa.JpaSystemException: could not execute query; nested exception is org.hibernate.exception.GenericJDBCException: could not execute query] with root cause

Answer 1

You need to add mapping , so add this class
public class CustomerResult{
private String firstname;
private String lastname;
public CustomerResult(String surname, String lastname){
this.firstname = firstname;
this.lastname = lastname;
}
// getters / setters
}
And add this in your repository
#Query("select NEW com.yourpackageClass.CustomerResult(
o.customer.firstname, o.customer.lastname)
from Customer as o")
List< CustomerResult> findAllCustomer();
Hope useful