I have problem with fullpage js, situation is:
in full page content there is element with styling for example:
.element{
left: auto;
right: 5vw;
width: 50%;
bottom: 15vh;
transform: none;
}
When page is load (with this section anchor or no ) div looks like for about 100px more to bottom as it should be. When this first section is scrolled down and then back to top position of this element looks as it should be.
I know that element is in same position as in code, but don't know why looks more to bottom before first scroll.
I was also try with min-height and padding:15vh 0 but usucessfuly:/
Thanks for help
solution was to adding height 100vh to parent element of this absolute element. In my case slick slider.
Related
I have this jsfiddle script that I am having trouble to do the following:
Respond to button click.
To show the box drawn on the canvas
I know that I could make this work if I add "z-index: -1" to
var sss = `
.container:before {
content: "";
position: absolute;
width: 200%;
height: 200%;
top: -50%;
left: -50%;
background: url("${url}") 50% 50% no-repeat;
-webkit-transition: all 1s;
-moz-transition: all 1s;
-ms-transition: all 1s
-o-transition: all 1s;
transition: all 1s;
}
`;
$(`<style id="dynastyle" type='text/css'>${sss}</style>`).appendTo("head");
But I don't want to do that for a peculiar reason that is too complicated to explain here.
Does anyone know how to get this to work? To be honest, I have no idea why the button is not clickable. enter link description here
Also, I need to be able to draw on top of the canvas. BTW, I don't want to draw the image in the canvas.
After tweaking it for a few hours, I finally got it working. Basically I needed to do the following:
enclosing the buttons in a div that has the position attribute and z-index'd (I used 1, I believe that the default value is 0, giving 1 to the buttons makes it bigger than the 0 for the background image).
place the canvas in a different div and use absolute position to overlay it on top of the div that has the background image and use z-index 1.
When all these two things are done, I can remove the z-index on the dynamic style for the background image. What has giving me a lot of trouble during this was that I keep forgetting to add the position attribute on the elements involved in the layering.
So my image is 1920px x 150px
all I want is the image should remain at the center of the screen when the browser screen bocomes lessthan 1920px, it should auto hide an equal amount of pixels from left and right sides of the image.
eg., if the browser total width is 1520px, then 200px from left and 200px from right should be hidden (I don't want the image to be at the center allways)
Is there some way i can do this?
Thanks in advance
Instead of using the image in an <IMG> tag, use it as the background of a div, give it a class imgBG, and include these styles:
.imgBG{
background: url(images/imagename.jpg) no-repeat 50% top;
width: 100%;
height: 150px;
margin: auto;
}
Is it possible to comply all these requirements ?
the height of the grid shall be fixed whatever the number of records;
the right space after the last columns shall be never displayed;
if the number of records is greater than the height of the grid then a vertical scrollbar shall be displayed;
an horizontal scrollbar shall be never displayed;
when possible, the height could be adapted in order to not have an "half" displayed record in the bottom of the grid.
with scroll = true
... and whatever the number of grids on screen OUF !
PS: Oleg has surely the answer ...
Add this to your stylesheet:
.ui-jqgrid .ui-jqgrid-bdiv thead,div,tbody{
position: relative;
margin: 0em;
padding:0;
/*overflow: auto;*/
overflow-x:hidden;
overflow-y:auto;
text-align:left;
}
As parameters to jqgrid add:
scrollOffset: 0,
I have an outer div with a variable height (and max-height) that's set with a specific pixel amount by JavaScript, containing two divs within.
The 1st div is intended to hold a variable amount of content, e.g. a list of links. It has no height set.
The 2nd div is intended to hold a fixed amount of content, and has a specific height set.
Right now, the max-height isn't working. The 1st div keeps growing, even with overflow: auto; set, and pushes the 2nd div below it outside the bounds of the outer div. How can I make it so that when the 1st div gets too large for the outer div to contain both it and the fixed-height 2nd div, the 1st div will start to scroll?
Example page: http://thevastdesign.com/scrollTest.html
Thanks for any help. I'd appreciate a CSS solution the most, even if it requires some hacks. It only has to work in Firefox 3+, IE8, and IE7.
Ideas?
You cant really do that without JS. Your max-height on the outer-div isnt going to control the height of one of your inner divs to invoke its scrolling. That inner div is always going to be the height you set (pixels, auto, etc..). You can either make the entire outer div scroll as needed by using overflow: auto or you can set a max height on the first inner div and set the overflow.
Given your setup, I would do the following (class names are implied by your question, not taken from the linked source):
div.outer {
position: relative;
max-height: $length(y);
overflow: hidden;
}
div.innerFixed {
position: absolute;
bottom: 0;
height: $length(y);
overflow: hidden; /* just in case, to keep things from
blowing out into all manner of crazy */
}
div.innerFlex {
max-height: $length(y);
overflow: auto;
}
These rules don't address box properties, which will have an impact on the height values that you apply. The combined height values (with box values included) of .innerFixed and .innerFlex should equal the height value of the container.
If you want to get all Zen and flip the vertical composition, you do that by swapping bottom for top on .innerFixed and assigning margin-top or padding-top to .innerFlex.
Something else I noticed is that you've got
div.outer { float: left; }
...But given what you need from that element (and to set the right content priority) I would instead suggest that you put your big column first in the source order and apply
div.mainContent {
float: right;
width: $length(x);
}
div.outer { /* i.e., the column that started the discussion */
margin-right: length(x);
}
with the understanding that the margin-right of the latter is somewhat greater than the width of the former (greater to account for the gutter between the two elements). Try it, you'll like it.
I have a problem with IE.
I have a fixed div like this:
#fixed {
position: fixed;
top: 0px;
left: 0px;
z-index: 9998;
width: 100%;
height: 40px;
}
Inside this div I want to place another div that has a height that is higher than its holder (higher than 40px). So I put a relative or an absolute div inside it and it works splendid in all browsers except IE, at least IE8.
But in IE8 the child div gets cut because of the height of 40px specified for it's holder.
Is there any workaround to this problem? I'm starting to get gray hairs..
Quick reply: have you tried setting the clip property of the contained div to it's own size?
Another workaround would be (if, say you have a container div with left/right margins auto and position: relative) to have the second div outside the fixed div in your HTML, then position it fixed within the container div instead - since it's also fixed, you can then set top/bottom and left/right positions to suit.