I'm following this example LINK. But, I have floating value for the cell, so when I run this example with every cell value as 4.5 (hardcoded), the excel generates cells with value 450.00 %, while expected value was 4.500 %.
NOTE: I have just changed line 26 of above example from:
ws.add_row ["Q#{i}", 10000*((rows/2-i) * (rows/2-i)), "=100*B#{i}/SUM(B3:B#{rows+offset})"], :style=>[nil, money, percent]
to:
ws.add_row ["Q#{i}", 10000*((rows/2-i) * (rows/2-i)), "4.5"], :style=>[nil, money, percent]
Just hard-coded 4.5
OUTPUT:
How to add just a % sign to cell value without changing cell value?
Also, I don't wanr cell to be :string formatted, it has to be :float
Related
I have two columns in excel and want to subtract the time difference in minutes
21/12/2022, 8:17 pm
21/12/2022, 8:00 pm
How can I convert text to a number format so that I can subtract those easily
You can use the VALUE function. The VALUE function converts a text string that represents a number to a number value.
For example, to convert the text "8:17" to a number value, you can use the following formula:
=VALUE("8:17")
This will return a number value equivalent to the time 8:17.
To subtract the time difference between two cells in Excel, you can use the =B2-A2 formula, where A2 and B2 are the cells containing the two times you want to subtract.
You can also use the =TEXT function to convert the result of the subtraction back to a text string in a desired format, if needed. For example, to convert the result to a time format, you can use the following formula:
=TEXT(B2-A2, "h:mm")
This will return the time difference in the format "hh:mm".
Good morning,
I have a little problem there.
I would like work with data from two different time interval.
for example, BTC (1 day time interval) and BTC (4 hour time interval) chart.
The main time interval is the 4 hour. The value "HA_C", this is the close value of "BTC 1 Day".
The "close BTC 1 Day time interval" value displayed correct in the 4 hour chart.
But the value "test" with a simple arithmetic problem differs greatly and is wrong.
You can test this as follows:
Loads the strategy in "BTC", time interval "1 Day",
note from one day the "BTC Close" value and the "test" value.
Then switch to "BTC" 4 hour time interval.
You will see, that the "HA_C Close" from the 1 hour time interval is the correct value,
but the "test" value is displayed incorrectly.
Why is the "test" value after a calculation incorrectly, although the "Close" value is correct ???
I have find out, that the problem is the "ta.ema (source, length)" function. Can someone give me a formula, that calculates the same value as the "ta.ema (source, length)" function.
**// This source code is subject to the terms of the Mozilla Public License 2.0 at https://mozilla.org/MPL/2.0/
// © flashpit
//#version=5
strategy("TEST", process_orders_on_close=true, overlay=true, calc_on_every_tick=true, pyramiding=30)
varip test = 0.0
HA_Symbol = ticker.heikinashi("BINANCE:BTCUSDT")
HA_C = request.security(HA_Symbol, "1D", close)
test:= ta.ema(HA_C, 7) * 1.05
plot (HA_C)
plot (test)**
I have finde the correct code. Here is it:
c2_1D = request.security(ticker.heikinashi('BINANCE:BTCUSDT'), "1D", t3_D (close, T3Length_1D, T3FactorCalc_1D))
It is due to the context you have called the ema function. If your chart is H4 and you perform your test calculation in the global scope, it is using 7 x H4 bars of HA_C. On BTCUSDT, over the last 7 H4 bars, it would have been 7 bars made up of multiples of only 2 daily values, hence the incorrect result.
When you change the chart to D1, it shows the correct result because now the global context of the script is now operating in the same timeframe as the security call.
If you want the correct value from the ema using 7 x 1D bars it has to be done within the context of the security call. For example :
test = request.security(ticker.heikinashi("BINANCE:BTCUSDT"), "D", ta.ema(close, 7))
If you need to perform multiple operations using the same ticker, you can also wrap them in a function and just pass the one function to a single security call. For example, this will return the daily close and the daily ema 7 :
f_ema_and_close(_src, _len) =>
_ema = ta.ema(_src, _len)
[_src, _ema]
[D1_close, D1_ema7] = request.security(ticker.heikinashi("BINANCE:BTCUSDT"), "D", f_ema_and_close(close, 7))
plot(D1_close, color = color.yellow)
plot(D1_ema7, color = color.red)
I have measure column, which I am using for pivoting, and I have also used New calculated items. Now the new calculated item is to return data in double format,which is percentage, but the other results is to return data in integer. If the data format of the column is decimal then the measure column, which are integers would show data with decimals (so 2 becomes 2.00), and if i keep it integer then decimals from the percentage column would be removed (so 45.28% becomes 45%).
Can the data format of the column be changed such that when there are decimal, then decimals are returned and when whole numbers, whole numbers are returned (without the .00s)?
Expected Result
A B (A/B)*100
2 6 33.33
Note that A and B are coming from the same column, and the (A/B)*100 is my New Calculated Item.
Criteria tab / Properties / Data format and select "up to 2" in decimal places. This option excludes the ".00" for integer values.
In the image above, how do I replace the portion "Tom.A:C" in the vlookup function with the text in cell B2 + .A:C ?
Where "Tom" is the name of a sheet in my workbook and I want to lookup a value in the second column of that sheet.
The formula
=VLOOKUP(lookup,sheet!range,column,match)
Then, in your example, you must write it like this:
=VLOOKUP(A2, TOM ! [Range of the sheet], 2, FALSE)
Edit:
I did not understand the first time exactly what was the question, so here it is the answer:
The formula
=VLOOKUP(lookup,indirect(concat(<cell with sheetname>,<"!"|".">,"<CELL RANGE IN ALL LOOKING SHEETS>")), column, match)
Then in your example:
=VLOOKUP(A2, indirect(concat(A2,".","A:C")), 2, 0)
First you need to concatenate the value of the sheet and range that you want, then with indirect, you take that string value and use it as a valid reference.
I need to change all the value labels of all my variables in my spss file to be the value itself.
I first tried -
Value Labels ALL.
EXECUTE.
This removes the value labels, but also removes the value entirely. I need this to have a label of some sort as I am converting the file and when there is no values defined it turns the value into a numeric. Therefore, I need the all value labels changed into numbers so that each value's label is just the value - value = 1 then label = 1.
Any ideas to do this across all my variables??
Thanks in advance!!
Here is a solution to get you started:
get file="C:\Program Files\IBM\SPSS\Statistics\23\Samples\English\Employee data.sav".
begin program.
import spss, spssaux, spssdata
spss.Submit("set mprint on.")
vd=spssaux.VariableDict(variableType ="numeric")
for v in vd:
allvalues = list(set(item[0] for item in spssdata.Spssdata(v.VariableName, names=False).fetchall()))
if allvalues:
cmd="value labels " + v.VariableName + "\n".join([" %(i)s '%(i)s'" %locals() for i in allvalues if i <> None]) + "."
spss.Submit(cmd)
spss.Submit("set mprint off.")
end program.
You may want to read this to understand the behaviour of fetchall in reading date variables (or simply exclude date variables from having their values labelled also, if they cause no problems?)