Models and relations
class Publisher extends Model
{
use HasRelationships;
public function collections(): BelongsToMany
{
return $this->belongsToMany(Collection::class)
->orderBy('title')
->using(CollectionPublisher::class);
}
public function series(): HasManyDeep
{
return $this->hasManyDeepFromRelations($this->collections(), (new Collection())->series());
}
}
class Collection extends Model
{
use HasRelationships, Translatable;
public function editions(): HasMany
{
return $this->hasMany(Edition::class);
}
public function series(): HasManyDeep
{
return $this->hasManyDeepFromRelations($this->editions(), (new Edition)->series());
}
}
class Edition extends Model
{
use HasRelationships, LoadsRelationshipsWithoutScopes, Translatable;
public function series(): BelongsTo
{
return $this->belongsTo(Series::class);
}
public function collection(): BelongsTo
{
return $this->belongsTo(Collection::class);
}
}
And of course there is a Series model.
The problem is that the series relation on the Publisher is returning each Series as many times as there is an Edition for that Publisher in the Series
How do I trim it down so each series is only returned once?
A simple groupBy('series.id') does not work due to the full group by limitations, and I'm not sure how to get around this using the has many deep package.
I finally came up with a solution
On the Publisher model:
public function series(): Builder
{
return $this->hasManyDeepFromRelations($this->collections(), (new Collection())->series())
->getQuery()
->select('series.*')
->groupBy('series.id');
}
The getQuery() part (undocumented in Laravel) limits the scope and allows the groupBy() to work
Thanks to Jonas Staudenmeir for the help
Related
I have an Article model with many-to-many relation with the Tag model
The Article model
class Article extends Model
{
public function tags()
{
return $this->belongsToMany(Tag::class);
}
}
The Tag model
class Tag extends Model
{
public function articles()
{
return $this->belongsToMany(Article::class);
}
}
What I want is to get all the unique tags that have a relation with at least one (or more) article in the articles table. I want to retrieve it through a static method in the Article model like below
public static function allTags()
{
// return static:: all the tags
}
How can I do this? Thanks in advance.
EDIT: this is how I solved it. Appreciate the help!
public static function allTags()
{
return Tag::query()->whereHas('articles', function($query) {
$query->where('status', '<>', 'draft');
})->pluck('tag', 'id');
}
Using whereHas()
$tags = Tag::query()->whereHas('articles')->get();
I have 3 table in laravel:
class General extends Mode
{
public function populars()
{
return this->hasMany('App\Popular');
}
}
enter code here
and
class Popular extends Model
{
public function general()
{
return this->belongsTo('App\General');
}
}
and
class Specific extends Model
{
public function popular(){
return this->belongsTo('App\Popular');
}
}
...
how to join tables and return this list result:
1. generals
2.popular
3.Specific
I assume Popular has many Specific, you could add another mapping in Popular model as
class Popular extends Model
{
public function general()
{
return this->belongsTo('App\General');
}
public function specific()
{
return this->hasMany('App\Specific');
}
}
Doing with eloquent way you could write it as
$generals = General::with('populars.specific')->get();
Using query builder you could join them as
DB::table('general as g')
->join('popular as p', 'g.id','=','p.general_id')
->join('specific as s', 'p.id','=','p.popular_id')
->get();
I have query that I run on my ServiceController
return Service::with('contacts', 'locations.datetimes')->find($service->id);
This works great perfectly, but I need to change it. The relationships are defined as follows:
class Service extends Model
{
public function locations()
{
return $this->belongsToMany('App\Models\Service_location', 'service_location_service');
}
}
class Service_location extends Model
{
public function datetimes()
{
return $this->hasMany('App\Models\Service_detail');
}
}
I need a second constraint on the datetimes where I need the relationship to be along the lines of
return $this->hasMany('App\Models\Service_detail')->where('service_id', $service->id);
The problem is I can't find a way to pass through the $service_id. How do you handle two constraints on a hasMany relationship?
Let try this. Change Service_location to this
class Service_location extends Model
{
public function datetimes()
{
return $this->hasMany('App\Models\Service_detail');
}
public function scopeServiceId($query)
{
return $query->where('service_id', $service->id);
}
}
Now your query will be
Service::with(['contacts', 'locations.datetimes' =>function($q) use($serviceId){
$q->serviceId($serviceId);
}])->find($service->id);
There is no way to pass argument to a relationship function. If you do its highly likely that you will run into the N+1 query problem.
I have a project with main table 'Qsos' and bunch of relations. Now when I try to create advanced search I don't really know how to query all relations at the same time. Qso model has following:
public function band()
{
return $this->belongsTo('Band');
}
public function mode()
{
return $this->belongsTo('Mode');
}
public function prefixes()
{
return $this->belongsToMany('Prefix');
}
public function user()
{
return $this->belongsTo('User');
}
public function customization() {
return $this->hasOne('Customization');
}
Then I have SearchController with following code that has to return collection of all Qsos following required conditions:
$qsos = Qso::withUser($currentUser->id)
->join('prefix_qso','qsos.id','=','prefix_qso.qso_id')
->join('prefixes','prefixes.id','=','prefix_qso.prefix_id')
->where('prefixes.territory','like',$qTerritory)
->withBand($qBand)
->withMode($qMode)
->where('call','like','%'.$input['qCall'].'%')
->orderBy('qsos.id','DESC')
->paginate('20');
And then in view I need to call $qso->prefixes->first() and $qso->prefixes->last() (Qso and Prefix has manyToMany relation) but both return null. What is wrong?
Here is the eloquent code that I found working but taking VERY long time to process:
$qsos = Qso::withUser($currentUser->id)
->with('prefixes')
->withBand($qBand)
->withMode($qMode)
->where('call','like','%'.$input['qCall'].'%')
->whereHas('prefixes', function($q) use ($qTerritory) {
$q->where('territory','like',$qTerritory);
})
->orderBy('qsos.id','DESC')
->paginate('20');
hi sorry bit of a newbie here but I am have three tables users, profiles, friends. they all have the user_id fields within them and I want fetch all of the fields in one statement using Eloquent and not DB::statement and doing the table joins.
How can I achieve this?
Try this
use the User class and the with method that laravel has to query model relationships
$user = User::with(['profile', 'friend'])->get();
Ensure your models has the correct relationships as follows:
app/models/User.php
public function friend () {
return $this->hasMany('Friend');
}
public function profile () {
return $this->hasOne('Profile');
}
app/models/Profile.php
public function user() {
return $this->belongsTo('User');
}
app/models/Friend.php
public function user() {
return $this->belongsTo('User');
}
use some thing like this:
You should define relations in your models with hasOne, hasMany.
class Review extends Eloquent {
public function relatedGallery()
{
$this->hasOne('Gallery', 'foreign_id', 'local_id');
}
}
class Gallery extends Eloquent {
public function relatedReviews()
{
$this->hasMany('Review', 'foreign_id', 'local_id');
}
}
$gallery = Gallery::with('relatedReviews')->find($id);
Will bring the object Gallery with
$gallery->id
gallery->name
...
$gallery->relatedReviews // array containing the related Review Objects