Duplicating a nested set of folders in bash/fish - bash

Question

I have a folder full of other folders. Within each of these folders, there also exists another folder that I want to duplicate, but with a new name (same for all copies).
For example:
├── application
│   └── foo
│ └── bar
│   └── redacted.txt
│
├── something_different
│   └── foo
│ └── bar
│   └── RobotoMono.ttf
So every top level folder has a "foo/bar/" folder. I'd like to clone the "bar" folder (and the contents) so there is a "bar2" folder under each "foo" folder.
Then it would look like this:
├── application
│ └── foo
│ └── bar
│ └── redacted.txt
│ └── bar2
│ └── redacted.txt
│
├── something_different
│ └── foo
│ └── bar
│ └── RobotoMono.ttf
│ └── bar2
│ └── RobotoMono.ttf
I can successfully get the list with "find". Here is what I have tried:
find . -name bar -exec cp -r '{}' '{}'/bar2 \;
find . -name bar | xargs cp -r /bar2
And of course theses don't work and leave some nice looping that was fun to clean up. Thank you for reading and explaining what I'm doing incorrectly, or if I'm even close to what I should be doing.

Answer 1

First of all the single quotes around the parentheses will give you a string not the actual target (the directory) that you want. Removing these and copying to one level above "bar" seems to work (bash):
#> mkdir -p application/foo/bar && touch application/foo/bar/redacted.txt
#> find application -name bar -exec cp -r {} {}/../bar2 \;
#> ls -l application/foo/ | awk '{ print $NF }'
./
../
bar/
bar2/
#> ls -l application/foo/bar2/ | awk '{ print $NF }'
./
../
redacted.txt

Answer 2

find . \
-path '.*/foo/bar' \
-type d \
-exec sh -c 'p="${0%/*}"; n="${0##*/}"; cp -rp -- "$p/$n" "$p/${n}2"' {} \;
-exec sh -c Executes the inline shell script
Here is the content of the inline shell script with added comments:
# Extract the path before /bar from argument 0
p="${0%/*}"
# Extract the trailing name bar or anything else from argument 0
n="${0##*/}"
# Perform a recursive copy with preserved permissions
# from the source to the destination with suffix2
cp -rp -- "$p/$n" "$p/${n}2"