I'm developing a big hugo template. I try to simplfy the problem, so I have two datafile:
PROMO_00_1.yaml
PROMO_00_2.yaml
that are phisically stored in this directory:
themes/data/hp/
So, in the site config the user will decide which of this data file will be used simply indicate it in a param (HpElement).
In the template I call the partial in this way:
{{ partial "multiplepages/homepage/promos/00_promo_singleslide_text_video" (dict "context" . "data" $.Site.Params.HpElement) }}
In a partial I write:
{{ $data_partial := (printf "$.Site.Data.homepage.%s" .data)}}
{{ $data_partial}}
and the Hugo output is on the website:
$.Site.Data.homepage.PROMO_00_1
What I need is to access the single variable inside the .yaml file but the user MUST can decide which YAML file have to use. How can I achieve that?
Thanks
I just finished up a similar use case where I needed to select a YAML based on a date stamp. The index function is key to this operation.
https://gohugo.io/functions/index-function/
Here is a simplified version of my situation:
{{ $date := now.Format "s20060102"}}
{{ $data := (index .Site.Data.schedule $date) }}
{{ with $data }}
<h1>.longdate</h1>
{{ range .times }}
<h2>{{ .name }} - {{ .location }}
{{ end}
{{ end}
The example in the Hugo documentation uses an example where the data file is selected based on an attribute in the front matter.
Related
So I am making a review carousel using Bootstrap and Hugo, I've got code that breaks down into this:
{{ range seq 1 3 (len site.Data.reviews) }}
...
{{ range seq . (add . 2) }}
{{ with (index site.Data.reviews (string .)) }}
{{ .des }}
{{ end }}
{{ end }}
...
{{ end }}
So there's two loops, one to make the slides for the carousel, and the other to fill the slides with data files. The issue is I need to delete the active class and adjust the data-bs-interval input on the next few slides I thought about making an if statement but I'm not sure how to replace the first div with one that doesn't have the active class after that in whats generated.
I don't know if this is the best solution to it, instead of editing the loop I wrote a bit of javascript:
var addActive = document.getElementById('carouselExampleDark').getElementsByClassName('carousel-item')[0];
addActive.classList.add("active");
That works for my use case so I'll leave it at that.
I am writing a layout template for a Hugo generated post/page. The .yaml header is
image:
- post/mytitle/image.jpg
The template incorporates the variable in Hugo as
{{ .Params.Image }}
When served, the variable is returned as
[post/mytitle/image.jpg]
My html then becomes
<img src="[post/mytitle/image.jpg]"/>
which is 404 in the browser. I've tried a number of Hugo functions to no avail like {{ trim .Param.Image "[]" }} and {{ subset .Params.Image 1 -1 }} and {{ print .Params.Image }}. Each time Hugo returned the error: "error calling substr: unable to cast []string{"post/mytitle/image.jpg"} of type []string to string".
How do I get the variable to return the string without the brackets, or alternatively, how do I omit the brackets from the string?
In Go template, you access an item in a slice with index:
{{ index .Params.Image 0 }}
The question is why the value is a sequence in the first place. You could simply do
image:
post/mytitle/image.jpg
Then you could keep the original syntax since it is now a simple value, not a sequence.
If you want to possibly include multiple images, you'd do
{{ range .Params.Image }}<img src="{{.}}">{{ end }}
Then you can have
image:
- post/mytitle/image.jpg
- post/mytitle/anotherimage.jpg
I need to write a template where I first define some variables, and then use them in what will be generated from the template:
{{ if $value.Env.CADDY_URL }}
{{ $url := $value.Env.CADDY_URL }}
{{ else }}
{{ $url := printf "http://%s.example.info" $value.Name }}
{{ end }}
{{/* more template */}}
{{/* and here I would like to use $url defined above */}}
{{ $url }}
I get the error
undefined variable "$url"
Reading the documentation, I see that
A variable's scope extends to the "end" action of the control structure ("if", "with", or "range") in which it is declared, or to the end of the template if there is no such control structure.
Does this mean that there are no global (or scoped on the whole template) variables? Or is there a way to define $url so that it can be reused later in the template?
Variables are scoped. You create the $url variable inside the {{if}} and {{else}} blocks, so they are not visible outside of those blocks.
Create the variable before the {{if}}, and use assignment = instead of declaration :=:
{{$url := ""}}
{{ if . }}
{{ $url = "http://true.com" }}
{{ else }}
{{ $url = "http://false.com" }}
{{ end }}
{{ $url }}
Testing it:
t := template.Must(template.New("").Parse(src))
fmt.Println(t.Execute(os.Stdout, true))
fmt.Println(t.Execute(os.Stdout, false))
Output (try it on the Go Playground):
http://true.com<nil>
http://false.com<nil>
Note: Modifying template variables with assignment was added in Go 1.11, so you need to build your app with Go 1.11 or newer. If you're using an older version, you cannot modify values of template variables.
Edit: I've found a duplicate: How do I assign variables within a conditional
You can mimic "changeable template variables" in earlier versions, see this question for examples: In a Go template range loop, are variables declared outside the loop reset on each iteration?
I am new in Laravel and I am working on inbuilt project I have got {{ trans(core.text) }} after browse on internet I find that trans is a helper but I am not getting any file. So, Any one explain what does the line meaning {{ trans(core.text) }}.
Thank You
The trans function translates the given translation key using your localization files:
echo trans('messages.welcome');
If the specified translation key does not exist, the trans function will return the given key.
Link : https://laravel.com/docs/master/helpers
I have a question about how to order a map by a slice in Go Templates and if it is possible.
Problem: I have a slice of ordered variable names that I want to display on a website, accompanying them I have a map of metadata of variable information that I would like to display together with the variable.
If I have the following struct that I pass in to the template:
type Data struct {
Variables []string
Information map[string]int
}
I would iterate over the slice and pass the variable name in to the map
{{ range $v := .Variables }} {{ index .Information $v }} {{ end }} // Doesn't work.
Here's a Go Playground with the example.
https://play.golang.org/p/AL2csnXdoU
Question: How can I do this?
I am fairly new to Golang. Thankful for any input.
The following should work. To access .Information inside range, you should use $, which is basically d in your Playground example.
{{ range .Variables }} {{ index $.Information . }} {{ end }}