Signal assignment method - vhdl

Question

I am new to VHDL and have had some difficulty in performing the assignment of two different values to the same signal inside a process. For example,
process(CLK)
if rising_edge(CLK) then
OUTPUT0 <= X(0);
OUTPUT1 <= X(1);
OUTPUT2 <= X(2);
LED0 <= VALUE;
OUTPUT0 <= Y(0);
OUTPUT1 <= Y(1);
OUTPUT2 <= Y(2);
LED1 <= VALUE;
end if;
end process;
Note that VALUE is an output dependent on the values assigned to OUTPUT0, OUTPUT1, OUTPUT2.
From what I understand in a process is that the last assignment to the same signal is always applied. What I am trying to do is apply two different sets of values to one set of inputs, map the output and it be done sequentially. I have tried separate processes tied to the same clock, a FSM to attempt to move sequentially and so on. At this point I have exhausted my knowledge of things to try.
My question is: What would be the best way to sequentially assign two values to one input and map its output in order?
EDIT:
As per Brian's suggestion on the state machine I had went ahead and implemented one again and found my error and fixed it. This gave the sequential assignment I was looking for.
I was reading 2 addresses from one instance of 32x1 distributed RAM which is the reason for a sequential assignment. Apologies for not providing the best example. Below is my final implementation:
RAM_READ_FSM : process(CLOCK) -- FSM to read the RAM addresses sequentially
begin
if rising_edge(CLOCK) then
case curr_state is
when S0 => if SW2 = '1' then
RAMADDR0 <= XYVEC(5); -- Y addresses
RAMADDR1 <= XYVEC(6);
RAMADDR2 <= XYVEC(7);
RAMADDR3 <= XYVEC(8);
RAMADDR4 <= XYVEC(9);
LED1 <= RAMOUT;
curr_state <= S1;
else
curr_state <= S0;
end if;
when S1 => if SW2 = '1' then
RAMADDR0 <= XYVEC(0); -- X addresses
RAMADDR1 <= XYVEC(1);
RAMADDR2 <= XYVEC(2);
RAMADDR3 <= XYVEC(3);
RAMADDR4 <= XYVEC(4);
LED2 <= RAMOUT;
curr_state <= S0;
else
curr_state <= S1;
end if;
end case;
end if;
end process;

Answer 1

The signals should be driven from the same process : multiple drivers would interfere with each other..
See Is process in VHDL reentrant? on signal assignment semantics.
now you can see there is need for some delay (even just 2 delta cycles, if the logic calculating VALUE is just a simple signal assignment) between the X and LED0 assignments.
You were on the right lines with a state machine but you didn't say anything about how it failed. Worth adding that to the Q to get a fuller answer.
Meanwhile there is a simple way to add delay :
like
LEDS : process is
begin
wait until rising_edge(CLK);
OUTPUT0 <= X(0);
OUTPUT1 <= X(1);
OUTPUT2 <= X(2);
wait until rising_edge(CLK);
LED0 <= VALUE;
wait until rising_edge(CLK);
OUTPUT0 <= Y(0);
-- etc
end process LEDS;