i use laravel 5.8 and i have a a problem if i insert or update a page than i go not back to the page list.
postcontroller :
i use : return response()->json('Post Created');
and i use a ajax file whit this code :
$.ajax({
type: 'POST',
url: this.action,
data: new FormData(this),
dataType: 'json',
contentType: false,
cache: false,
processData:false,
success: function(response){
Sweet('success',response)
success(response)
},
error: function(xhr, status, error)
{
$('.errorarea').show();
$.each(xhr.responseJSON.errors, function (key, item)
{
Sweet('error',item)
$("#errors").html("<li class='text-danger'>"+item+"</li>")
});
errosresponse(xhr, status, error);
}
})
});
i get a nice message if it is insert or updated but it not go back to my list, hope you understand what i mean.
if you want to redirect after success do something like this:
$.ajax({
type: 'POST',
url: this.action,
data: new FormData(this),
dataType: 'json',
contentType: false,
cache: false,
processData:false,
success: function(response){
Sweet('success',response)
success(response)
window.location.href = "url you want to redirect to";
},
error: function(xhr, status, error)
{
$('.errorarea').show();
$.each(xhr.responseJSON.errors, function (key, item)
{
Sweet('error',item)
$("#errors").html("<li class='text-danger'>"+item+"</li>")
});
errosresponse(xhr, status, error);
}
})
});
Related
To apply a command to an issue i'm using this code:
$.ajax({
async: false,
type: 'post',
url: "https://golaservices.myjetbrains.com/youtrack/rest/issue/"+e.target.id+"/execute"+"?command="+target.val(),
cache: "true",
dataType: "html"
});
but that brings up this error
You have no access to this resource. Try to log in.
that's why i tried putting that first bit of code like this:
$.ajax({
async: false,
type: 'post',
url: "https://golaservices.myjetbrains.com/youtrack/rest/user/login?login=xxx&password=123",
cache: "true",
dataType: "html",
success: function(output, status, xhr) {
alert(xhr.getResponseHeader('Set-Cookie'));
}
}).done(function (data) {
console.log("in done");
$.ajax({
async: false,
type: 'post',
url: "https://golaservices.myjetbrains.com/youtrack/rest/issue/"+e.target.id+"/execute"+"?command="+target.val(),
cache: "true",
dataType: "html"
});
console.log("after done");
});
but i still get the same error, any idea how to do this ?
/rest/user/login endpoint has been deprecated for a while already and is not recommended for further use. Try permanent tokens instead, they don't require any preflight login requests to be executed.
$.ajax({
type: "post",
url: "https://golaservices.myjetbrains.com/youtrack/rest/issue/" + e.target.id + "/execute" + "?command=" + target.val(),
dataType: "json"
beforeSend: function(xhr) { xhr.setRequestHeader("Authorization", "Bearer " + permanentToken); },
});
Here I am using Ajax+Mvc when I call my data from database it comes in Json format but how can I display that data in div?
Html
<div id="Div1">
</div>
<b>Get data</b><input type="button" id="BtnGetData" value="GetData" />
When user click on BtnGetData the data should be display in #Div1 Here my AJax working fine.But please suggest me where to write $('#Div1').load();
$('#BtnGetData').click(function () {
alert('ok data')
$.ajax({
url: '/Home/Getdata',
method: "GET",
type: "JSON",
contentType: 'application/json; charset=utf-8',
data: JSON.stringify(),
})
})
MvcController
public JsonResult Getdata()
{
var x = Objrepo.GetEmplo();
return new JsonResult { Data = x, JsonRequestBehavior = JsonRequestBehavior.AllowGet };
}
You can write to the div on the success function of your $.ajax call.
eg:
$('#BtnGetData').click(function () {
$.ajax({
url: '/Home/Getdata',
method: "GET",
type: "JSON",
contentType: 'application/json; charset=utf-8',
data: JSON.stringify(),
success: function (data) {
console.log(data);
}
})
});
You need to add a success callback to your ajax:
$('#BtnGetData').click(function () {
alert('ok data')
$.ajax({
url: '/Home/Getdata',
method: "GET",
type: "JSON",
contentType: 'application/json; charset=utf-8',
success: function(data){
$("#Div1").append(data);
}
})
})
There is no need to add the data property to the ajax if your are not sending anything.
May be, you can add this function in your script.
$('#BtnGetData').click(function () {
alert('ok data')
$.ajax({
url: '/Home/Getdata',
method: "GET",
type: "JSON",
contentType: 'application/json; charset=utf-8',
data: JSON.stringify(),
writeResponse(data)
})
});
writeResponse(data){
$("Div1").html(data);
};
Hello guys i have the next ajax call for login. I serialize the form and send the data to server and return redirect url link. My problem is that my url after post is like
http://localhost:50802/?username=&password= and not http://localhost:50802/Home
$.ajax({
type: "POST",
url: "Login/Login",
dataType: 'json',
contentType: "application/json; charset=utf-8",
data: loginJson,
cache: true,
async: false,
complete: function (result) {
alert(result.link);
window.location.replace = "/Home/Index";
},
error: function () {
$("#username").val("");
$("#password").val("");
alert("Wrong Username or Password!");
}
}); //end ajax call
It looks like you wrote this $.ajax call in the .click event of a submit button or in the .submit event of a form without canceling the default action by returning false from the callback or by calling preventDefault on the argument. Here's how your code should look like:
$('#id_of_your_form').submit(function(e) {
e.preventdefault(); // <-- That's what I am talking about and what you forgot
$.ajax({
type: "POST",
url: "Login/Login",
dataType: 'json',
contentType: "application/json; charset=utf-8",
data: loginJson,
cache: true,
async: false,
complete: function (result) {
window.location.replace = "/Home/Index";
},
error: function () {
$("#username").val("");
$("#password").val("");
alert("Wrong Username or Password!");
}
}); //end ajax call
});
Also async: false,????? You know what this does, do you? That's not AJAX. That's a blocking synchronous call to your webserver during which the client browser would be frozen like during the Ice Age 2 ruining all user experience.
Try returning false at the end of your submit function
$('#id_of_your_form').submit(function(e) {
$.ajax({
type: "POST",
url: "Login/Login",
dataType: 'json',
contentType: "application/json; charset=utf-8",
data: loginJson,
cache: true,
async: false,
complete: function (result) {
window.location = "/Home/Index";
},
error: function () {
$("#username").val("");
$("#password").val("");
alert("Wrong Username or Password!");
}
}); //end ajax call
return false; });
Another option would of course be to return the correct redirectlink from the controller instead of overriding it in the java script.
$.ajax({
type: 'GET',
url: 'http://api.xhanch.com/islamic-get-prayer-time.php?lng=34.4366455078125&lat=31.48957771850194&yy=2013&mm=5&gmt=3&m=json',
dataType: 'jsonp',
success: function () {
console.log('Success!');
},
error: function () {
console.log('Uh Oh!');
},
jsonp: 'jsonp'
});
when I run this code I get an error in the return json object
Uncaught SyntaxError: Unexpected token:
Why?
The problem is jsonp: 'jsonp' is calling the method jsonp that doesn't exist in your code. If you really need this, just create the method or remove it.
Remove
$.ajax({
type: 'GET',
url: 'http://api.xhanch.com/islamic-get-prayer-time.php?lng=34.4366455078125&lat=31.48957771850194&yy=2013&mm=5&gmt=3&m=json',
dataType: 'jsonp',
success: function () {
console.log('Success!');
},
error: function () {
console.log('Uh Oh!');
},
});
Or create the method
$.ajax({
type: 'GET',
url: 'http://api.xhanch.com/islamic-get-prayer-time.php?lng=34.4366455078125&lat=31.48957771850194&yy=2013&mm=5&gmt=3&m=json',
dataType: 'jsonp',
success: function () {
console.log('Success!');
},
error: function () {
console.log('Uh Oh!');
},
jsonp: { jsonp: false, jsonpCallback: "callbackName" }
});
function callbackName(){
/*do something*/
}
Reference: http://api.jquery.com/jQuery.ajax/
jsonp
Type: String Override the callback function name in a jsonp request.
This value will be used instead of 'callback' in the 'callback=?' part
of the query string in the url. So {jsonp:'onJSONPLoad'} would result
in 'onJSONPLoad=?' passed to the server. As of jQuery 1.5, setting the
jsonp option to false prevents jQuery from adding the "?callback"
string to the URL or attempting to use "=?" for transformation. In
this case, you should also explicitly set the jsonpCallback setting.
For example, { jsonp: false, jsonpCallback: "callbackName" }
want to get response from url using ajax and jquery.
tried with this code
$(document).ready(function () {
$.ajax({
type: 'POST',
url: 'apexweb.co.in/apex_quote/uname_validation.asp?,
dataType:'jsonp',
success: function(data){
alert(data);
}
});
});
i want to display response as fail but i didn't get any response on browser
Help Me
Try this
$(document).ready(function () {
$.ajax({
type: "POST",
url: "apexweb.co.in/apex_quote/uname_validation.asp?",
contentType: "application/json; charset=utf-8",
dataType: "jsonp",
success: function (data) {
alert(data.d);
},
failure: function (data) {
alert(data.d);
}
});
});