Go regExRepl-Script does not change the text file - go

Question

my go script should add one newline before matching the regEx-Search-String ^(.+[,]+\n).
The Prototype i had tested before into the editor:
i want add newlines before this lines: \n$1.
This works if i try it into the Text-Editor.
If i try this (see line 24) with my script it is changing nothing and sends no error.
Any ideas what i do wrong?
Example
i like to use PCRE like it works in this Example https://regex101.com/r/sB9wW6/17
Same Example here:
Example source
Dear sir,
Thanks for your interest.
expected result
#### here is a newline ####
Dear sir,
Thanks for your interest.
result is (produced by the script below)
Dear sir,
Thanks for your interest.
go script:
// replace in files and store the new copy of it.
package main
import (
"fmt"
"io/ioutil"
"os"
"path/filepath"
"regexp"
"strings"
"time"
)
func visit(path string, fi os.FileInfo, err error) error {
matched, err := filepath.Match("*.csv", fi.Name())
if err != nil {
panic(err)
return err
}
if matched {
read, err := ioutil.ReadFile(path)
if err != nil {
panic(err)
}
newContents := string(read)
newContents = regExRepl(`^(.+[,]+\n)`, newContents, `\n\n\n$1`)
var re = regexp.MustCompile(`[\W]+`)
t_yymmdd := regexp.MustCompile(`[\W]+`).ReplaceAllString(time.Now().Format(time.RFC3339), `-`)[:10]
t_hhss := re.ReplaceAllString(time.Now().Format(time.RFC3339), `-`)[11:19]
t_yymmddhhss := t_yymmdd + "_" + t_hhss
fmt.Println(t_yymmddhhss)
filePath := fileNameWithoutExtension(path) + t_yymmddhhss + ".csv"
err = ioutil.WriteFile(filePath, []byte(newContents), 0)
if err != nil {
panic(err)
}
}
return nil
}
func regExRepl(regExPatt string, newContents string, regExRepl string) string {
return regexp.MustCompile(regExPatt).ReplaceAllString(newContents, regExRepl)
}
func main() {
err := filepath.Walk("./november2020messages.csv", visit) // <== read all files in current folder 20:12:06 22:44:42
if err != nil {
panic(err)
}
}
func fileNameWithoutExtension(fileName string) string {
return strings.TrimSuffix(fileName, filepath.Ext(fileName))
}

Answer 1

for interpretation \n as newline don't us
`\n`` use "\n"
may use ^(.+[,]+) instead ^(.+[,]+\n) and ad (?m) before for multi-line replacements
this suggestion you could test here: https://play.golang.org/p/25_0GJ93oCT
The following example illustrates the difference (in golang-playground here https://play.golang.org/p/FkPwElhx-Xu ):
// example from:
package main
import (
"fmt"
"regexp"
)
func main() {
newContents := `line 1,
line 2
line a,
line b`
newContents1 := regexp.MustCompile(`^(.+[,]+\n)`).ReplaceAllString(newContents, `\n$1`)
fmt.Println("hi\n" + newContents1)
newContents1 = regexp.MustCompile(`(?m)^(.+[,]+\n)`).ReplaceAllString(newContents, "\n$1")
fmt.Println("ho\n" + newContents1)
}
Result:
hi
\nline 1,
line 2
line a,
line b
ho
line 1,
line 2
line a,
line b