Codeigniter 4 Passing Array to view - codeigniter

Fairly new to codeigniter and i just cant find the right way to load an array into a view.
for example lets say i have an array like
$data = [
'title' => 'my title,
'desc' => 'my desc,
];
i can pass that to my view like
return view('myview',$data);
then simply echo it out in my view like
<h1><?= $title ?></h1>
<p><?= $desc ?></p>
That works fine. but now lets say i have another array like :
$moredata =[
'more_data' => 'some more data',
'even_more_data' => 'even more data',
];
if i try to add that to my data array like
$data[] = $moredata
when i try to access 'more_data' or 'even_more_data' in my view like
<?= $more_data ?>
i get a undefined variable error for $moredata. So how do i access the variables within that new array? am i declaring them properly?
also if i wanted to loop through the secondary array how do i do that. trying
<?php foreach($moredata as $items){ ?>
<li><?php echo $items; ?></li>
<?php } ?>
also gives me an undefined variable error for $moredata
any help on how to do this correctly in codeigniter 4 appreciated.

Codeigniter uses the key of the array you're giving him to create variables name.
You should init it this way :
$moredata =[
'more_data' => 'some more data',
'even_more_data' => 'even more data',
];
// key of your array will be a variable name in your view
$data['my_var_name_in_view'] = $moredata
return view('myview',$data);
Then in your view you will be able to perform this :
<?php foreach($my_var_name_in_view as $items){ ?>
<li><?php echo $items; ?></li>
<?php } ?>

Related

Yii2 dropDownList get selected value

I have dropDownList in my view ( data from db) :
use yii\widgets\ActiveForm;
\app\assets\HelloAsset::register($this);
$form = ActiveForm::begin();
$users=\app\models\User::find()->all();
$items=\yii\helpers\ArrayHelper::map($users,'id','username');
echo $form->field($model, 'username')->dropDownList($items);
echo \yii\bootstrap\Html::submitButton('Send');
ActiveForm::end();
I want to get data from 'username' in my controller:
$model=new Data();
if ($model->load(\Yii::$app->request->post())){
echo 'it is status:'.$model->username;
}else {
return $this->render('simple', ['model' => $model]);
}
But data is null.
How I must get data in right?
Please, help me solve this problem.

Yii2 update related model makes insert

Depending on this question: Yii2 updating two related models does not show data of the second. I have manged calling the related model InvoiceItems to the Invoices model it hasMany relation.
However, updating leads to insert new records in invoice_items table instead of updating the current related records to the invoices table.
I tried to add the id field of each InvoiceItems record in the _form view to solve this issue, but it still exist.
The following is actionUpdate of the InvoicesController:
public function actionUpdate($id)
{
$model = $this->findModel($id);
//$invoiceItems = new InvoiceItems();
$count = count(Yii::$app->request->post('InvoiceItems', []));
//Send at least one model to the form
$invoiceItems = [new InvoiceItems()];
//Create an array of the products submitted
for($i = 1; $i < $count; $i++) {
$invoiceItems[] = new InvoiceItems();
}
if ($model->load(Yii::$app->request->post()) && $model->save()) {
//$invoiceItems->invoice_id = $model->id;
if (Model::loadMultiple($invoiceItems, Yii::$app->request->post())){
foreach ($invoiceItems as $item){
$item->invoice_id = $model->id;
//$item->id = $model->invoiceItems->id;
$item->save(false);
}
return $this->redirect(['view', 'id' => $model->id]);
}
else{
return var_dump($invoiceItems);
}
} else {
//$invoiceItems->invoice_id = $model->id;
$invoiceItems = $this->findInvoiceItemsModel($model->id);
return $this->render('update', [
'model' => $model,
'invoiceItems' => $invoiceItems,
]);
}
}
This is the code of _form view of InvoicesController:
<div class="invoices-form">
<?php $form = ActiveForm::begin(); ?>
<?= $form->field($model, 'created')->textInput() ?>
<?= $form->field($model, 'type')->textInput(['maxlength' => true]) ?>
<hr />
<?php if (is_array($invoiceItems)): ?>
<?php foreach ($invoiceItems as $i => $item): ?>
<?= $form->field($item, "[$i]id")->textInput();?>
<?= $form->field($item, "[$i]item_id")->textInput();?>
<?= $form->field($item, "[$i]unit_id")->textInput();?>
<?= $form->field($item, "[$i]qty")->textInput();?>
<?php endforeach; ?>
<?php else: ?>
<?= $form->field($invoiceItems, "item_id")->textInput();?>
<?= $form->field($invoiceItems, "unit_id")->textInput();?>
<?= $form->field($invoiceItems, "qty")->textInput();?>
<?php endif; ?>
<div class="form-group">
<?= Html::submitButton($model->isNewRecord ? Yii::t('app', 'Create') : Yii::t('app', 'Update'), ['class' => $model->isNewRecord ? 'btn btn-success' : 'btn btn-primary']) ?>
</div>
<?php ActiveForm::end(); ?>
</div>
The following screen shot, visually, demonstrates what I have got:
if you in update you don't need new record you should remove
this part
$count = count(Yii::$app->request->post('InvoiceItems', []));
//Send at least one model to the form
$invoiceItems = [new InvoiceItems()];
//Create an array of the products submitted
for($i = 1; $i < $count; $i++) {
$invoiceItems[] = new InvoiceItems();
}
The $invoiceItems you create in this way are obviuosly "new" and then are inserted ..for an update the model must to be not new..
You have already the related models to save they came from post.. and from load multiple
If you however need to manage new model (eg: because you added new record in wide form update operation) you can test
$yourModel->isNewRecord
and if this is new check then if the user have setted properly the related fields you can save it with
$yourModel->save();
otherwise you can simple discart.. (not saving it)
I am pretty sure that this code below of course fills a array named $invoiceItems with the submitted data.
if (Model::loadMultiple($invoiceItems, Yii::$app->request->post())){
foreach ($invoiceItems as $item){
$item->invoice_id = $model->id;
//$item->id = $model->invoiceItems->id;
$item->save(false);
}
}
But all $items have the scenario "insert" (could be that you allow the setting of the attribute 'ID' but normally this isn't allowed in the Gii generated code. and then you get "new items" whenever you save.
if you add a return var_dump($invoiceItems);after the loadMultiple you will see that only the safe attributes are filled with the submitted data.
You are also not validating them before saving, which is also kind of bad.
if (Model::loadMultiple($invoiceItems, Yii::$app->request->post()) && Model::validateMultiple($invoiceItems)) {
http://www.yiiframework.com/doc-2.0/guide-input-tabular-input.html
According to scaisEdge answer and this widget documentation. I could able to determine the problem solution.
Simply, in my code I neglected the relation between the two models, when I say:
$count = count(Yii::$app->request->post('InvoiceItems', []));
//Send at least one model to the form
$invoiceItems = [new InvoiceItems()];
The value of $invoiceItems should be obtained using the relation like the following:
$invoiceItems = $model->invoiceItems;
However, I still have another issue with adding new records to the related model InvoiceItems during the update.

Dependanat Drop down is not working when it has only one value in yii framework

I am using dependant dropdownlist for get value for subject dropdown when select value from 'Grade' dropdown. It is working fine. But the problem is when there are only one value in grade dropdown the subject dropdown is not updated.
this is my code:-
Grade DropDown----------
($data is consist of grade)
<?php echo CHtml::dropDownList('myDropDown1','',$data,array(
'id'=>'gr',
'empty' => '(Select Grade)',
'style'=>'width:200px',
'ajax' =>
array(
'type'=>'POST', //request type
'url'=>CController::createUrl('sub'), //action to call
'update'=>'#cls', // which HTML element to update
)
)); ?>
Subject Dropdown (which depend on grade dropdown)------------
<?php echo CHtml::label('Subject',''); ?>
<?php echo CHtml::dropDownList('myDropDown3','',array(),array(
'id'=>'sub',
'prompt'=> 'Please select a class', 'style'=>'width:150px',
'style'=>'width:200px',
)); ?>
<?php //echo $form->error($model,'sub_id'); ?>
In controller-------------------
public function actionClass()
{
$grd = $_POST['myDropDown1'];
$c_id = TbClass::model()->findAll('id=:id',
array(':id'=>$grd,));
$data3 = CHtml::listData($c_id,'id','grade');
$grd2 = array_shift($data3);
$sub1 = TbClass::model()->findAll('grade=:grade',
array(
':grade'=>$grd2,
));
$data4 = CHtml::listData($sub1,'id','class');
foreach($data4 as $value=>$name)
{
echo CHtml::tag('option',
array('value'=>$value),CHtml::encode($name),true);
}
}
This code is working fine. Problem is when grade has only one value in the dropdown , cannot update the subject dropdown.
I think your problem is in array_shift,
have you checked the value of $grd2 ?

Data through controller - view in CodeIgniter

I have this snippet code in my Controller:
// load model
$this->load->model('article');
$data['article'] = $this->article->get_data_article();
// add more array in data['article']
$data['article'][] = array( 'newcontent' => 'dummy string' );
$this->load->view('index',$data);
then I have 2 views, first is index.php:
$this->load->view('content',$article[0]);
second view is content.php:
<?php echo $title;?> <br>
<?php echo $newcontent;?>
I've got error on second line above. The error message is:
Severity: Notice
Message: Undefined variable: newcontent
Filename: views/content.php
What's wrong with my code?
You have to display like this,
echo $article[0]['newcontent'];
Because you have created it as a two dimensional Array.
This is the right way to do it.
$data['article']['article1'] = array( 'newcontent' => 'dummy string' );
$data['article']['article2'] = $this->article->get_data_article();
And in view
echo '<pre>';
print_R($article1);
echo '<pre>';
print_R($article2);
Now you can access. Numeric arrays cause problem passing data to views. Use indexed arrays.
EDITS :
You can pass it to view like this
$this->load->view('content',$data);
And in the view now you have $article.
echo '<pre>';
print_R($article);
if you apply php extract on article
extract($article);
You will be able to access
echo '<pre>';
print_R($article1);
echo '<pre>';
print_R($article2);
But the each way is to do that
Controller
$data['article1'] = array( 'newcontent' => 'dummy string' );
$data['article2'] = $this->article->get_data_article();
Pass it to view
$this->load->view('content',$data);
and access like this
echo '<pre>';
print_r($article1);
echo '<pre>';
print_r($article2);
No extraction required
More EDITS:
You can do it like this
$result['article1'] = array( 'newcontent' => 'dummy string' );
$this->load->view('content',$result);
$result1['article2'] = $this->article->get_data_article();
$this->load->view('index',$result1);

Codeigniter and Tank_auth sending validation to view not working

Hi I am new to Codeigniter but have hit a brick wall.
I am trying to see if a user already exists.
First I upload the data via a form to a controller which does its validation etc but breaks on only that issue. I managed to find where it breaks but cant fix it from there.
Prior to all this it querys the database finds there is in fact a match username and then reaches the snippet below
$errors = $this->tank_auth->get_error_message();
//find the correct error msg
foreach ($errors as $k => $v) $data['errors'][$k] =$this->lang->line($v);
//loop and find etc
$temp_mess = $data['errors'][$k];
//stores relevant stuff in the string
}
}
//echo $temp_mess; it outputs to the html so i can see it "says user exists"
$data['temp_mess'] = $tempmess; /// put this into a array
$this->load->view('layout', $data); ///send
}
}
Now for the view, it then calls the layout view etc but alas there is no output
$username1 = array(
'name' => 'username1',
'id' => 'username1',
'value' => set_value('username1'),
'maxlength' => $this->config->item('username_max_length', 'tank_auth'),
'size' => 30,
);
<?php echo form_open('register', $form_reg_id ); ?>
<fieldset>
<legend align="center">Sign up</legend>
<?php echo form_label('Username', $username1['id']); ?>
<?php echo form_input($username1); ?>
<?php $tempmess; ?>
<div class="error"><?php echo form_error($username1['name']); ?>
<?php echo isset($errors[$username1['name']])?$errors[$username1['name']]:''; ?>
<?php echo form_close(); ?>
</fieldset>
Thanks for any help on this
also could some one explain this line please. (for a really dumb person)
<?php echo isset($errors[$username1['name']])?$errors[$username1['name']]:''; ?>
Tank_auth automatically returns an error when the username exists. Juste have to check the errors array.

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