chmod +x cant find build.sh file - bash

I have been trying to make a VCS in C++ but the build file is not running in my LINUX(Ubuntu).
It is prompting the above message.
my build file is as follows:
#!/bin/bash
sudo apt-get update
udo apt-get install openssl -y
sudo apt-get install libssl-dev -y
mkdir -p ~/imperium/bin
cp imperium.sh ~/imperium
cd ..
make
cd ~/imperium/bin || echo "error"
chmod +x main
cd ..
if grep -q "source $PWD/imperium.sh" "$PWD/../.bashrc" ; then
echo 'already installed bash source';
else
echo "source $PWD/imperium.sh" >> ~/.bashrc;
fi
my imperium.sh file is also as follows:
function imperium(){
DIR=$PWD
export dir=$DIR
cd ~/imperium/bin || echo "Error"
./main "$#"
cd "$DIR" || echo "Error"
}
I will be heavily obliged if any one can solve this problem of mine. After chmod I have been doing:
./build.sh but its prompting that build.sh file does not exists.

For me it seems you have a typo right in the 3rd row "udo" ->
"sudo".
Also, You should avoid using cd .. and use relative paths for
the commands.

Related

Bash Script with Several Nested elif Statements Not Working

I am trying to create a script I can provide to those who will use an academic game I am making. I am trying to do the following:
Verify that Apache2 is installed and Running
If Apache2 is installed, move a folder containing the website files to /var/www/html while backing up apache's original index.html
The code is as follows:
#!/bin/sh
acm=[]
cnn=[]
gnu=[]
ieee=[]
if [pgrep -x "apache2" > /dev/null]; then
echo "Apache 2 Installed and Running!"
if [ -d "$HOME/acmDL" ]; then
sudo mkdir /var/www/bak
sudo mv /var/www/html/index.html /var/www/bak
sudo mv acmDL /var/www/html/
cd /var/www/html/
sudo mv acmDL/* .
exit
elif [ -d "$HOME/cnnDL" ]; then
sudo mkdir /var/www/bak
sudo mv /var/www/html/index.html /var/www/bak
sudo mv cnnDL /var/www/html/
cd /var/www/html/
sudo mv cnnDL/* .
exit
elif [ -d "$HOME/gnuDL" ]; then
sudo mkdir /var/www/bak
sudo mv /var/www/html/index.html /var/www/bak
sudo mv gnuDL /var/www/html/
cd /var/www/html/
sudo mv gnuDL/* .
exit
elif [ -d "$HOME/ieeeDL" ]; then
sudo mkdir /var/www/bak
sudo mv /var/www/html/index.html /var/www/bak
sudo mv ieeeDL /var/www/html/
cd /var/www/html/
sudo mv ieeeDL/* .
exit
else
echo "Provided websites not found... Are you using a custom website?"
fi
else
echo "Please check apache2... It may not have installed correctly"
fi
The error I keep getting is syntax error near unexpected token `elif' on line 15.
As you can see, I even tried moving the boolean expression [ - d "$HOME/site" ] to their own variables, but then the error becomes : -d: command not found and the error on line 15.
Is what I am trying to do impossible, or am I missing something undocumented and yet completely obvious (like a handful of my previous posts)?
This is being run on a minimal installation of Ubuntu 18 on a Virtual Machine. The site directories are shared by Filezilla. Script written in Notepad++ on Windows 7 x64.
First of all, can you rewrite it like this?
Please tell me the execution result.
This is wrong.
if [pgrep -x "apache2" > /dev/null]; then
This is correct.
pgrep -x "apache2" > /dev/null
if [ $? -eq 0 ]; then

sh script to build from source Ubuntu

Im trying to automate some dependency installing from an sh script, however, I feel that not all commands are getting through.
Here is an example:
#!/bin/sh
cd /Downloads
sudo wget https://github.com/tpaviot/oce/archive/OCE-0.16.1.tar.gz
sudo tar -xvf OCE-0.16.1.tar.gz
cd oce-OCE-0.16.1/
sudo mkdir build
cd build
sudo cmake ../
sudo make
sudo make install/strip
Is this valid in a .sh script?

basic BASH variable call failing in script

Why is this basic variable call in my script failing?
The script is just below and the errors outputted in terminal after execution are below the script.
Line 8 is the first sudo command.
I am executing this script as root in terminal for now. It works just fine if I execute the commands manually, one-at-a-time, within terminal...
I would be grateful for any insight.
#!/bin/bash
echo Enter username
read NAME
echo Enter number
read NUM
sudo (cd /Users/$NAME && tar c .) | (cd /Users/$NUM && tar xf -)
sudo chown -R $NUM:"Domain Users" /Users/$NUM
sudo chmod g+rwx /Users/$NUM
Stephen-Kucker:Desktop root# ./stackoverflowq.txt
Enter username
jsteinberg-c
Enter number
admin
./stackoverflowq.txt: line 8: syntax error near unexpected token `cd'
./stackoverflowq.txt: line 8: `sudo (cd /Users/$NAME && tar c .) | (cd /Users/$NUM && tar xf -)'
Try this:
sudo tar -C /Users/$NAME -c . | sudo tar -C /Users/$NUM -xf -
You need to use the -s option to pass an arbitrary shell command (like the pipeline shown) to the shell with sudo:
sudo -s "(cd /Users/$NAME && tar c .) | (cd /Users/$NUM && tar xf -)"

Unable to install parse.com command line tool on Mac OSX 10.10 Yosemite

Running the command
curl -s https://www.parse.com/downloads/cloud_code/installer.sh | sudo /bin/bash
does not install the tool
I was able to install it easily on my other computer running 10.9.2
STEP : 1
Make a copy of this
#!/bin/bash
TMP_FILE=/tmp/parse.tmp
if [ -e /tmp/parse.tmp ]; then
echo "Cleaning up from previous install failure"
rm -f /tmp/parse.tmp
fi
echo "Fetching latest version ..."
curl --progress-bar https://www.parse.com/downloads/cloud_code/parse -o /tmp/parse.tmp
if [ ! -d /usr/local/bin ]; then
echo "Making /usr/local/bin"
mkdir -p /usr/local/bin
fi
echo "Installing ..."
mv /tmp/parse.tmp /usr/local/bin/parse
chmod 755 /usr/local/bin/parse `
to a file named install.sh and run it in your terminal as bash install.sh. This will install you parse in your Terminal.
STEP :2
Download the Gist from this link and run the file named install.sh in your Terminal preceded by bash

mkdir always creates a file instead a directory

First I want to say that I don't really know what I should look for, here in Stack Overflow and what could be a good query for my problem.
In simple words I want to create a new directory and than do some file operations in it. But with the script that I have crafted I got always a file instead of a directory. It seems to be absolutely regardless how I stick the code together there is always the same result. I hope tat masses can help me with their knowledge.
Here is the script:
#!/bin/bash
DLURL=http://drubuntu.googlecode.com/git'
d7dir=/var/www/d7/'
dfsettings=/var/www/d7/sites/default/default.settings.php
settings=/var/www/d7/sites/default/settings.php
#settiing up drush
drush -y dl drush --destination=/usr/share;
#Download and set up drupal
cd /var/www/;
drush -y dl drupal;
mkdir "$d7dir"; #this is the line that always produces a file instead a directory
# regardless if it is replaced by the variable or entered as
# /var/www/d7
cd /var/www/drup*;
cp .htaccess .gitignore "$d7dir";
cp -r * "$d7dir";
cd "$d7dir";
rm -r /var/www/drup*;
mkdir "$d7dir"sites/default/files;
chmod 777 "$d7dir"sites/default/files;
cp "$dfsettings" "$settings";
chmod 777 "$settings";
chown $username:www-data /var/www/d7/.htaccess;
wget -O $d7dir"setupsite $DLURL/scripts/setupsite.sh; > /dev/null 2>&1
chmod +x /var/www/setupsite;
echo "Login Details following...";
read -sn 1 -p "Press any key to continue...";
bash "$d7dir"setupsite;
chown -Rh $username:www-data /var/www;
chmod 644 $d7dir".htaccess;
chmod 644"$settings";
chmod 644"$dfsettings";
exit
I hope someone got the reason for that.
There are many way to debug a shell-scripting.
Add set -x in your beginning script
Get the return value.
mkdir 'the-directory'
ret=$?
if test $ret -eq 0; then
echo 'Create success.'
else
echo 'Failed to create.'
fi
Set to verbose mode $ mkdir -v 'the-directory'
Try this command $ type mkdir, to checking mkdir command.

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