Below is the sample XML fragment, from it i'm trying to filter out id's of articles matching both conditions as below. Currently i could extract id's for individual condition with help of expression below
get Avaialable articles, Xpath2 expression = (//*//*//*//*[starts-with(state,'Avaialable')])/id
get articles name starting with 'A' () , Xpath2 expression = (//*//*//*//*[starts-with(name,'A')])/id
I want to merge these conditions in a single expression and would like to
fetch id's of Articles where Name starts with 'A' AND articles which
are Available
. Tried multiple ways but not working as expected.
Dummy XML fragment:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<ns3:GetArtclesResponse
xmlns:ns2="XXX"
xmlns:ns4="XXX"
xmlns:ns3="XXX"
xmlns:ns6="XXX"
xmlns:ns5="XXX"
xmlns:ns8="XXX"
xmlns:ns7="XXX"
xmlns:ns13="XXX"
xmlns:ns9="XXX"
xmlns:ns12="XXX"
xmlns:ns11="XXX">
<serverTimeInfo timezone="+00:00" timestamp="1606409365419"/>
<items>
<count>2</count>
<articles>
<article>
<name>ABC</name>
<id>1234</id>
<state>Avaialable</state>
</article>
<article>
<name>XYZ</name>
<id>3456</id>
<state>Avaialable_Conditional</state>
</article>
</articles>
</items>
</ns3:GetArtclesResponse>
You can use and to check both:
(//*//*//*//*[starts-with(state,'Avaialable') and starts-with(name,'A')])/id
If you want to combine 2 different XPath expressions you can use | (union) operator like:
//article[state = 'Avaialable'] | //article[starts-with(name,'A')]
it will return you both:
nodes which have state=Available
and nodes which name starts with A
If you want to combine 2 conditions in a single XPath expression - go for and operator like:
//article[state = 'Avaialable' and starts-with(name,'A')]
it will return
nodes which nave state=available and whose name attribute starts with a
More information:
XPath Operators
The JMeter XPath2 Extractor: How to Achieve Better Correlations
Related
sample_xml='<employees>\
<person id="p1">\
<name value="Alice">ALICE</name>\
</person>\
<person id="p2">\
<name value="Alice">BOB</name>\
</person>\
<person id="p3">\
<name value="Alice"/>\
</person>\
</employees>'
data = [
[f'{sample_xml}']
]
df = spark.createDataFrame(data, ['data'])
df=df.selectExpr(
'xpath(data,"/employees/person/name[#value=\'Alice\']/text()") test'
)
this gives expcted ["ALICE", "BOB"]
Problem:
I want my result to be ["ALICE", "BOB","NA"]
i.e for empty path like below
<name value="Alice"/>
I want to return a default NA .
is it possible to achieve this ?
Regards
With XPath itself this is not possible. It can only return you the actual values of the matching nodes or nothing if no match.
In order to get NA or any other data that is not actually contained in the XML, you should wrap the basic XPath request with some additional, external code to return the customized output in case of no match.
In XPath 2.0, use /employees/person/name[#value=\'Alice\'] /(string(text()), 'NA')[1]".
It can't be done in XPath 1.0. In XPath 1.0 there's no such thing as a sequence of strings; you can only return a sequence of nodes, and you can only return nodes that are actually present in the input document.
I am trying to fetch two nodes from XML as combined result using OR condition.
Nodes in XML where name = John or name="jim",both should be returned . So basically I expect following result:
<person name="John"></person>
<person name="Jim"></person>
I have tried XPath function * ///person[#name="John"] or ///person[#name="Jim"]*
but it gives me only one node.
How to construct Xpath function in this case ?
regards,
Venky
I would use a predicate person[#name = ('John', 'Jim')] if we assume Saxon means a Saxon 9 version where XPath 2 or 3 is supported. Of course the right place for your or expression would be inside the square brackets person[#name = 'Jim' or #name = 'John'].
I have posted sample XML and expected output kindly help to get the result.
Sample XML
<root>
<A id="1">
<B id="2"/>
<C id="2"/>
</A>
</root>
Expected output:
<A id="1"/>
You can formulate this query in several ways:
Find elements that have a matching attribute, only ascending all the time:
//*[#id=1]
Find the attribute, then ascend a step:
//#id[.=1]/..
Use the fn:id($id) function, given the document is validated and the ID-attribute is defined as such:
/id('1')
I think it's not possible what you're after. There's no way of selecting a node without its children using XPATH (meaning that it'd always return the nodes B and C in your case)
You could achieve this using XQuery, I'm not sure if this is what you want but here's an example where you create a new node based on an existing node that's stored in the $doc variable.
declare variable $doc := <root><A id="1"><B id="2"/><C id="2"/></A></root>;
element {fn:node-name($doc/*)} {$doc/*/#*}
The above returns <A id="1"></A>.
is that what you are looking for?
//*[#id='1']/parent::* , similar to //*[#id='1']/../
if you want to verify that parent is root :
//*[#id='1']/parent::root
https://en.wikipedia.org/wiki/XPath
if you need not just parent - but previous element with some attribute: Read about Axis specifiers and use Axis "ancestor::" =)
In case below two elements do not show in same time
<a title='a' />
<b title='b' />
I want to check if one of them can show
does xpath support the 'or' function? I just want to write in one line:
//a[#title='a'] or .. #title='b' ??
XPath Operators
Select either matching nodes (your case here):
//a[#title='a'] | //b[#title='b']
Select one element with either matching attributes
//a[#title='a' or #title='b']
If you want to match either <a/> elements with #title='a' attribute or <b/> elements with #title='b' attribute, you can also match all elements and perform a test on their name:
//*[local-name(.) = 'a' and #title='a' or local-name(.) = 'b' and #title='b']
Is there a way to use data from the current context to filter nodes somewhere else in the statsource.
For instance, if I have this XML:
<root>
<group1>
<inst>
<type>Foo</type>
<value>First Foo</value>
</inst>
<inst>
<type>Bar</type>
<value>The Bar</value>
</inst>
<inst>
<type>Foo</type>
<value>Second Foo</value>
</inst>
</group1>
<group2>
<Filter>
<FilterType>Foo</FilterType>
</Filter>
<Filter>
<FilterType>Bar</FilterType>
</Filter>
</group2>
</root>
Assuming my context is one of the Filter tags, I want to return get the number of instances of the specified type in group1. I would like to write XPATH that looks something like this:
count(/root/group1/inst[type = **FilterType**])
Is there anything I can use to get the FilterType in the original context?
This can be done easily in XPath 2.0:
for $type in /*/*/Filter[1]/FilterType
return
count(/*/group1/*[type eq $type])
When this Xpath expression is evaluated against the provided XML document, the correct result is returned:
2
In XPath 1.0, if the number of group1/inst elements is known in advance, and $vType stands for the FilterType in question, then one could construct the following XPath 1.0 expression:
($vType = /*/group1/inst[1]/type)
+
($vType = /*/group1/inst[2]/type)
+
($vType = /*/group1/inst[3]/type)
which again produces:
2.
Finally, if the XPath 1.0 expression is needed in XSLT and the "Filter" is the current node,
then the following XPath expression calculates the exact number of matches:
count(/*/group1/inst[type = curent()/FilterType])
I'm looking for a solution to the same problem. Currently, I'm using a variable to route around this... it'd look something like the following
<xsl:variable name='FilterType'><xsl:value-of select='FilterType'/></xsl:variable>
<xsl:value-of select='count(/root/group1/inst[type = $FilterType])'/>
But there has to be a better way.