Unable to use associative array value in sed or awk - bash

Question

I am trying to iteratively search and replace strings in a file using a variable input and replacement string. I have tried using sed and awk and have seemed to determine that it is actually the associative array value that is giving me issues(?).
I am looking at an associative array like this:
declare -A speedReplaceValuePairsText
speedReplaceValuePairsText["20"]="xthirtyx"
speedReplaceValuePairsText["30"]="xfiftyx"
speedReplaceValuePairsText["40"]="xsixtyx"
speedReplaceValuePairsText["50"]="xeightyx"
speedReplaceValuePairsText["60"]="xhundredx"
and for ease I was declaring my replacement vars first:
for speedBeforeValue in "${!speedReplaceValuePairsText[#]}";
do
findValue=${speedBeforeValue}
replaceWithValue=${speedReplaceValuePairsText[$speedBeforeValue]}
#replaceWithValue="blah"
echo " Replacing $findValue with $replaceWithValue..."
awk -v srch="$findValue" -v repl="$replaceWithValue" '{gsub(srch,repl); print}' infile.txt > outfile.txt
#sed 's/'"$findValue"'/'"$replaceWithValue"'/g' infile.txt > outfile.txt
#sed "s/$findValue/$replaceWithValue/g" $scriptDir/$currentFileName > outfile.txt
done
The commented out lines are alternate versions of what I have tried with similar inbetween versions.
I have tried using just a normal string (the commented out "blah") and that works fine.
The weirdest part is that the echo statement displays the right value for both key and value.
I have tried so many combinations I am losing my mind. Please someone tell me I am doing something dumb here.
NOTE: This is nested inside another loop but I do not believe this to be an issue, let me know if I am wrong
EDIT: I have simplified the in and out files, and to clarify, if i try to use my associative array value, nothing gets replaced. But if i use a dummy string like "blah" it works.
BONUS: I have marked the answer below, but my search and replace values start and end in double quotes but no matter what I try it replaces all instances of 60. How can i make it replace "60" with "xsixtyx"?
Thanks

Answer 1

I think you want to use >> instead of > inside your loop?
awk -v srch="$findValue" -v repl="$replaceWithValue" '{gsub(srch,repl); print}' $scriptDir/$currentFileName >> ./$outputFolderName/$currentFileName
I tried to run your code it works as expected except that >.
Or if you just want to see the replaced results
awk -v srch="$findValue" -v repl="$replaceWithValue" '{ if (gsub(srch,repl)) print}' $scriptDir/$currentFileName >> ./$outputFolderName/$currentFileName
For a file with
30
20
60
the output looks like
xthirtyx
xhundredx
xfiftyx
For the second case.
Here is the full bash script I tried
#!/bin/bash
declare -A speedReplaceValuePairsText
speedReplaceValuePairsText["20"]="xthirtyx"
speedReplaceValuePairsText["30"]="xfiftyx"
speedReplaceValuePairsText["40"]="xsixtyx"
speedReplaceValuePairsText["50"]="xeightyx"
speedReplaceValuePairsText["60"]="xhundredx"
for speedBeforeValue in "${!speedReplaceValuePairsText[#]}";
do
findValue=${speedBeforeValue}
replaceWithValue=${speedReplaceValuePairsText[$speedBeforeValue]}
echo " Replacing $findValue with $replaceWithValue..."
awk -v srch="$findValue" -v repl="$replaceWithValue" '{if (gsub(srch,repl)) print}' test.txt >> /tmp/test.txt
done