I am having trouble while I am redirecting an authentication link from my login page. I added the link in to my login page in JSF like this:
<div>
Login via Testinium Cloud
</div>
My spring security configuration is like this:
and()
.authorizeRequests()
.antMatchers(DEFAULT_URL).permitAll()
.antMatchers("/javax.faces.resource/**").permitAll()
.antMatchers("/jsfPages/*").permitAll()
.antMatchers("/errorPages/*").permitAll()
.anyRequest().authenticated()
.and()
.exceptionHandling()
.accessDeniedHandler(jsfAccessDeniedHandler())
.authenticationEntryPoint(jsfAuthenticationEntryPoint())
.and()
.formLogin()
.loginPage(LOGIN_PAGE).permitAll()
.failureUrl(LOGIN_PAGE).permitAll()
.defaultSuccessUrl(DEFAULT_URL)
.successHandler(authSuccessHandler)
.and()
.logout()
.logoutUrl(LOGOUT_URL).permitAll()
.invalidateHttpSession(true)
.logoutSuccessHandler(logoutSuccessHandler)
.and()
.exceptionHandling().accessDeniedPage("/error/403.xhtml");
How could I redirect my link from login page without gettin an authentication error. I tried
#Override
public void configure(WebSecurity web) throws Exception {
web.ignoring().antMatchers("/api/v1/signup");
}
But it didn't work out for me. Thanks!
If you want to exclude a page from your spring security configuration without overriding web security, you can add 'not' method that is connected to 'antMatchers' method in your code with authenticated() method following like this:
.authorizeRequests()
.antMatchers(DEFAULT_URL).permitAll()
.antMatchers("/javax.faces.resource/**").permitAll()
.antMatchers("/jsfPages/*").permitAll()
.antMatchers("/errorPages/*").permitAll()
.antMatchers(LOGIN_TESTINIUM).not().authenticated()
.anyRequest().authenticated()
.and()
Related
I know this question is old but it is not working in my case.
I have a webapp using spring security authentication and CSRF enabled.
Now I want to expose couple of URL to expose to other application without authentication.
#Override
protected void configure(HttpSecurity http) throws Exception {
http
.authorizeRequests()
.antMatchers("/resources/**").permitAll()
.antMatchers("/rest/book").permitAll()
.antMatchers("/rest/check").permitAll()
.anyRequest().authenticated()
.and()
.formLogin()
.loginPage("/login")
.failureUrl("/login")
.successHandler(customizeAuthenticationSuccessHandler)
//.defaultSuccessUrl("/")
.permitAll()
.and()
.logout()
.logoutSuccessUrl("/login?logout")
.permitAll();
}
I have other urls with "/rest/" which are secure. I tried csrfMatcher and with that I am able to expose "/rest/book" but then other urls are giving unexpected behavior.
Unexpected behavior like, my default login page is /login when no authentication but it stopped.
Need to customise the default oauth2 authentication server /login page to user defined page along with passing query parameters
I tried by using this link https://www.javainuse.com/spring/boot_form_security_custom_login
protected void configure(HttpSecurity http) throws Exception {
http.requestMatchers()
.antMatchers("/login","/oauth/authorize")
.and()
.authorizeRequests()
.anyRequest()
.authenticated()
.and()
.formLogin()
.permitAll();
}
I have added swagger ui in my application, earlier below two url's i was able to access directly without any authentication.
http://localhost:1510/swagger-ui.html
http://localhost:1510/v2/api-docs
i need secure swagger urls, don't want anybody directly see the api details of my application.
Note :- For authentication purpose i am using JWT with spring security in my application.
SO in order to secure swagger URLS , i have made entry in spring seurity config .. below code
#Override
protected void configure(HttpSecurity http) throws Exception {
http
.addFilterBefore(corsFilter, UsernamePasswordAuthenticationFilter.class)
.exceptionHandling()
.authenticationEntryPoint(problemSupport)
.accessDeniedHandler(problemSupport)
.and()
.csrf()
.disable()
.headers()
.frameOptions()
.disable()
.and()
.sessionManagement()
.sessionCreationPolicy(SessionCreationPolicy.STATELESS)
.and()
.authorizeRequests()
.antMatchers("/api/register").permitAll()
.antMatchers("/api/activate").permitAll()
.antMatchers("/api/userLogin").permitAll()
.antMatchers("/v2/api-docs").hasAuthority(AuthoritiesConstants.ADMIN)
.antMatchers("/swagger-ui.html").hasAuthority(AuthoritiesConstants.ADMIN)
.and()
.apply(securityConfigurerAdapter());
}
and when i am trying to access swagger urls , i am getting below exception on browser and as well as on eclipse console.
org.springframework.security.authentication.InsufficientAuthenticationException: Full authentication is required to access this resource
How can i pass the jwt token to see the swagger page ?
I am working on a web application & have opted to use spring Security. The idea is for the user to be authenticated to see the Home Page, if the user is not authenticated they are redirected to the login page. This login page also displays a link to a registration form, This part is working correctly.
However, I have encountered an issue when attempting to allow users to sign up via the registration link. The link to the registration form cannot be accessed if the user if not authenticated ("showRegistrationForm")
Can anyone provide insight to why this is occuring? I have Included the code snippet from my SecurityConfig below
#Override
protected void configure(HttpSecurity http) throws Exception {
//Restrict Access based on the Intercepted Servlet Request
http.authorizeRequests()
.antMatchers("/resources/**", "/register").permitAll()
.anyRequest().authenticated()
.antMatchers("/").hasRole("EMPLOYEE")
.antMatchers("/showForm/**").hasAnyRole("EMPLOYEE","MANAGER", "ADMIN")
.antMatchers("/save/**").hasAnyRole("MANAGER", "ADMIN")
.antMatchers("/delete/**").hasRole("ADMIN")
.and()
.formLogin()
// Show the custom form created for the below request mappings
.loginPage("/showSonyaLoginPage")
.loginProcessingUrl("/authenticateTheUser")
// No need to be logged in to see the login page
.permitAll()
.and()
// No need to be logged in to see the logout button.
.logout().permitAll()
.and()
.exceptionHandling().accessDeniedPage("/access-denied");
}
Change the code like below:
#Override
protected void configure(HttpSecurity http) throws Exception {
// Restrict Access based on the Intercepted Servlet Request
http.authorizeRequests()
.antMatchers("/showRegistrationForm/").permitAll()
.anyRequest().authenticated()
.antMatchers("/").hasRole("EMPLOYEE")
.antMatchers("/resources/").permitAll()
.antMatchers("/showForm/**").hasAnyRole("EMPLOYEE","MANAGER", "ADMIN")
.antMatchers("/save/**").hasAnyRole("MANAGER", "ADMIN")
.antMatchers("/delete/**").hasRole("ADMIN")
.and()
.formLogin()
// Show the custom form created for the below request mappings
.loginPage("/showSonyaLoginPage")
.loginProcessingUrl("/authenticateTheUser")
// No need to be logged in to see the login page
.permitAll()
.and()
// No need to be logged in to see the logout button.
.logout().permitAll()
.and()
.exceptionHandling().accessDeniedPage("/access-denied");
}
Moved down the below code:
anyRequest().authenticated()
At my Spring Boot application I need to implement a following scenario:
Anonymous User visits the following page: http://example.com/product-a.html
This User wants to ask a question about this product. It can be done at another page, located by the following address: http://example.com/product-a/ask. User press Ask Question button at the http://example.com/product-a.html and login/registration popup is shown. After successful login User should be automatically redirected to http://example.com/product-a/ask (but currently with a default Spring Security implementation User are redirecting back to the page originator http://example.com/product-a.html)
How to properly with Spring Boot/Spring Security implement/configure this redirect ?
UPDATED
This is my web security config:
#Override
protected void configure(HttpSecurity http) throws Exception {
// #formatter:off
http.addFilterBefore(new CorsFilter(), ChannelProcessingFilter.class);
http
.csrf().ignoringAntMatchers("/v1.0/**", "/logout")
.and()
.authorizeRequests()
.antMatchers("/oauth/authorize").authenticated()
//Anyone can access the urls
.antMatchers("/images/**").permitAll()
.antMatchers("/signin/**").permitAll()
.antMatchers("/v1.0/**").permitAll()
.antMatchers("/auth/**").permitAll()
.antMatchers("/actuator/health").permitAll()
.antMatchers("/actuator/**").hasAuthority(Permission.READ_ACTUATOR_DATA)
.antMatchers("/login").permitAll()
.anyRequest().authenticated()
.and()
.formLogin()
.loginPage("/login")
.loginProcessingUrl("/login")
.failureUrl("/login?error=true")
.usernameParameter("username")
.passwordParameter("password")
.permitAll()
.and()
.logout()
.logoutUrl("/logout")
.logoutSuccessUrl(logoutSuccessUrl)
.permitAll();
// #formatter:on
}
I use OAuth2/JWT + Implicit Flow for AngularJS client
I think you should not use spring's default /login processing url, but create your own e.g /mylogin in a controller. And then you can inject the HttpServletRequest in the method and take the action based on the context of the request for example:
#PostMapping("/mylogin")
public ResponseEntity<> processingLogingURL(HttpServletRequest request){
// switch bases on the request URL after checking security off course
switch(request.getRequestURL()){
//redirect based on the caller URL
}
}
and finally change your .loginProcessingUrl("/login") to .loginProcessingUrl("/mylogin")