I'm trying to make a script that is working from 12/24/2020 through 06/01/2021. For now I olny have it working only for 2 dates with this:
if [ "$(date +'%m%d')" != "1224" ] && [ "$(date +'%m%d')" != "1226" ];
So this script should be working from 12/24 - 01/06.
Any suggestions? Thanks
You can use the +%s option in date to convert the start/finish dates to epoch time. You supply the dates using the -d option.
Then, you retrieve the current date using +%s again and compare using standard integer comparison, like this:
start=$(date +%s -d '12/24/2020')
finish=$(date +%s -d '06/02/2021')
now=$(date +%s)
if [ $now -ge $start ] && [ $now -lt $finish ]
then
echo "Do something"
else
echo "Skip"
fi
Edit: For the finish date, its necessary to use the day after your intended finishing date and compare using -lt. This is because date will return the timestamp for the start of the specified date. So doing this, you end up having the comparison succeed until midnight on 06/01/2021. Thanks to #gordon-davisson for pointing this out.
beg='20201224'
end='20210601'
now=$(date +'%Y%m%d')
if (( beg <= now )) && (( now <= end)); then
Related
I am trying to compare a string converted to date and a file creation time in bash.
#!/bin/bash
test='2020-05-13 08:00'
testConverted=$(date -d "$test" +'%Y %m %d %H:%M')
[ "~/fileToCompare" -nt "$testConverted" ] && echo "yes"
This always returns false no matter what date I put for test. Is the conversion of the date wrong? Is this possible to do?
The way to do this is to convert the date string into Unix Epoch time (seconds since Jan 1, 1970) with the date command and then similarly get the Epoch time modification date of the test file using the stat command and compare using arithmetic evaluation
#!bin/bash
testDate='2020-05-13 08:00'
testFile="$HOME/fileToCompare"
if (( $(date -d "$test" +%s) > $(stat "$testFile" -c %Z) )); then
echo "testDate ($testDate) is newer than $testFile"
fi
I have nested for loops going through dates and create a date. How can I check if that specific date is on the weekend or not?
String date is in the format of mm/dd/yyyy but can easily be changed. Each has its own variable $m $d $y
if [[ $(date +%u) -gt 5 ]] ; then
#do something
fi
above code works with current date, not sure how to translate that to accepting a string date.
You could use Ruby Date#cwday in your bash script. For example:
#!/bin/bash
y=2019
m=11
d=10
ruby -rtime -e "puts ([6,7].include? Date.new($y,$m,$d).cwday)"
which outputs true
I like more to use the variable directly:
if [[ $(date -d $your_variable +%u) -gt 5 ]]; then
#do something
fi
Just makes the code cleaner in my opinion.
I am trying to create a script in which 4 days ago date should be equal to to current date if it is not then add 1 more day and check. Below is the one i have created but still not clear about answer.
#!/bin/bash
batchdate=`date --date "4 day ago" '+%Y%m%d'`
matchdate=`date --date "today" '+%Y%m%d'`
for i in {0..4}
do
if [ $batchdate != $matchdate && $NEXT_DATE != $matchdate ]; then
NEXT_DATE=$(date +%Y%m%d -d "$batchdate + $i day")
echo "$NEXT_DATE"
break
fi
done
First, define a little helper function to avoid doing the same thing in slightly different ways:
get_date () {
date +%Y-%m-%d --date "$1"
}
Now, you have two variables: the current date, which will never change, and the starting date, which you will increment one day at a time until it matches the current date.
then=$(get_date "4 days ago")
now=$(get_date "today")
while [[ $then != $now ]]; do
then=$(get_date "$then + 1 day")
echo "$then"
done
This question already has answers here:
A variable modified inside a while loop is not remembered
(8 answers)
Closed 4 years ago.
please bear with me and my questions, but I just started programming in bash yesterday effectively.
I have a script that does a lot of stuff so far. And I came to a point where I need to iterate through variables. I created these variables before using a while loop. The $Time variable for example looks like this:
2016-01-29 17:07:00Z
2016-01-29 17:26:20Z
2016-01-29 17:26:20Z
2016-01-29 00:07:00Z
The Grabinterval variable like this:
hour
minute
minute
day
The first step for me is to check if a different variable is not empty. If it is not I go on with checking line per line inside the $Grabinterval variable what kind it is day, hour or minute.
That is done by a while loop as well and works good. But no the problems are rising. Now I want to calculate a time difference between a time that was created earlier outside of the while loop and the time given in the first line of the $Time variable. I tried this using the following code:
while read -r line; do
if [[ ! -z "$Filelocation" ]]
then
if [[ $line = "day" || $line = "days" ]]
then
Interval="Days"
GrabTimeNew=$(date +'%Y-%m-%d 00:0'$UPOFFSET':00Z')
default=$(date --date "-1 day" +'%Y-%m-%d 00:0'$UPOFFSET':00Z')
start=$(date -d"$line$Time" +%s)
end=$(date -d"$GRABtime" +%s)
TimeDiff=$(( $start - $end ))
fi
fi
done <<< $Grabinterval
This is only on part of the bigger while loop, the other two parts looking for hour and minuteare pretty much the same.
The way I tried it here using $line$Time gives me following error message:
date: invalid date ‘day2016-01-29 17:07:00Z\n2016-01-29 17:26:20Z\n2016-01-29 17:26:20Z\n2016-01-29 00:07:00Z’
So it goes over all lines instead of only the dayline I want it to go through. Is there a way to use the first line of the $Timevariable inside the $Grabinterval variable?
I would love to use a for loop, but I have no idea how to use it later in the command block to have the wanted line read in the command block of the if statement.
Thanks,
BallerNacken
EDIT: Tried something like this now, but not working either:
while read -r GI TI; do
if [[ ! -z "$Filelocation" ]]
then
if [[ $GI = "day" || $GI = "days" ]]
then
Interval="Days"
GrabTimeNew=$(date +'%Y-%m-%d 00:0'$UPOFFSET':00Z')
default=$(date --date "-1 day" +'%Y-%m-%d 00:0'$UPOFFSET':00Z')
start=$(date -d"$TI" +%s)
end=$(date -d"$GRABtime" +%s)
TimeDiff=$(( $start - $end ))
fi
if [[ $GI = "hours" || $GI = "hour" ]]
then
Interval="Hours"
GrabTimeNew=$(date +'%Y-%m-%d %H:0'$UPOFFSET':00Z')
default=$(date --date "-1 hour" +'%Y-%m-%d %H:0'$UPOFFSET':00Z')
start=$(date -d"$TI" +%s)
end=$(date -d"$GRABtime" +%s)
TimeDiff2=$(( $start - $end ))
fi
if [[ $GI = "min" || $GI = "minutes" || $GI = "minute" ]]
then
Interval="Minutes"
GrabTimeNew=$(date +'%Y-%m-%d %H:%M:20Z')
default=$(date --date "-1 minute" +'%Y-%m-%d %H:%M:00Z')
start=$(date -d"$TI" +%s)
end=$(date -d"$GRABtime" +%s)
TimeDiff3=$(( $start - $end ))
fi
fi
done < <(paste <(echo "$Grabinterval") <(echo "$Time"))
I don't get any error messages, but no variables were created inside the if statement/while loop.
You might want to try something like this:
while read -r interval datetime; do
#...
done < <(paste <(echo "$Grabinterval") <(echo "$Time"))
That will read one line from Grabinterval and the corresponding line from Time
You need to quote the variable to keep the newlines in the <<< $var.
list=$'a\nb\nc'
while read a ; do echo $a ; done <<< $list
while read a ; do echo $a ; done <<< "$list"
I trying to print date between 2 dates using while loop in a bash script.
But when i execute i am getting below error:
test.sh: line 8: [: 02-12-14: integer expression expected
Below is my code, can anyone help me out
#!/bin/bash
sdate=02-12-14
edate=02-25-14
while [ "$sdate" -le "$edate" ]
do
echo $sdate
sdate=$(date +%m-%d-%y -d "$sdate + 1 day")
done
You should store them as timestamps:
#!/bin/bash
sdate=$(date -d '2014-02-12' +%s)
edate=$(date -d '2014-02-25' +%s)
while [[ sdate -le edate ]]; do
date -d "#$sdate" '+%m-%d-%y'
sdate=$(date -d "$(date -d "#${sdate}" ) + 1 day" +%s)
done
Output:
02-12-14
02-13-14
02-14-14
02-15-14
02-16-14
02-17-14
02-18-14
02-19-14
02-20-14
02-21-14
02-22-14
02-23-14
02-24-14
02-25-14
Always prefer [[ ]] over [ ] when it comes to conditional expressions in Bash. (( )) may also be a preference.
It requires GNU date. e.g. date --version = date (GNU coreutils) 8.21 ...
mm-dd-yy is not a format acceptable by date for input so I used yyyy-mm-dd which is acceptable.