I just wanted to know, how do I pass multiple clips to animation-mixer?
The extension GitHub mentions that the clip parameter accepts clips(s). I have tried to add multiple clip names separated by comma and in array, but nothing works. How does it work?
model.setAttribute('animation-mixer', {
clip: '["Idle", "Laugh"]',
loop: 'once',
crossFadeDuration: 0.4,
timeScale: 1,
})
The animation-mixer component does not support multiple animation names. However, if you use the asterisk(*) at the end of the word. Then, it will generate a Regexp that will match every clip that starts with the word before the * and everything after it.
E.g.
Idle* will be converted into ^Idle.*$ Regexp, therefore, any clip that starts with word "Idle" will be matched.
Related
I'm using the REGEXREPLACE function in google sheets to extract some text contained in skus. If it doesn't find a text, it seems to return the entire original string. Is it possible to make it return an empty string instead? Having problems with this because it doesn't actually error out, so using iserror doesn't seem to work.
Example: my sku SHOULD contain 5 separate groups delimited by the underscore character '_'. in this example it is missing the last group, so it returns the entire original string.
LDSS0107_SS-WH_5
=REGEXREPLACE($A3,"[^_]+_[^_]+_[^_]+_[^_]+_(.*)","$1")
Fails to find the fifth capture group, that is correct... but I need it to give me an empty string when it fails... presently gives me the whole original string. Any ideas??
Perhaps the solution would be to add the missing groups:
=REGEXREPLACE($A1&REPT("_ ",4-(LEN($A1)-LEN(SUBSTITUTE($A1,"_","")))),"[^_]+_[^_]+_[^_]+_[^_]+_(.*)","$1")
This returns space as result for missing group. If you don't want to, use TRIM function.
How can I test whether a sentence (combination of four or five words) is displayed in a single line?
I have to search with a name or some other fields. After search results are displayed, I should test whether the displayed text is a single line. For example, the code below is used to verify the search result link:
//ol[contains(#class,'search results')]/li[contains(#class,'mod result') and contains(#class,'XXXXXX')]//a[contains(#href,'trk=XXXXXX')]
I am not familiar with ruby, but the following java approach should work in any language.
Assuming that your "sentence" is entirely contained in one element, you could find all occurrences with something like:
driver.findElements(By.xpath("//*[text()='your sentence']"))
Then simply test for the size of the array.
Assuming that a single or multiple lines will be contained within a single DOM element, you could use the vertical component of the element size to check for the multiple line condition.
webElement.getSize()
I just want to save the text between two specific points in a string into a variable. The text would look like this:
..."content"=>"The text I want to save to a variable"}]...
I suppose I would have to use scan or slice, but not exactly sure how to pull out just the text without grabbing the RegEx identifiers before and after the text. I tried this, but it didn't work:
var = mystring.slice(/\"content\"\=\>\".\"/)
This should do the job
var = mystring[/"content"=>"(.*)"/, 1]
Note that:
.slice aliases []
none of the characters you escaped are special regexp characters where you're using them
you can "group" the bit you want to keep with ()
.slice / [] take a second parameter to pick a matched group
your_text = '"content"=>"The text I want to save to a variable"'
/"content"=>"(?<hooray>.*)"/ =~ your_text
Afterwards, hooray local variable will be magically set to contain your text. Can be used to set multiple variables.
This regex will match your string:
/\"content\"=>\"(.*)\"/
you can try rubular.com for testing
It looks like you're trying to truncate a sentence. You can split the sentence either on punctuation, or even on words.
mystring.split(".")
mystring.split("word")
I have been looking at regular expressions to try and do this, but the most I can do is find the start of a line with ^, but not replace it.
I can then find the first characters on a line to replace, but can not do it in such a way with keeping it intact.
Unfortunately I don´t have access to a tool like cut since I am on a windows machine...so is there any way to do what I want with just regexp?
Use notepad++. It offers a way to record an sequence of actions which then can be repeated for all lines in the file.
Did you try replacing the regular expression ^ with the text you want to put at the start of each line? Also you should use the multiline option (also called m in some regex dialects) if you want ^ to match the start of every line in your input rather than just the first.
string s = "test test\ntest2 test2";
s = Regex.Replace(s, "^", "foo", RegexOptions.Multiline);
Console.WriteLine(s);
Result:
footest test
footest2 test2
I used to program on the mainframe and got used to SPF panels. I was thrilled to find a Windows version of the same editor at Command Technology. Makes problems like this drop-dead simple. You can use expressions to exclude or include lines, then apply transforms on just the excluded or included lines and do so inside of column boundaries. You can even take the contents of one set of lines and overlay the contents of another set of lines entirely or within column boundaries which makes it very easy to generate mass assignments of values to variables and similar tasks. I use Notepad++ for most stuff but keep a copy of SPFSE around for special-purpose editing like this. It's not cheap but once you figure out how to use it, it pays for itself in time saved.
I am getting completely different reults from string.scan and several regex testers...
I am just trying to grab the domain from the string, it is the last word.
The regex in question:
/([a-zA-Z0-9\-]*\.)*\w{1,4}$/
The string (1 single line, verified in Ruby's runtime btw)
str = 'Show more results from software.informer.com'
Work fine, but in ruby....
irb(main):050:0> str.scan /([a-zA-Z0-9\-]*\.)*\w{1,4}$/
=> [["informer."]]
I would think that I would get a match on software.informer.com ,which is my goal.
Your regex is correct, the result has to do with the way String#scan behaves. From the official documentation:
"If the pattern contains groups, each individual result is itself an array containing one entry per group."
Basically, if you put parentheses around the whole regex, the first element of each array in your results will be what you expect.
It does not look as if you expect more than one result (especially as the regex is anchored). In that case there is no reason to use scan.
'Show more results from software.informer.com'[ /([a-zA-Z0-9\-]*\.)*\w{1,4}$/ ]
#=> "software.informer.com"
If you do need to use scan (in which case you obviously need to remove the anchor), you can use (?:) to create non-capturing groups.
'foo.bar.baz lala software.informer.com'.scan( /(?:[a-zA-Z0-9\-]*\.)*\w{1,4}/ )
#=> ["foo.bar.baz", "lala", "software.informer.com"]
You are getting a match on software.informer.com. Check the value of $&. The return of scan is an array of the captured groups. Add capturing parentheses around the suffix, and you'll get the .com as part of the return value from scan as well.
The regex testers and Ruby are not disagreeing about the fundamental issue (the regex itself). Rather, their interfaces are differing in what they are emphasizing. When you run scan in irb, the first thing you'll see is the return value from scan (an Array of the captured subpatterns), which is not the same thing as the matched text. Regex testers are most likely oriented toward displaying the matched text.
How about doing this :
/([a-zA-Z0-9\-]*\.*\w{1,4})$/
This returns
informer.com
On your test string.
http://rubular.com/regexes/13670