Max and min from all index in query - elasticsearch

Question

Is there way to get max and min for all documents in index, not only max and min from category "game" without making another request to elastic?
{
"query": {
"bool": {
"must": [
{
"match": {
"category": "game"
}
}
]
}
},
"aggs": {
"maxPoints": {
"max": {
"field": "points"
}
},
"minPoints": {
"min": {
"field": "points"
}
}
}
Here is some data data i have, with query above I want to get this 2 docs from category game and min 0, max 100 instead of min 10, max 20.
[
{
"id": 1,
"category": "offer",
"points": 0
},
{
"id": 2,
"category": "game",
"points": 10
},
{
"id": 3,
"category": "game",
"points": 20
},
{
"id": 4,
"category": "offer",
"points": 100
}
]

Answer 1

Yeah, just remove the match clause, and add match_all query to include all the documents in your index. Use post_filter to get the expected results in a single ES call.
{
"query": {
"match_all": {}
},
"aggs": {
"maxPoints": {
"max": {
"field": "points"
}
},
"minPoints": {
"min": {
"field": "points"
}
}
},
"post_filter": { // Note this
"term": {
"category": "game"
}
}
}
Output
{
"took": 8,
"timed_out": false,
"_shards": {
"total": 1,
"successful": 1,
"skipped": 0,
"failed": 0
},
"hits": {
"total": {
"value": 2,
"relation": "eq"
},
"max_score": 1.0,
"hits": [
{
"_index": "65406564",
"_type": "_doc",
"_id": "2",
"_score": 1.0,
"_source": {
"id": 2,
"category": "game",
"points": 10
}
},
{
"_index": "65406564",
"_type": "_doc",
"_id": "3",
"_score": 1.0,
"_source": {
"id": 3,
"category": "game",
"points": 20
}
}
]
},
"aggregations": {
"maxPoints": {
"value": 100.0
},
"minPoints": {
"value": 0.0
}
}
}