How to understand order of calling coroutines with scope? - kotlin-coroutines

Question

I saw the coroutines example here.
To understand the example I made three different examples with each scope.
The printed number is the following #N.
It's just my opinion, so if there is a wrong thing, let me know.
#1: 3->1->2->4
runBlocking {
launch {
println("1-Task from runBlocking")
}
coroutineScope { // Creates a coroutine scope
launch {
println("2-Task from nested launch")
}
println("3-Task from coroutine scope")
}
println("4-Coroutine scope is over")
}
I understood the coroutineScope waits until the children will be completed. The outer runBlocking has two coroutines.
The first is launch of 1 and the second is in coroutineScope.
The coroutineScope will be handled first based on the call stack.
Thus the first printed number is 3 because it's within regular function.
And then the 1 can be printed before 2.
The 4 will be printed after coroutineScope block is finished.
#2: 1->3->2->4
runBlocking {
launch {
println("1-Task from runBlocking")
}
runBlocking { // Creates a coroutine scope
launch {
println("2-Task from nested launch")
}
println("3-Task from coroutine scope")
}
println("4-Coroutine scope is over")
}
runBlocking is not suspend function that's why the outer runBlocking doesn't have a coroutine. Thus the 1 will be printed first. After that, the inner runBlocking has one coroutine so wait until this block will be finished. Thus 3 and 2 will be printed. Last, 4 printed after inner runBlocking.
#3: 2->4->3->1, 4->3->2->1, 4->2->3->1
runBlocking {
launch {
println("1-Task from runBlocking")
}
GlobalScope.launch { // Creates a coroutine scope
launch {
println("2-Task from nested launch")
}
println("3-Task from coroutine scope")
}
println("4-Coroutine scope is over")
}
There are several different results so I guessed it depends on environments on runtime.
But I wonder if it's impossible to print 1 first or not.
Second, how to understand scope in other suspend or scope.