Ansible if else using shell script - shell

Question

I am using following ansible tasks for triggering certain a task based on user's choice.
This is working:
tasks:
- name: Run python script for generating Repos Report
command: python GetRepos.py -o {{ org }} -p {{ pat }}
register: result
- debug: msg="{{result.stdout}}"
when: choice == "Repos"
- name: Run python script for generating projects Report
command: python Getprojects.py -o {{ org }} -p {{ pat }}
register: result
- debug: msg="{{result.stdout}}"
when: choice == "projects"
But I want to use a shell script with if else statement to run this in one task as below:
tasks:
- name: run python script
shell: |
if [choice == "repos"]
then
cmd: python GetRepos.py -o {{ org }} -p {{ pat }}
elif [choice == "projects"]
then
cmd: python Getprojects.py -o {{ org }} -p {{ pat }}
fi
register: cmd_output
- debug: msg="{{cmd_output.stdout}}"
But this does not execute the task; it just ends without error.
Is this the right syntax for shell?
How can I achieve these 2 separate working tasks in just one task using the shell module?

Answer 1

The cmd: in a shell script will try to run cmd: as a command, which you don't want.
Also, the if statement conditions need spaces on either side - otherwise, it would try to run [choice as a command, which you also don't want.
Also prefer to use single equals instead of double equals, to make it more portable (the remote hosts could have various different shells!).
The other issue is that choice as used inside the shell script is just a literal string. You need to add the braces {{ }} to interpolate the value, as done elsewhere in the playbook.
Taking into consideration the above, the following should work for you:
tasks:
- name: run python script
shell: |
if [ "{{ choice }}" = "repos" ]
then
python GetRepos.py -o "{{ org }}" -p "{{ pat }}"
elif [ "{{ choice }}" = "projects" ]
then
python Getprojects.py -o "{{ org }}" -p "{{ pat }}"
fi
register: cmd_output
- debug:
msg: "{{ cmd_output.stdout }}"