I am running a program where I want the use to be able to select 1-28 and the program will print_details. However if the user types in ANYTHING else I want to print an error.
UPDATED CODE
input = gets.strip
if input.to_i.between?(0, 27)
print_details(gets.strip)
puts "Is there another episode you would like details on? Y/N".cyan
input = gets.strip
if input == "Y"
list_episode
list_menu
elsif input == "y"
list_episode
list_menu
elsif input == "N"
bye
elsif input == "n"
bye
else
puts "That is not a valid input".red
list_menu
end
Not sure if I missed something? I noticed that if I input "88" it exits my program and if I type "a" it prints that last episode details.
Related
I wonder if there is a way to use the if-else statements to trigger a loop that has the user re-enter a valid input? I have tried using the While loop as that type of structure technically works, but I cannot get the correct implementation. As of now, I have used an if-else conditional to individually test for each number in the valid range, and if the user inputs any of those values, it moves on. The else statement tells the user it is incorrect, but I can't seem to figure out a way to loop the user back until they enter a valid number.
This is the code I am working with:
class Humanoid < Player
def play()
userinput = print 'Enter your move [1 - 5]: '
input = gets&.rstrip
if input == '5'
return input
elsif input == '4'
return input
elsif input == '3'
return input
elsif input == '2'
return input
elsif input == '1'
return input
else
return "That is not an option, choose again"
end
end
end
Is it possible to prompt the user to enter another number if it wasn't correct? I feel like it should be but I am currently stumped on what to do.
I would use a simple loop that runs forever unless you explicitly return (or break) from it:
class Humanoid < Player
def play()
loop do
print 'Enter your move [1 - 5]: '
input = gets.chomp
if %w[1 2 3 4 5].include?(input)
return input
else
puts "That is not an option, choose again"
end
end
end
end
Additionally, I cleaned up your conditions.
I would write it like this:’
loop do
userinput = print 'Enter your move [1 - 5]: '
input = gets&.rstrip
if input == '5'
return input
elsif input == '4'
return input
elsif input == '3'
return input
elsif input == '2'
return input
elsif input == '1'
return input
puts "That is not an option, choose again"
end
Basically, this just makes it repeat forever until a value is returned. If none is, then the issue is printed and it loops again.
I'm doing a pwd generator in ruby and when I get to a certain point of the code I need to return back if the user says that he want to retry to generate the pwd.
print "do you want to retry to generate the password? [y/n]"
retrypwd = gets.chomp
if retrypwd == y
(code to jump to some lines ago)
elsif retrypwd == n
print "Ok, It'll be for the next time"
end
The trick is to use a loop and break it or repeat it according to your expectations:
def try_again?
loop do
print "Would you like to try again? Y/N"
again = gets.chomp.capitalize
case (again)
when 'N'
return false
when 'Y'
return true
else
puts "Huh? I don't know what that means."
end
end
end
Then you can incorporate this into your main program:
begin
try_password
end while try_again?
You will keep trying passwords until try_again? returns false, which happens if you type "N".
I have a program that displays a numbered list and asks the user to input either a number or name from the list, and loops a block until the user enters "exit", after which it ends.
I want to add a line or two that puts an error message like, "Sorry, I don't seem to understand your request" if the user inputs something that is not on the list (name/number) and is not the word "exit".
I can't seem to figure it out. Any advice? My current code is below.
def start
display_books
input = nil
while input != "exit"
puts ""
puts "What book would you more information on, by name or number?"
puts ""
puts "Enter list to see the books again."
puts "Enter exit to end the program."
puts ""
input = gets.strip
if input == "list"
display_books
elsif input.to_i == 0
if book = Book.find_by_name(input)
book_info(book)
end
elsif input.to_i > 0
if book = Book.find(input.to_i)
book_info(book)
end
end
end
puts "Goodbye!!!"
end
Seems that you should add an elsif statement in this if:
if book = Book.find_by_name(input)
book_info(book)
elsif input != 'exit'
puts "Sorry, I don't seem to understand your request"
end
A good template for an interpreter is to build around Ruby's very capable case statement:
loop do
case (gets.chomp.downcase)
when 'list'
display_books
when /\Afind\s+(\d+)/
if book = Book.find($1.to_i)
book_info(book)
end
when /\Afind\s+(.*)/
if book = Book.find_by_name($1)
book_info(book)
end
when 'exit'
break
else
puts "Not sure what you're saying."
end
end
Although this involves regular expressions, which can be a bit scary, it does give you a lot of flexibility. \A represents "beginning of string" as an anchor, and \s+ means "one or more spaces". This means you can type in find 99 and it will still work.
You can create a whole command-line interface with it if you take the time to specify the commands clearly. Things like show book 17 and delete book 17 are all possible with a bit of tinkering.
I am trying to get this program to run:
cpucount = 0
playercount = 0
tiecount = 0
playerchoice =
while playerchoice != "n"
puts "Chose your Weapon. Paper (0), Rock (1), Scissors (2)"
player1 = 0 #gets
cpuplayer = 2#rand(3)
puts player1
puts cpuplayer
if player1 == 0 and cpuplayer == 1
puts "You Win"
playercount +=1
elsif player1 == 1 and cpuplayer == 2
puts "You Win!"
playercount +=1
elsif player1 == 2 and cpuplayer == 0
puts "You Win!"
playercount +=1
elsif player1 == cpuplayer
puts "You tied!"
tiecount +=1
else
puts "You lose"
cpucount +=1
end
puts cpucount
puts playercount
puts tiecount
puts "Do you want to play again? y/n?"
playerchoice = gets
puts playerchoice
end
but there are a few issues.
First, regardless of whether I select "y" to continue to another round or "n" to quit, it still runs another round.
Second, the logic is fine when I manually input the values for player1 and cpuplayer, but when I use the rand method and the user input, the program takes those and then the logic doesn't work.
Any help would be appreciated.
In your input statement which is using gets you need to take into account the newline that is placed in the string, and the fact that it is a string. When the player is inputting it, it is coming in as text, not an integer. A simple way to do this is to make it an integer on input, via
player1 = gets.to_i
That will guarantee that the conditional logic you use to test against integers is not going to fail because you are comparing a string.
The newline that is coming in with the playerchoice input needs get chomped to make that happy for comparison. So, there is another method to get rid of newlines.
playerchoice = gets.chomp
Try assigning the playerchoice variable in the following way:
playerchoice = gets.chomp
The #gets method by itself will output any carriage returns that come with the user's input, which is why if you were to inspect the returned value for playerchoice, you'd see that instead of "n", the value returned is actually "n\n", causing your comparison to resume looping the game. Calling #chomp on that value strips out the carriage return characters (\n, \r, \r\n), which should allow the game to end if "n" is typed in by the user.
Hope it helps!
I don't really know how to word this short enough for me to google it.
But is it possible to execute a certain condition in a multiple condition while loop differently, without creating a whole entire while loop.
For example, Is it possible to do something like this
while num == "" || num == "0"
#ENTER CODE
Instead of doing this
while num == ""
print "YOU MUST ENTER A NUMBER!"
num = gets.chomp
end
while num == "0"
print "ZERO IS NOT A VALID NUMBER!"
num = gets.chomp
end
I want to know is it possible to do this, but make it look more visually appealing and concise.
This should do the trick, one loop and use conditionals for which error message to print.
while num == "" || num == "0"
print "YOU MUST ENTER A NUMBER!" if num == ""
print "ZERO IS NOT A VALID NUMBER!" if num == "0"
num = gets.chomp
end
You could write something like this:
while num.to_i.zero?
case number
when ''
print 'YOU MUST ENTER A NUMBER!'
when '0'
print 'ZERO IS NOT A VALID NUMBER!'
end
num = gets.chomp
end
This works, because to_i returns 0 for both the string "0" and nil.
Furthermore I would suggest to change the error message to simplify the code even more:
while num.to_i.zero?
print 'Please enter a number greater then zero'
num = gets.chomp
end