Tried many different ways but doesn't seem to work. Hoping someone can shed some light on this
This is what I'm trying to achieve and _variable.scss / _base.scss are coming from a library so I can't modify them
_variables.scss
$color: red !default;
_base.scss
#use 'variable' as base-variable;
.test {
color: base-variable.$color;
}
my-component.scss
#use '_base'; // I want to modify the color in this file, how should it be done?
**expected output
.test {
color: **another color**;
}
I finally figured it out, you can override the whole imported module.
my-component
#use 'variable' as base-variable with (
$color: 'another-color'
);
#use '_base'
Related
I want the _typography.scss access variables on _variables.scss .
// _variables.scss
$color: <null> | <$variable> | <value> | <etc>;
// _typography.scss
body {color: $color;}
When I try:
//_typography.css
#use '_variables.scss'
body:{color: $color;} / Error undefined variable. color: $color;
But when I try:
//_typography.css
#import '_variables.scss'
body:{color: $color;} / works as intended.
Since Sass is migrating from #import to #use, why the #use doesnt work as expected in this case?
And what would be the best practice to avoid this problem?
Thanks in advance.
When you use #use, your imports have a namespace by default. You can either use the namespace:
#use "variables";
body: { color: variables.$color; }
Or remove it with #use "<url>" as *:
#use "variables" as *;
body: { color: $color; }
The best practice is to read the doc. ;)
I have a main.scss file that I want to import colors into from a _colors file.
I have defined a body color in the color file, when I try to import it, I see no changes in the webpage. They are both in the same scss folder but neither #include or #import seem to make a difference. I have tried with and without the underscore in my import statement, both single and double quotes and both import and include keywords. Please tell me what stupid mistake I am making that will rectify this problem as I have researched the problem and think I have been able to copy the examples with no success.
_colors.scss
body {
$background-color: maroon;
}
main.scss
#include 'colors';
Partials are used with #use directive. Then,
_colours.scss
body{
background-color: maroon;
}
style.scss
#use "_colours";
The reuse of code is done through the #mixin directive.
_colours.scss
#mixin body--background{
background-color:maroon;
}
style.scss
#use "_colours.scss" as so;
body{
#include so.body--background;
}
But, if you want to just define just colours use variables instead. Example below,
_colours.scss
$maroon=maroon;
$lightblue=//et cetera.
style.scss
#use "_colours";
body{
background-color:$maroon;
}
If you have a main.scss file which will be the file that gets compiled, and you want to import variables, mixins etc from another partial file, such as _colors.scss. You could do so by loading the members from the partial _colors.scss into main.scss with a #use at-rule. This allows loaded members from the module to be referenced with dot-notation throughout your main.scss stylesheet.
Let's say your _colors.scss file looked like this:
$bodyColor: maroon;
$someOtherColor: #f06;
/* adding a mixin for demo */
#mixin highlight($c, $bg) {
color: $c;
background: $bg;
}
/* some extra styles pertaining to _color.scss */
.some-styles {
color: $someOtherColor;
}
Note: The syntax for #use is #use <url> as <namespace>;.
You could load the variables/mixins etc into main.scss with a #use rule and reference the namespace throughout your program:
#use "./colors" as c;
body {
background-color: c.$bodyColor;
}
.highlighted {
#include c.highlight(#fff, #f06);
}
or without defining a namespace like:
#use "./colors" as *;
body {
background-color: $bodyColor;
}
.highlighted {
#include highlight(#fff, #f06);
}
You certainly can include a body {} declaration inside _colors.scss and load it the same way as discussed above, but I think your wanting to place the body style block inside main.scss and simply reference loaded variables from _color.scss. If you have a directory of many partials and want to load them into main.scss without writing separate #use rules for each load, then introduce a index file with #forward rules to load an entiry directory of partials into main.scss using a single #use rule.
i am struggling with breaktpoints in SASS.
I have this file structure
style.scss
_layout.scss
_variables.scss
I wanna use code breakpotints from _variables.scss in _layout.scss
_variables.scss
$screen-xl-min: 1200px;
#mixin xl {
#media (min-width: #{$screen-xl-min}) {
#content;
}
}
_layout.scss
#use 'variables';
nav {
height: 80px;
#include xl {
background-color: red;
}
}
style.scss
#use 'variables';
#use 'layout';
And I have error
SassError: Undefined mixin.
Can someone tell me, what am I doing wrong? Thanks a lot for a help!
Try and change
#use 'variables'
for
#use 'variables' as *;
Check the documentation: https://sass-lang.com/documentation/at-rules/use
In your example correct way will be write #include variables.xl {}
Or modify #use rule like #Café wrote
I'm attempting to integrate scss with the .net theming functionality.
Ideally most scss would be in a dedicated directory, but each theme would have its own scss page containing exclusively the variable values for that particular theme.
The problem I'm encountering is that I need to pass placeholder variables to the _layout.scss sheet, and then have their values updated by the theme scss sheets. Currently the original null values are outputted.
SCSS Files
Resources/SCSS/_variables.scss
$theme_color: null;
Resources/SCSS/_layout.scss
#import "variables";
div {
color: $theme_color;
}
Themes/Blue/blue.scss
$theme_color: #0000ff !default;
#import '../../Resources/SCSS/layout';
Themes/Red/red.scss
$theme_color: #ff0000 !default;
#import '../../Resources/SCSS/layout';
Desired CSS Output Files
blue.css
div {
color: #0000ff;
}
red.css
div {
color: #ff0000;
}
You have it backwards. The !default flag tells Sass that this is the value to use if it doesn't a previous declaration doesn't exist.
$foo: red;
$foo: blue !default;
#debug $foo; // red
$bar: red !default;
$bar: blue;
#debug $bar; // blue
You need to place the !default flag on the default null values, not the theme values.
In addition to application.css.scss, I have multiple partials like homepage.css.scss. At the moment I have to add #import 'bootstrap' to each one of them in order to use bootstrap variables and mixins.
Let's say I want to change my default links colour to red, I'd add that to application.css.scss. But the links in homepage.css.scss will not be red because the bootstrap import will override it with blue.
In LESS, I can do #import (reference) "bootstrap", how can I do that in SASS?
The closest you will get is a silent class / placeholder. These work a little different to how LESS and reference work, you can read more on them here: http://blog.teamtreehouse.com/extending-placeholder-selectors-with-sass
LESS
lib.less
.class {
background: red;
}
main.less
#import (reference) "lib";
.anotherClass {
&:extend(.class);
}
SASS
lib.sass
%class {
background: red;
}
main.sass
#import "lib";
.anotherClass {
#extend %class;
}
CSS Output
.anotherClass {
background: red;
}