I want to make the password optional while login into the system. If the user enters the password the login works fine and return the jwt token, when I entered to try to login only with email it gives the following error:-
Undefined index: password (500 Internal Server Error)
The following is the code of my login method
public function authenticateUser($request)
{
$input = $request->only('email','password');
if (!$authorized = Auth::attempt($input, true)) {
return $this->failure('Credentials doesnot match our records!', 401);
} else {
$token = $this->respondWithToken($authorized);
return $this->success('Login Successfully !', $token, 200);
}
}
protected function respondWithToken($token)
{
return [
'token' => $token,
'token_type' => 'Bearer',
'expires_in' => Auth::factory()->getTTL() * 60,
'user' => Auth::user()
];
}
so basically, what I want is when a user enters an email it will login and should return the token, and if the user login with email and password then it should also work and return the token.
You can create a custom Authentication User Provider that will work around this potentially missing 'password' field. Though, I would probably not here. You can check the input yourself to see if there is a password or not. If there is pass it through attempt like normal. If it is not there find the user using the configured User Provider and login to the guard (what attempt is doing).
Perhaps something like this:
public function authenticateUser($request)
{
if ($request->has('password')) {
$token = Auth::attempt($request->only(['email', 'password']));
} else {
$token = ($user = Auth::getProvider()->retrieveByCredentials($request->only(['email'])))
? Auth::login($user)
: false;
}
return $token
? $this->success('Login Successfully !', $this->respondWithToken($token), 200)
: $this->failure('Credentials do not match our records!', 401);
}
The error that you're getting means that there is no password key in the input array that you're sending via request. This happens on this line:
$input = $request->only('email','password');
In order to bypass that, you would need go get all inputs, or check if those inputs exist and then read from them:
//Get all inputs
$input = $request->input();
//Or get email first, and then check for password
$input['email'] = $request->email;
$input['password'] = $request->filled('password') ? $request->password : null;
Note: Since I can't see your actual login functions, this might not work with only email, since password might be required parameter. If that's the case, you will have to alter those functions.
Related
I have an api that has a method to start and I am calling it from a frontend project.
In the front end project I use Guzzle to make the call via post to the api and login, from which I get back a json with the user data and a jwt token.
But when I receive the token as I manage the session, I must create a session and save the token, since the laravel to authenticate I need a model user and have a database, which of course I do not have in this backend because I call the api to log in, which brings a token and user data, then as I manage it from the backend, I'm a little lost there.
$api = new Api();
$response = $api->loginapi(['user'=>'wings#test.com','password'=>'123']);
Because here I could not do Auth::login($user) to generate the session.
Because I don't have here the database because the login is done from the api.
There I call the api, of which the answer is the token, but how do I manage it from here, creating a session? saving the token?
thanks for your help.
With api, you don't usually manage a session. usually, you'd call something like
Auth::attempt([
'email' => 'me#example.com',
'password' => 'myPassword'
]);
If the credentials are correct, laravel will include a Set-Cookie header in response, and, that is how you authenticate with api. Via an auth cookie. You don't need to do anything else.
Let's show you how:
//AuthController.php
public function login(Request $request) {
$validatedData = $request->validate([
'email' => 'required|email',
'password' => 'required'
]);
if(Auth::attempt($validatedData)){
return ['success' => 'true'];
}
else{
return ['success' => false, 'message' => 'Email or password Invalid'];
}
}
public function currentUser (){
return Auth::user();
}
Now, the APi file
Route::post('/login', ['App\Http\Controllers\AuthController', 'login']);
Route::get('/current_user', ['App\Http\Controllers\AuthController', 'currentUser']);
Now if you make a call to /api/current_user initially, you'll get null response since you're not currently logged in. But once you make request to /api/login and you get a successful response, you are now logged in. Now if you go to /api/current_user, you should see that you're already logged in.
Important ::
If you are using fetch, you need to include credentials if you're using something other than fetch, check out how to use credentials with that library or api
You want to use the API to authenticate and then use the SessionGuard to create session including the remember_me handling.
This is the default login controller endpoint for logging in. You don't want to change this, as it makes sure that user's do not have endless login attempts (protects for brut-force attacks) and redirects to your current location.
public function login(Request $request)
{
$this->validateLogin($request);
// If the class is using the ThrottlesLogins trait, we can automatically throttle
// the login attempts for this application. We'll key this by the username and
// the IP address of the client making these requests into this application.
if (method_exists($this, 'hasTooManyLoginAttempts') &&
$this->hasTooManyLoginAttempts($request)) {
$this->fireLockoutEvent($request);
return $this->sendLockoutResponse($request);
}
if ($this->attemptLogin($request)) {
if ($request->hasSession()) {
$request->session()->put('auth.password_confirmed_at', time());
}
return $this->sendLoginResponse($request);
}
// If the login attempt was unsuccessful we will increment the number of attempts
// to login and redirect the user back to the login form. Of course, when this
// user surpasses their maximum number of attempts they will get locked out.
$this->incrementLoginAttempts($request);
return $this->sendFailedLoginResponse($request);
}
The core happens when we try to "attemptLogin" at
protected function attemptLogin(Request $request)
{
return $this->guard()->attempt(
$this->credentials($request), $request->boolean('remember')
);
}
When using the SessioGurad (which is default) the method attemptLogin fires a couple of events, checks if the user has valid credentials (by hashing the password and matching it with db) and then logs the user in, including the remember me functionality.
Now, if you don't care about events, you can just check from your API if the credentials match and then use the login method from the guard. This will also handle the remember me functionality. Something like this:
protected function attemptLogin(Request $request)
{
$username = $request->input($this->username());
$password = $request->input('password');
$result = \Illuminate\Support\Facades\Http::post(env('YOUR_API_DOMAIN') . '/api/v0/login' , [
'username' => $username,
'password' => $password
])->json();
if(empty($result['success'])){
return false;
}
// Maybe you need to create the user here if the login is for the first time?
$user = User::where('username', '=', $username)->first();
$this->guard()->login(
$user, $request->boolean('remember')
);
return true;
}
I'm just starting with laravel 5, I'm doing a simple login function to check if email and password passed by user matches with the email and password stored in the database. I've been reading the documentation ([https://laravel.com/docs/5.0/hashing1) but Hash::check($content['password'], $user->{'password'}) returns false always. My code looks like this.
When I create a new user I hash the password like that:
$content = json_decode($request->getContent(), true);
$user -> password = Hash::make($content['email']);
And my login function looks like that:
public function login(Request $request)
{
$content = json_decode($request -> getContent(), true);
$user = DB::table('users')->where('email', $content['email'])->first();
if (Hash::check($content['password'], $user->{'password'}))
{
// Redirect to dashboard
}
}
Thanks in advance!!
Actually you are hashing the email instead of password while creating the user. change the code from
$user->password = Hash::make($content['email']);
To
$user->password = Hash::make($content['password']);
i came up with same issue. check database users table, password field. make the size of the field to 60 or more. this fixed mine.
The facade Hash just will encrypt your data:
Hash::make('123456');
is the same that:
$password = bcrypt('123456');
to login a user you need to use AuthController functions:
Auth::attempt(['email' => 'test#test.com' , 'password' => Hash::make('password')]);
it's a example.
If you're receiving a request, you can add this method to login:
if(Auth::attempt(['email' => $request->email, 'password' => $request->password , 'active' => 1])){
flash()->success('Successfully logged in!');
return redirect('/');
}
the attempt function will hash your password field and will compare with database data.
I am making an application and I want users to login with their google account. I have user oauth-4-laravel and I have this:
UserController.php
// get data from input
$code = Input::get('code');
// get google service
$googleService = Artdarek\OAuth\Facade\OAuth::consumer("Google");
if (!empty($code)) {
// This was a callback request from google, get the token
$token = $googleService->requestAccessToken($code);
// Send a request with it
$result = json_decode($googleService->request('https://www.googleapis.com/oauth2/v1/userinfo'), true);
$user = DB::select('select id from users where email = ?', array($result['email']));
if (empty($user)) {
$data = new User;
$data->Username = $result['name'];
$data->email = $result['email'];
$data->first_name = $result['given_name'];
$data->last_name = $result['family_name'];
$data->save();
}
if (Auth::attempt(array('email' => $result['email']))) {
return Redirect::to('/');
} else {
echo 'error';
}
}
// if not ask for permission first
else {
// get googleService authorization
$url = $googleService->getAuthorizationUri();
// return to facebook login url
return Redirect::to((string) $url);
}
}
After this i get successfully user info and can save user name, in my database. The problem is that after this I want to redirect user to home page and can't do this because with normal login i chec authentication:
if (Auth::attempt(array('email' => Input::get('email'), 'password' => Input::get('password')))) {
return Response::json(["redirect_to" => "/"]);
and with google login i get onlu username , user id and email. How to login directly the user after google login?
If you need to log an existing user instance into your application, you may simply call the login method with the instance:
$user = User::find(1);
Auth::login($user);
This is equivalent to logging in a user via credentials using the attempt method.
For further info see: http://laravel.com/docs/security#manually
Upon login, I return the user object + session token in JSON form, so that the mobile device that connects to my application can be authenticated.
However, I have a difficulty understanding how would I go about authenticating the user only with his session id?
Once logged in, the mobile device sends the session token upon every request, which means I somehow need to check whether it's the same user (using a custom auth filter).
How would I do it?
You may have a table for saving tokens
Add a filter in routes.php
Route::group(array('before' => 'auth'), function() { ... })
And in the filters.php you can search the token in the database, if isn't exist you return a no access response
Route::filter('auth', function () {
$input_token = Input::get('token');
if (!empty($input_token)) {
$validator = Validator::make(
['token' => $input_token],
['token' => 'token']
);
if (!$validator->fails()) {
$token = Token::where('hash', $input_token)->first();
if ($token) {
$user = User::find($token->user_id);
if ($user) {
Auth::login($user);
return;
}
}
}
}
$response = Response::make(json_encode([
'error' => true,
'messages' => [
Lang::get('errors.NO_ACCESS')
]
]), 200);
$response->header('Content-Type', 'application/json');
return $response;
});
You could do it like this:
$sessionID = '4842e441673747d0ce8b809fc5d1d06883fde3af'; // get this from \Session::getId(); from your previous authenticated request (after logging in because it changes).
$s = new \Illuminate\Session\Store(NULL, \Session::getHandler(), $sessionID);
$s->start();
$userID = $s->get('login_82e5d2c56bdd0811318f0cf078b78bfc');
\Session::set('login_82e5d2c56bdd0811318f0cf078b78bfc', $userID);
return \Auth::user();
Not the prettiest code but it works. It creates an instance of a session using the previous Session ID, then start loads it up from file. The user ID is in that key, so then it just sets the user id on the current session. Then when you call Auth::user() it loads up the User using that user id.
The reason for all the numbers in the key is because the larval developer thought it would be smart to hash the Auth class name to make the key as unique as possible... :-S
I am building a REST API with Laravel, and I have a filter that checks for a TOKEN:
Route::filter('api.auth', function() {
$token = Request::header('X-CSRF-Token') ? Request::header('X-CSRF-Token') : '';
if (empty($token)) {
return Response::json(
['message' => 'A valid API key is required!'],
401
);
};
$user = User::where('token', '=', $token);
if ($user->count()) {
$user = $user->first();
Auth::login($user);
} else {
return Response::json(
['message' => 'Your token has expired!'],
401
);
};
});
If everything is ok, the filter will log in the user with uth::login($user);
How can I log him for only 1 request?
Since this filter is going to be checked on every request, I think it would be better to log the user out each time.
I have seen this in Laravel's docs, not sure how to apply it:
if (Auth::once($credentials))
{
//
}
Could I have a callback in my response? where I could log the user out?
/*
Get all products.
*/
public function getProducts() {
$products = Auth::user()->products;
return Response::json($products, 200);
}
Any ideas?
If you haven't user's password use this:
if(Auth::onceUsingId($userId)) {
// do something here
}
If I correctly understand the question then I would say that, just replace following
Auth::login($user);
with this (To log the user in only for current request):
Auth::once(['email' => $user->email, 'password' => $user->password]);
If you log in a user only for once then you don't have to manually logo out the user, the user will be asked again for to log in on next request.