can you say to me, where is the error. I wanna write in console the content of the a[i] in every for run. The output could be 6 digits. There is compiler Alert:
/usr/bin/ld.bfd: warning: link.res contains output sections; did you forget -T?
...Program finished with exit code 0
program Hello;
type aha = array [1..6] of integer;
var
a: aha;
n,x,i: integer;
begin
a[1]:=2;
a[2]:=6;
a[3]:=4;
a[4]:=2;
a[5]:=4;
a[6]:=3;
n:=6;
x:=a[1];
for i:=2 to n do
begin
{
if (a[i-1]>= x) then
begin
a[i]:=a[i] - x div 2;
end;
else
begin
a[i]:=a[i] + x;
x:= x + mod x(a[i] + 1);
end;
writeln (a[i]);
}
end;
end.
Related
I'm coding a little program but it won't print out the right math answer, it just stays at 993.
The Code:
program _Gul_;
uses crt;
var a: integer;
var b: integer;
begin
writeln('1000 - 7?');
a := 1000;
b := a - 7;
while a > 0 do
begin
writeln (a - 7, ' - 7?');
delay(120);
a := a - 7;
writeln (b)
if a = 6 then
break;
end;
writeln('я гуль')
end
I don't quite know why it is not working. I defined "b" and made a command that prints it out and the output is just:
You never update the value in b. In point of fact, b is not necessary to your program at all. Your printing strategy is also more complicated than it needs to be. Print a minus 7, then do the subtraction and print it. This prevents the program telling you the rest of 6 - 7 is 6.
program _Gul_;
uses
crt;
var
a: integer;
begin
a := 1000;
while a > 0 do
begin
writeln (a, ' - 7?');
delay(120);
a := a - 7;
writeln (a);
if a = 6 then
break;
end;
writeln('я гуль')
end.
In this program when I try to put the code blocks [1] and [2] in procedures they don't work properly when calling them, and when I keep them in the main program only the first one works properly and the second doesn't and when I comment out the first one the second one works as it's supposed...can you please spot the error, I think it's with getting the files names from the user cause when I choose the file's name it works properly
program Linked_lists_files;
type
Node = ^T;
T = record
num : integer;
next : Node;
End;
var
File1 : Text;
N, i, j, cmp, y, x, Num, matrixvalue : integer;
Head, Tail, Head2, Tail2, Head3, Tail3 : Node;
s : string;
matrix : array [1..20, 1..20] of Integer;
// procedures
// [1]
Procedure fillFile();
Begin
write('Input file name to create : ');
readln(s);
assign(File1,s);
rewrite(File1);
Repeat
write('Enter a number : ');
readln(N);
if (N>=0) then
writeln(File1, N);
Until (N<0);
close(File1);
End;
// [2]
Procedure GetFromFile();
Begin
cmp := 0;
write('Enter file name to read from : ');
readln(s);
assign(File1, s);
reset(File1);
while not eof(File1) Do
Begin
readln(File1, N);
if (Head = Nil) then
Begin
new(Head);
Tail := Head;
End
Else
Begin
new(Tail^.next);
Tail := Tail^.next;
End;
Tail^.num := N;
Tail^.next := Nil;
cmp := cmp + 1;
End;
Close(File1);
Write('Elements of the list : ');
Tail := Head;
if (Head<>nil) then
Begin
while(Tail <> nil) Do
Begin
write('[',Tail^.num,']', ' ');
Tail := Tail^.next;
End;
End
Else
Writeln('[!] The list is empty');
writeln;
writeln('Number of elements in the list : ', cmp);
End;
// [3]
Procedure SaveFromFile();
Begin
Head := Nil;
write('Enter file name to read from : '); readln(s);
writeln('[+] Fill in your list');
Repeat
write('+ Enter an integer : ');
read(y);
if (y>=0) then
Begin
if (Head = Nil) then
Begin
new(Head);
Tail := Head;
End
Else
Begin
new(Tail^.next);
Tail := Tail^.next;
End;
Tail^.num := y;
Tail^.next := Nil;
End;
Until y<0;
assign(File1, s);
rewrite(File1);
Tail := Head;
while(Tail <> nil) Do
Begin
Num := Tail^.num;
Tail := Tail^.next;
Writeln(File1, Num);
End;
Close(File1);
Writeln('[+] Elements of the lists have been successfully added to the new file');
End;
// [4]
Procedure SquareMatrix();
Begin
cmp := 0;
x := 0;
writeln('[+] Fill in your list');
Repeat
write('+ Enter an integer : ');
read(y);
if (y>=0) then
Begin
if (Head3 = Nil) then
Begin
new(Head3);
Tail3 := Head3;
End
Else
Begin
new(Tail3^.next);
Tail3 := Tail3^.next;
End;
Tail3^.num := y;
Tail3^.next := Nil;
cmp := cmp + 1;
End;
Until y<0;
while (cmp<>1) Do
Begin
if (cmp mod 2 <> 0) and (cmp <> 1) then
x := x + 1;
cmp := cmp div 2;
End;
if (x>0) then
writeln('[-] False')
Else
writeln('[+]True');
End;
// [5]
Procedure ElementsOfSM();
Begin
cmp := 0;
x := 0;
writeln('[+] Fill in your list');
Repeat
write('+ Enter an integer : ');
read(y);
if (y>=0) then
Begin
if (Head = Nil) then
Begin
new(Head);
Tail := Head;
End
Else
Begin
new(Tail^.next);
Tail := Tail^.next;
End;
Tail^.num := y;
Tail^.next := Nil;
cmp := cmp + 1;
End;
Until y<0;
Tail := Head;
i := 1;
j := 1;
while(Tail <> nil) Do
Begin
matrixvalue := Tail^.num;
matrix[i,j] := matrixvalue;
Tail := Tail^.next;
j := j + 1;
if (j = sqrt(cmp)+1) then
Begin
i := i + 1;
j := 1;
End;
End;
for i:=1 to cmp Do
for j:=1 to cmp Do
Begin
if (matrix[i,j]<>0) then
writeln('[',matrix[i,j],']',' : ','[',i,',',j,']');
End;
End;
// [6]
Procedure Element();
Begin
write('Enter the number of the line : ');
read(i);
write('Enter the number of the column : ');
read(j);
write('The element corresponding to ','[',i,',',j,'] is : ','[',matrix[i,j],']');
writeln;
End;
// [7]
Procedure WriteP();
Begin
write('Enter the number of the line : ');
read(i);
write('Enter the number of the column : ');
read(j);
write('Enter the value you want to pass in : ');
read(N);
matrix[i,j] := N;
writeln('The new matrix');
for i:=1 to cmp Do
for j:=1 to cmp Do
Begin
if (matrix[i,j]<>0) then
writeln('[',matrix[i,j],']',' : ','[',i,',',j,']');
End;
writeln;
End;
// [8]
Procedure Content();
Begin
write('Enter the number of the line : ');
read(i);
write('Enter the number of the column : ');
read(j);
writeln('The value stored inn this cell is : ','[', matrix[i,j],']');
End;
// Start of main program
Begin
Head := Nil;
Repeat
writeln('*********** MENU ***********');
writeln('[1] fillFile');
writeln('[2] GetFromFile');
writeln('[3] SaveFromFile');
writeln('[4] SquareMatrix');
writeln('[5] ElementsOfSM');
writeln('[6] Element');
writeln('[7] WriteP');
writeln('[8] Content');
writeln('*********** End ***********');
write('Choose one : ');
read(N);
case N of
1 : fillFile();
2 : GetFromFile();
3 : SaveFromFile();
4 : SquareMatrix();
5 : ElementsOfSM();
6 : Element();
7 : WriteP();
8 : Content();
End;
Until (N<>1) and (N<>2) and (N<>3) and (N<>4) and (N<>5) and (N<>6) and (N<>7) and (N<>8) and (N<>9);
End.
The problem you describe is being caused by the known behaviour of the Read statement; basically, the second (and subsequent) times you call it, it returns immediately, without waiting for any keyboard input and without reading anything.
This happen because FPC is closely based on Object Pacal in the commercial Delphi development package, and in Delphi's case, this is the officially documented behaviour.
From the Delphi (v7) online help:
Delphi syntax:
Text files:
procedure Read( [ var F: Text; ] V1 [, V2,...,Vn ] );
Description
The Read procedure can be used in Delphi code in the following ways.
[...]
With a type string variable:
Read reads all characters up to, but not including, the next end-of-line
marker or until Eof(F) becomes true; it does not skip to the next line after reading. If the resulting string is longer than the maximum length of the string variable, it is truncated.
After the first Read, each subsequent Read sees the end-of-line marker and returns a zero-length string (emphasis added).
Use multiple Readln calls to read successive string values.
Fortunately, the solution is simple, use readln, instead of read, as in
readln(s);
Update Make sure you replace all instances of read by readln, as you have left a number of them unchanged, as #TomBrunberg has commented.
After that, run your code again and select 1 from the menu and you will find that fillFile executes, but the program terminates on the until ... line. And that's because it is a very bad idea to use the same global variable, in this case N for several different purposes throughout the program. So, you should edit your code further (and carefully) so that as far as possible it only uses global variables for global purposes. Turn all all the other variables into local variables, preferably with different names than the global ones. If after that you are still having problems, submit a new question focused on that.
I'm learning algorithms and I'm trying to make an algorithm that extracts numbers lets say n in [1..100] from a string. Hopefully I get an easier algorithm.
I tried the following :
procedure ReadQuery(var t : tab); // t is an array of Integer.
var
x,v,e : Integer;
inputs : String;
begin
//readln(inputs);
inputs:='1 2 3';
j:= 1;
// make sure that there is one space between two integers
repeat
x:= pos(' ', inputs); // position of the space
delete(inputs, x, 1)
until (x = 0);
x:= pos(' ', inputs); // position of the space
while x <> 0 do
begin
x:= pos(' ', inputs); //(1) '1_2_3' (2) '2_3'
val(copy(inputs, 1, x-1), v, e); // v = value | e = error pos
t[j]:=v;
delete(inputs, 1, x); //(1) '2_3' (2) '3'
j:=j+1; //(1) j = 2 (2) j = 3
//writeln(v);
end;
//j:=j+1; // <--- The mistake were simply here.
val(inputs, v, e);
t[j]:=v;
//writeln(v);
end;
I get this result ( resolved ) :
1
2
0
3
expected :
1
2
3
PS : I'm not very advanced, so excuse me for reducing you to basics.
Thanks for everyone who is trying to share knowledge.
Your code is rather inefficient and it also doesn't work for strings containing numbers in general.
A standard and performant approach would be like this:
type
TIntArr = array of Integer;
function GetNumbers(const S: string): TIntArr;
const
AllocStep = 1024;
Digits = ['0'..'9'];
var
i: Integer;
InNumber: Boolean;
NumStartPos: Integer;
NumCount: Integer;
procedure Add(Value: Integer);
begin
if NumCount = Length(Result) then
SetLength(Result, Length(Result) + AllocStep);
Result[NumCount] := Value;
Inc(NumCount);
end;
begin
InNumber := False;
NumCount := 0;
for i := 1 to S.Length do
if not InNumber then
begin
if S[i] in Digits then
begin
NumStartPos := i;
InNumber := True;
end;
end
else
begin
if not (S[i] in Digits) then
begin
Add(StrToInt(Copy(S, NumStartPos, i - NumStartPos)));
InNumber := False;
end;
end;
if InNumber then
Add(StrToInt(Copy(S, NumStartPos)));
SetLength(Result, NumCount);
end;
This code is intentionally written in a somewhat old-fashioned Pascal way. If you are using a modern version of Delphi, you wouldn't write it like this. (Instead, you'd use a TList<Integer> and make a few other adjustments.)
Try with the following inputs:
521 cats, 432 dogs, and 1487 rabbits
1 2 3 4 5000 star 6000
alpha1beta2gamma3delta
a1024b2048cdef32
a1b2c3
32h50s
5020
012 123!
horses
(empty string)
Make sure you fully understand the algorithm! Run it on paper a few times, line by line.
I am trying to verify all elements of an array[1..199] if there are negative elements. This code doesn't verify first element of the array. I am obliged to do this by recursive method.
I tried to do a separate condition, but this didn't worked. I firstly made it with for and then changed to recursive method.
Var a:array[1..100] of integer;n:integer;
Function E(n:integer):boolean;
Begin
if n=0 then E:=False
else if a[n]<0 then E:=True
else E:=E(n-1);
End;
Begin
readln(n);
for i:=1 to n do
readln(a[i]);
writeln('Are there negative numbers in array? ',E(n));
readln();
End;
I expect the output true if there are any negative elements or false if there not.
I am not a Pascal expert but I think you are looking for something like this:
program Hello;
var
arrayWithNegatives : array[1..10] of integer = (-1,20,30,40,50,60,71,80,90,91);
arrayWithPositives : array[1..10] of integer = (0,20,30,40,50,60,71,80,90,91);
emptyArray : array of integer;
Function HasNegativeNumbers(a: array of integer; n:integer):boolean;
Begin
if n < 0 then HasNegativeNumbers := False
else if a[n] < 0 then HasNegativeNumbers := True
else HasNegativeNumbers := HasNegativeNumbers(a, n - 1);
End;
begin
writeln (HasNegativeNumbers(arrayWithNegatives, length(arrayWithNegatives) - 1));
writeln (HasNegativeNumbers(arrayWithPositives, length(arrayWithPositives) - 1));
writeln (HasNegativeNumbers(emptyArray, length(emptyArray) - 1))
end.
I need a code to go from decimal to binary numbers, but my program shows them invert, example: needs to show 1011000 but it brings out 0001101.
+ I cant use massives and array in this program.
var
x,y,i:longint;
BEGIN
readln(y);
repeat
x:= y mod 2;
y:= y div 2;
write(x);
until y = 0;
END.
I think you can use recursion function. For example:
procedure dec2bin(y)
BEGIN
x := y mod 2;
y := y mod 2;
if y > 1 then
dec2bin(y)
end
write(x)
END
BEGIN
readln(y);
dec2bin(y)
END.
I'm not sure in correct syntax because I working with Pascal long time ago. But I think you can understand my idea and make this.
This should answer what you are looking for
function decimalToBinary(a:LongInt):String;
var d:Integer;
str:String;
Begin
str:='';
while a>0 do begin
d:=a mod 2;
str:=concat(IntToStr(d),str);
a:=a div 2;
end;
decimalToBinary:=str;
End;
This is my code. It works!
program convert;
var
number : integer;
procedure dec2bin(x : integer);
begin
// general case
if (x > 1) then dec2bin(x div 2);
// to print the result
if (x mod 2 = 0) then write('0')
else write('1');
end;
begin
write('Decimal: '); readln(number);
write('Binary : ');
dec2bin(number);
end.