I use pagination CodeIgniter. I want to remove page number from url or show page number 1,2,3 not 5,10,15. How can I do that please help me I'm beginner at CodeIgniter.
Thanks
Here is my action inside my controller
class Wiki_egypt extends CI_Controller {
public function __construct()
{
parent::__construct();
$this->load->helper("url");
$this->load->model('Tours_model');
$this->load->model('Wiki_egypt_model');
$this->load->model('Meta_model');
$this->load->library("pagination");
}
public function Wikipedia_egypt() {
$config = array();
$config["base_url"] = base_url() . "/wikipedia-egypt";
$config["total_rows"] = $this->Wiki_egypt_model->record_count();
$config["per_page"] = 5;
$config["uri_segment"] = 2;
$config['num_links'] = 3;
$this->pagination->initialize($config);
$page = ($this->uri->segment(2)) ? $this->uri->segment(2) : 0;
$data["wikis"] = $this->Wiki_egypt_model->
fetch_departments($config["per_page"], $page);
$data["links"] = $this->pagination->create_links();
$data['meta_tags'] = $this->Meta_model->meta_wikis_eg();
$this->load->view("Header", $data);
$this->load->view("Nav", $data);
$this->load->view("wiki_egypt/wikieg", $data);
$this->load->view("Footer");
}
}
Here is my action inside my Model
public function record_count() {
return $this->db->count_all("wiki_egypt");
}
public function fetch_departments($limit, $start) {
$this->db->limit($limit, $start);
$query = $this->db->order_by('id', 'DESC')->get("wiki_egypt");
if ($query->num_rows() > 0) {
foreach ($query->result() as $row) {
$data[] = $row;
}
return $data;
}
return false;
}
Here is my action inside my View
<?php echo $links; ?>
<?php
foreach($wikis as $row)
{
?>
<?php
} ?>
First you need another config there:
$config['use_page_numbers'] = TRUE;
Then you need to change the way your page variable works.
$page = ($this->uri->segment(2)) ? $this->uri->segment(2) : 1;
$page = $config['per_page'] * $page;
So now you're saying that your offset will be equal to the url page times the offset.
All the rest should work just the same.
Related
I am having the pagination kept in my codeigniter project. The links are all shown in the view page. But whichever link that I clicked is getting me to the same page...
The following is my controller code..
public function newsletter()
{
$this->load->library('pagination');
$config = array();
$config["base_url"] = base_url() . "index.php/welcome/newsletter";
$this->load->model('newsletter_model');
$total_row = $this->newsletter_model->record_count();
$config["total_rows"] = $total_row;
$config["per_page"] = 1;
$config['use_page_numbers'] = TRUE;
$config['num_links'] = $total_row;
$config['cur_tag_open'] = ' <a class="current">';
$config['cur_tag_close'] = '</a>';
$config['next_link'] = 'Next';
$config['prev_link'] = 'Previous';
$this->pagination->initialize($config);
if($this->uri->segment(3)){
$page = ($this->uri->segment(3)) ;
}
else{
$page = 1;
}
$this->load->model('newsletter_model');
$data["results"] = $this->newsletter_model->fetch_data($config["per_page"], $page);
$str_links = $this->pagination->create_links();
$data["links"] = explode(' ',$str_links );
$this->load->model('newsletter_model');
$data['rm_newsletter'] = $this->newsletter_model->get_rm_newsletter();
$this->load->view('newsletter/newsletter',$data);
}
The following is my view code:
foreach ($lt_newsletter as $letter) {
echo $newsletter['nl_newsletter']; }
<div id="pagination">
<ul class="pagination">
<?php foreach ($links as $link)
{
echo "<li>". $link."</li>";
} ?>
</ul>
</div>
And finally in my model:
public function fetch_data($limit, $id)
{
$this->db->limit($limit);
$this->db->where('nl_id', $id);
$query = $this->db->get("ins_newsletter");
if ($query->num_rows() > 0)
{
foreach ($query->result() as $row)
{
$data[] = $row;
}
}
}
public function record_count()
{
return $this->db->count_all("ins_newsletter");
}
public function get_rm_newsletter()
{
$data = $this->db->query('SELECT nl.* FROM ins_newsletter nl ORDER BY nl.nl_id DESC');
return $data->result_array();
}
In my browser all the links(1,2,3,4) are shown clearly, but after I click on every link(1,2,3,4), it is showing the same page with all the records. For presently, I have 4 records in my database and it lists all. Kindly point me where am i going wrong...! Thanks in Advance.
Maybe the error is in your model, I see that you have a
$this->db->where('nl_id', $id);
but in the function in the controller you pass two parameters
$data["results"] = $this->newsletter_model->fetch_data($config["per_page"], $page);
this are the pagination values, one for quantity of record,(not variable), and the other for the page you are passing (1,2,3,etc.)
So, you have to add another parameter to make the where. See this link in pagination does not work and if you have some other problem can tell me.
i'm new with CI and i tried a lot posibilities to make this run, but still it ain't working. Could you please tell me what i'm doing wrong?
So, Controller:
<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
class News extends CI_Controller {
public function __construct()
{
parent::__construct();
$this->load->model('model_add','',TRUE);
}
public function _remap($a){
if (isset($a) && !empty($a)):
switch ($a) {
case 'index':
$this->index();
break;
default:
$this->one_news($a);
break;
}
endif;
}
public function index()
{
$this->load->library('pagination');
$home=$this->uri->segment(2);
$limit=2;
$offset=0;
$query=$this->model_add->count_news($limit,$offset);
$config['base_url'] = base_url().'/news/';
$config['total_rows'] = $this->db->count_all('tdt_news');
$config['per_page'] = 2;
$config['uri_segment'] = 2;
$this->pagination->initialize($config);
$data = array('query' => $query,'page'=>$home);
$data['news'] = $query;
$this->load->view('main/header');
$this->load->view('main/news', $data);
$this->load->view('main/footer');
}
}
And the Model:
function count_news()
{
$query=$this->db->query("SELECT * FROM `tdt_news` ORDER BY `id` DESC LIMIT $limit, $offset;");
return $query->result();
}
I'll be very thankful for your help, thank you!
You have a series of errors
your count function in your model is missing parameters
you should reformat the SQL string
alternate and standard syntax in your view
renamed model class to empty string
heres a fixed version,
Controller:
<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');
class News extends CI_Controller {
public function __construct()
{
parent::__construct();
$this->load->model('model_add');
}
public function _remap($a){
if (isset($a) && !empty($a)) {
switch ($a) {
case 'index':
$this->index();
break;
default:
$this->one_news($a);
break;
}
}
}
public function index()
{
$this->load->library('pagination');
$home = $this->uri->segment(2);
$limit = 2;
$offset = 0;
$query=$this->model_add->count_news($limit,$offset);
$config['base_url'] = base_url().'/news/';
$config['total_rows'] = $this->db->count_all('tdt_news');
$config['per_page'] = 2;
$config['uri_segment'] = 2;
$this->pagination->initialize($config);
$data = array( 'query' => $query,
'page'=>$home,
'news' => $query);
$this->load->view('main/header');
$this->load->view('main/news', $data);
$this->load->view('main/footer');
}
}
Model:
// with default parameters just in case
function count_news($limit = 50, $offset = 0)
{
// and there is a nicer way to write your query
// it works with multiple dbs thanks to active record
$this->db->order_by('id','desc');
$query = $this->db->get('tdt_news', $limit, $offset);
return $query->result();
}
i'm new to codeigniter and i'm using codeigniter pagination by getting query result from Category Id, but the page always starts at page 2 .
how do i fix the pagination to set the start page at number page 1?
public function kategori($kat=''){
$config['base_url'] = base_url().'index.php/lowongan/kategori/'.$kat;
$data['db']=$this->query->katPostingan($kat);
$config['total_rows'] = $data['db']->num_rows();
$config['per_page'] = 1;
$config['uri_segment'] = 4;
$this->pagination->initialize($config);
$data2['paging'] = $this->pagination->create_links();
$page = ($this->uri->segment($config['uri_segment'])) ? $this->uri->segment($config['uri_segment']) : 0;
$data2['records'] = $this->query->katPos($kat, $config['per_page'], $page);
$this->load->view( 'user/hal_kategori',$data2);
}
and my model
public function katPos($kat='',$limit,$start){
$this->db->where("id_kat", $kat);
$this->db->limit($limit,$start);
$query = $this->db->get("showKat");
return $query;
}
public function katPostingan($kat=''){
$this->db->where("id_kat", $kat);
$query = $this->db->get("showKat");
return $query;
}
try a different way of solution,
controller(index())
$this->load->library('pagination');
$config['base_url'] = site_url().'classname/index';
$config['per_page'] = $this->config->item('pagination_number');
$config['uri_segment'] = 4;
$data['count']=$this->example_model->count();
$config['total_rows'] =$data['count'];
$data['classname']=$this->example_model->getall($this->config->item('pagination_number'),$this->uri->segment(4));
$this->pagination->initialize($config);
$data['page_link']=$this->pagination->create_links();
$this->load->view('users/classname.php',$data);
model
function getall($num,$offset)
{
$this->db->from('table_name');
$this->db->limit($num,$offset);
$query = $this->db->get();
return $query->result_array();
}
function count()
{
$this->db->from('table_name');
$query = $this->db->get();
$rowcount = $query->num_rows();
return( $rowcount);
}
View
<div class="pagination"> <?php echo $page_link;?> </div>
Codeigniter pagination Numbers not displayed correcly in result page,.
Plz help me.
/controller page code/
function search_all()
{
$this->load->view(‘prd’);
$config = array();
$config[‘base_url’] = base_url().’/product_search/search_all’;
$config[“total_rows”] = $this->search_product_model->record_count();
$config[“per_page”] = 8;
$config[“uri_segment”] = 3;
$this->pagination->initialize($config);
$page = ($this->uri->segment(3)) ? $this->uri->segment(3) : 0;
$data[“results”] = $this->search_product_model->
get_search($config[“per_page”], $page);
$data[“links”] = $this->pagination->create_links();
//$this->load->view(“example1”, $data);
$this->load->view(‘asd’, $data);
}
I think there is an problem with this
$config[“total_rows”] = $this->search_product_model->record_count();
For this you are not passing the search keys such that it will count all the data which it contains.If you get the record count based on search key then it will be fine.Like this
$config[“total_rows”] = $this->search_product_model->record_count('//search parameters');
and in your model:
Public function record_count($search_params)
{
$this->db->where('product',$search_params);
return $this->db->count_all(“products”);
}
You can modify as your needs like pass "color","type" to your record_count() function and based on that,you suggested to get "count_all".I hope it will works for you
Try this
function search_all()
{
$config[‘base_url’] = base_url(’product_search/search_all’);
$config[“total_rows”] = $this->search_product_model->record_count();//2 in your case
$config[“per_page”] = 8;
$config[“uri_segment”] = 3;
$this->pagination->initialize($config);
$page = ($this->uri->segment(3)) ? $this->uri->segment(3) : 0;
$data[“results”] = $this->search_product_model->
get_search($config[“per_page”], $page);
$data[“links”] = $this->pagination->create_links();
//$this->load->view(“example1”, $data);
$this->load->view(‘asd’, $data);
}
and at your model:
public function get_search($limit, $page)
{
//Add this...???
$this->db->limit($limit, $page); //or try $this->db->limit($page,$limit)
}
give search key in the record_count() function as parameters //You got 2 na.??
Then in placeof search_params put you same keys which are supplied to the record_count()
I have Admin controller in codeigniter
class Admin extends CI_Controller {
function __construct() {
parent::__construct();
if (!$this->tank_auth->is_logged_in()) redirect('login');
$this->load->library('pagination');
}
function index() {
$offset = $this->uri->segment(2);
$config['per_page'] = 3;
$data['sitetitle'] = 'Výpis jobů';
$data['listings'] = $this->Jobs_model->get_listings(0,$user_id = FALSE,$config['per_page'],$offset);
$config['uri_segment'] = 2;
$config['base_url'] = base_url().'admin/';
$config['total_rows'] = $this->db->count_all_results('jobs');
$this->pagination->initialize($config);
$this->template->set('title', 'Domovská stránka');
$this->template->load('template', 'site', $data);
}
}
and Jobs_model
function get_listings($category, $user_id = false, $limit = 0, $offset = 0) {
$data = array();
$this->db->order_by('id', 'desc');
$q = $this->db->get('jobs');
if ($category) {
$options = array('category' => $category);
$this->db->order_by('id', 'desc');
$this->db->where('category', $category);
$q = $this->db->get('jobs', $limit, $offset);
}
else {
$query = $this->db->order_by('id', 'desc');
if ($user_id) $query = $query->where('user_id', $user_id);
$q = $query->get('jobs',$limit, $offset);
}
if ($q->num_rows() > 0) {
foreach ($q->result_array() as $row) {
$data[] = $row;
}
}
$q->free_result();
return $data;
}
first page in paginatiom obtain data, but links generating in pagination localhost/sitename/admin/3 produce 404 error.
Where is problem in my script
You need to change:
$config['base_url'] = base_url().'admin/';
To:
$config['base_url'] = base_url().'admin/index/';
If you need the url to be like admin/3, you can use a route or _remap.
Side note: consider using this to get your page number rather than the URI class:
function index($offset = 0) {
// your code
}
It will do the same thing, but it's convenient to use the controller method arguments when possible.
You need to do some change.
$config['base_url']=base_url().'admin/index';
change
$config['uri_segment'] = 3;
check if you are using .htaccess or not. If you aren't, then $config['base_url'] in above should be
$config['base_url']=base_url().'index.php/admin/index';
If you get 404 error on codigniter paggination please check follwing things :
1 ) Check your controller it's index or somthing else if it's index then base_url should be :
base_url().'admin/index/pages' and if it's somethings else it should be :
base_url().'admin/somethingelse/pages'
2 ) Check 'uri_segment' by $this->uri->segment(4) so by this you got the page number then else will do the codiegniter.