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I have a for loop with inside two sed commands to edit different files. My problem is the second sed that should edit only the files named aaa but instead I get the error sed cannot edit "not a regular file".
for file in $directory
do [-e "$file"] || continue
sed -i 's/hello/hello1/g' "$file"
sed -i 's/hallo/hello12/g' [[ "$file" ~ aaa ]]
done
I suggest to replace
[-e "$file"]
with
[ -e "$file" ]
and
sed -i 's/hallo/hello12/g' [[ "$file" ~ aaa ]]
with
[[ "$file" =~ ^aaa$ ]] && sed -i 's/hallo/hello12/g' "$file"
Related
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I have list
dasfdsaf
afddt4fd
asdw5h6ufdh
sfds2dsddf2nu
dsfnjufsd443ajisdfaij
sdfjid654sij
asfdnu7sdfui
sdfmii
I want to move all lines containing numbers in it to new file.
If your grep has the -P option:
grep -P '\d' old_file > new_file
grep -vP '\d' old_file > temp
mv temp old_file
If -P isn't supported, use [0-9] instead of \d to match digits:
grep '[0-9]' old_file > new_file
grep -v '[0-9]' old_file > temp
mv temp old_file
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Exactly what the title says: what is the bash command for printing out the longest word in a text file that appears at least 10 times.
Try this Denis:
tr -s " " "\n" < file | while read -r l; do echo "${#l} $l"; done | sort -n | awk '$1 >= 10 ' | awk '{print $2}' | tail -n1
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the text file contains
from:sender#gmail.com
to:receiver#gmail.com
subject:
attachment:asdfg.xlsx
all arguments should be handled in shell script
I tried but if subject contains space then it gives problem
from=$(echo $1|cut -d ":" -f 2 <<< "$1")
to=$(echo $2|cut -d ":" -f 2 <<< "$2")
subject="$3"
attachment=$(echo $4|cut -d ":" -f 2 <<< "$4")
When you could read the Input_file then passing it as a variable will not be a good option IMHO, so create variables inside script by reading Input_file, opting OP's method of creating variables but enhancing code to awk.
from=$(awk -F':' '/from/{print $NF}' Input_file)
to=$(awk -F':' '/^to/{print $NF}' Input_file)
subject=$(awk -F':' '/^subject/{if($NF){print $NF} else {print "NULL subject"}}' Input_file)
attachment=$(awk -F':' '/^attachment/{print $NF}' Input_file)
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I have this list of inputs :
imalex
thislara
heiscarl
how to get :
alex
lara
carl
grep
Use grep to take the last four chars:
grep -o '.\{4\}$' file
The -o option makes sure only matched parts are printed.
sed
Using sed we can achieve a similar result:
sed 's/.*\(.\{4\}\)$/\1/' a
Here we capture the last four digits and replace each line with those last four digits. They are captured in a group \( \) and inserted \1.
read & tail
We can also grab the last five chars (including the newline) of each line using tail and a -c option. We do that for each line using read.
while read line; do
tail -c 5 <<< $line
done < file
2 answers using substring arithmetic
bash:
while read word; do
echo "${word:${#word}-4}"
done <<<"$list"
awk
echo "$list" | awk '{print substr($NF, length($NF)-4+1)}'
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My requirement is to create files in the respective directory (existing) in the server.
#!/bin/ksh
file1=$1 # Signifies DATE config file
file2=$2 # Signifies MONT config file
file4=$3 # Signifies SEQN config file
config1=`cat $file1 | awk -F "," '{print $1}'`
config2=`cat $file2 | awk -F "," '{print $2}'`
config3=`cat $file3 | awk -F "," '{print $3}'`
echo AT_EXTENSION_"$config1""$config2""$config3".dat
cat MY_DIR/$echo
Will this KornShell (ksh) script work to create a file in the respective directory with the contents in echo?
As the question currently stands, it appears that you want to write the contents of files $file1, $file2, and $file3 into a file called AT_EXTENSION_"$config1""$config2""$config3".dat. If this is the case, then do:
cat "$file1" "$file2" "$file3" >AT_EXTENSION_"$config1""$config2""$config3".dat
You should try to not use cat with awk and you should change back tics to parentheses $(code) and also add double quote around the variable name, to make sure file is read correctly
Not like this:
config1=`cat $file1 | awk -F "," '{print $1}'`
But like this:
config1=$(awk -F "," '{print $1}' "$file1")