I have been stuck on something on PowerQuery for hours now and I cannot seem to find a solution to my problem.
Context
I try to use "Table.TransformColumns" to change the table.
My code is
= Table.TransformColumns(table,{"A Only",
each Table.SelectRows(_, (X)=> Text.Contains(X[Customer Search Term], [Word A]))})
and the error msg is
Expression.Error: The column 'Word A' of the table wasn't found.
If I change the [Word A] into "AAA", the code can process normally.
Does anyone know how to use the columns[Word A] instead of the string "AAA"?
The problem here is that Table.Transform applies a transformation to a single column and cannot reference other columns without some sort of workaround.
See this post for more information:
Power Query Transform a Column based on Another Column
The simplest approach is to define a new custom column (which can reference multiple existing columns) and then delete the existing one that it replaces.
To do it without needing an extra column, you can use the approach in the linked post and use a row transformation, which has the other columns as part of the record you're transforming:
= Table.FromRecords(Table.TransformRows(table,
(r) => Record.TransformFields(r, {"A Only",
each Table.SelectRows(_, (X) => Text.Contains(X[Search Term], r[Word A]))
})))
Note the r in front of [Word A]. This is the context that was missing with Table.Transform.
Related
I have a data range in Google Sheets where I want to sort the data by column B, but only return column A. If it matters, column A is a string, column B is integers.
Using =SORT(A1:B10,2,FALSE) returns both columns A and B, sorted by column B...but I only want it to return column A.
I've also tried:
=QUERY((SORT(A1:B10,2,FALSE)),"select *") <- does exactly the same as sort, tried just for testing
=QUERY((SORT(A1:B10,2,FALSE)),"select col1") <- #value error
=QUERY((SORT(A1:B10,2,FALSE)),"select A") <- #value error (also tried "select A:A" and "select A1:A10")
=QUERY((SORT(A1:B10,2,FALSE)),"select Stat") <- #value error
I've also tried all of the above, but starting with =QUERY(A1:B10,SORT(...
Am I using QUERY wrong? Is SORT not what I want? I could just use SORT in a hidden part of the sheet, then reference the column I want but that feels cheaty, I want to know if there's a way to do what I want to do.
You can set in the first part the column you want to be returned, then the column you want to be sorted with, and then if it's ascending or not (you can then add other columns, obviously. They don't need to be included nor contiguous, but of the same size). Try this:
=SORT(A1:A10,B1:B10,FALSE)
use:
=INDEX(SORT(A1:A10,2,),,1)
I've been working on a spreadsheet with over 100 rows, and found a hacky way to incorporate a "hide" checkbox that will hide any row where column C matches a specific value (building type), specified beside the box. To do this, I first created a function like this: =FILTER(Data!A1, OR(Data!$C1<>$O$2, $P$2)) and dragged that across every row and column in a seperate sheet. This reads as, "Display current cell if the corresponding column C in that row in Data does not match the building type, or if the the checkbox is checked. This way, the whole row is hidden when the building type matches, and the box is unchecked. A1 adjusted to each row individually, $C1 referenced the building's type, $O$2 referenced the targeted type to potentially hide, and $P$2 was the checkbox.
Problem #1: This created a lot of formulas in hundreds of cells, and when the building type was not found, it displayed #N/A across the entire row. A Filter View was able to hide these values, but it was inconvenient to have to reset the values every time I wanted to hide or unhide another building type.
My Attempt to Fix: I used a filter function once again to recreate the entire sheet from one cell, hiding the appropriate rows, using this: =FILTER(Data!A2:J191, ARRAYFORMULA((Data!$C2:C191<>$O$2)+(Data!D2:D191*$P$2)) This is the hacky part. I multiplied the checkbox's "true" by an array arbitrary positive numerical values in the D column to "OR" it with each building type value to achieve the same goal as before, but for EVERY cell.
Problem #2 arose: When I get my beautiful sheet, I can not sort it via a filter view, or it will throw an error and display nothing. I'm resorting to sorting the original tab, but intend to have it be ignored entirely. So how do I combine these two, Filter View, and Filter Function, to create a nice spreadsheet where I can SORT AND HIDE rows?
Bonus Problem #3: To add more buttons, my formula is this: =FILTER(Data!A1:J191, ARRAYFORMULA((Data!$C1:C191<>$O$2)+(Data!D2:D192*$P$2)), ARRAYFORMULA((Data!$C1:C191<>$O$3)+(Data!D2:D192*$P$3)), ARRAYFORMULA((Data!$C1:C191<>$O$4)+(Data!D2:D192*$P$4)), ARRAYFORMULA((Data!$C1:C191<>$O$5)+(Data!D2:D192*$P$5)), ARRAYFORMULA((Data!$C1:C191<>$O$6)+(Data!D2:D192*$P$6)), ARRAYFORMULA((Data!$C1:C191<>$O$7)+(Data!D2:D192*$P$7)), ARRAYFORMULA((Data!$C1:C191<>$O$8)+(Data!D2:D192*$P$8)), ARRAYFORMULA((Data!$C1:C191<>$O$9)+(Data!D2:D192*$P$9))) This is ugly, and very slow to load. Is there a way to create a function range to handle the same checks on multiple rows, and crunch it into a single formula?
Here is another monstrosity (this one has less repetition) for you:
=QUERY(
{IGNORE!A2:J, IGNORE!P2:P},
"SELECT * "
& "WHERE Col3 is not null "
& IF(COUNTIF(P2:P9, False) = 0, "", "AND NOT Col3 MATCHES '^" & JOIN("$|^", IFNA(FILTER(O2:O9, P2:P9 = False))) & "$' ")
& IF(COUNTIF(A2:K2, ">0") = 0, "", "ORDER BY Col" & JOIN(", Col", IFNA(FILTER(COLUMN(A2:K2) & IF(COLUMN(A2:K2) = 1, "", " DESC"), A2:K2)))),
0
)
Your checkboxes should remain. The second row can have just True/False values, no need for column number (a simple change will be needed COUNTIF(A2:K2, ">0") -> COUNTIF(A2:K2, True)). Also consequent sort works now (but only in the actual order of columns: if checked 1, 3, 4 then it will be sorted first by 1, then by 2, then by 4). You could place another config table on the right about sorting, where you would select all the columns you wish to sort by, their mutual order, and desc/asc for them.
Edit: added IFNA so FILTER won't return an error, changed multiple ANDS to MATCHES and simple regexes.
I have a google sheet with a column of item names, (i.e. "Amy dress, Brooke Tshirt, etc.) Some of these items have a prefix - JK or JL (JK - Amy Dress, JL - Brooke Dress) in addition to the non-prefixed versions. I'm trying to find a way to search for a prefix (JK - ) and return the item name associated with that prefix in a different column.
Search for "JK - ", find JK - Amy Dress, return Amy Dress. Please help!
Tried lookup and match, but this is too complicated for my skill set.
You can try to use a Google Sheets Query.
If you want something like this:
Based on the table above the query you'll have to use will be:
=query(A:B;"select * where B Starts with 'JK'";-1)
If you want to select only the B column just remove the A:
=query(B;"select * where B Starts with 'JK'";-1)
The query automatically creates a new "table" with all the values you need.
If you want to make it customizable use the following query:
=query(A:B;"select * where B Starts with '"&$G1&"'";-1)
In this case instead of "JK" we are searching something that starts with the content of the cell G1. So if you type JK in the G1 cell you will obtain the same result as before.
Hope it helps.
I have a Pig latin related problem:
I have this data below (in one row):
A = LOAD 'records' AS (f1:chararray, f2:chararray,f3:chararray, f4:chararray,f5:chararray, f6:chararray);
DUMP A;
(FITKA,FINVA,FINVU,FEEVA,FETKA,FINVA)
Now I have another dataset:
B = LOAD 'values' AS (f1:chararray, f2:chararray);
Dump B;
(FINVA,0.454535)
(FITKA,0.124411)
(FEEVA,0.123133)
And I would like to get those two dataset joined. I would get corresponding value from dataset B and place that value beside the value from dataset A. So expected output is below:
FITKA 0.123133, FINVA 0.454535 and so on ..
(They can also be like: FITKA, 0.123133, FINVA, 0.454535 and so on .. )
And then I would be able to multiply values (0.123133 x 0.454535 .. and so on) because they are on the same row now and this is what I want.
Of course I can join column by column but then values appear "end of row" and then I can clean it by using another foreach generate. But, I want some simpler solution without too many joins which may cause performance issues.
Dataset A is text (Sentence in one way..).
So what are my options to achieve this?
Any help would be nice.
A sentence can be represented as a tuple and contains a bag of tuples (word, count).
Therefore, I suggest you change the way you store your data to the following format:
sentence:tuple(words:bag{wordcount:tuple(word, count)})
This is too tough for me guys. It's for Jeremy!
I have two tables (although I can also envision needing to join a third table) and I want to sum one field and count rows, in the same, table while joining with another table and return the result in json format.
First of all, the data type field that needs to be summed, is numeric(10,2) and the data is inserted as params['amount'].to_f.
The tables are expense_projects which has the name of the project and the company id and expense_items which has the company_id, item and amount (to mention just the critical columns) - the "company_id" columns are disambiguated.
So, the following code:
expense_items = DB[:expense_projects].left_join(:expense_items, :expense_project_id => :project_id).where(:project_company_id => company_id).to_a.to_json
works fine but when I add
expense_total = expense_items.sum(:amount).to_f.to_json
I get an error message which says
TypeError - no implicit conversion of Symbol into Integer:
so, the first question is why and how can this be fixed?
Then I want to join the two tables and get all the project names form the left (first table) and sum amount and count items in the second table. I have tried
DB[:expense_projects].left_join(:expense_items, :expense_items_company_id => expense_projects_company_id).count(:item).sum(:amount).to_json
and variations of this, all of which fails.
I would like a result which gets all the project names (even if there are no expense entries and returns something like:
project item_count item_amount
pr 1 7 34.87
pr 2 0 0
and so on. How can this be achieved with one query returning the result in json format?
Many thanks, guys.
Figured it out, I hope this helps somebody else:
DB[:expense_projects___p].where(:project_company_id=>user_company_id).
left_join(:expense_items___i, :expense_project_id=>:project_id).
select_group(:p__project_name).
select_more{count(:i__item_id)}.
select_more{sum(:i__amount)}.to_a.to_json