Each row 3 column sum result show as running total in last column, then from 2nd row > first row running total show in first column with group by - oracle

Question

Each row Total value go for the set OP value for the next row, except the first row
My Table Data
Id
WarehouseId
ProductId
OP
RE
IS
Total
1
100
10000
10
0
0
10
2
100
10000
0
0
5
5
4
100
10000
0
15
0
15
5
101
10001
15
0
0
15
6
101
10001
0
0
5
5
8
101
10001
0
15
0
15
9
101
10002
25
0
0
25
10
101
10002
0
0
10
10
11
101
10002
0
15
0
15
I want to show below result (OP+RE)-IS=Total
Id
WarehouseId
ProductId
OP
RE
IS
Total
1
100
10000
10
0
0
10
2
100
10000
10
0
5
5
4
100
10000
5
15
0
20
5
101
10001
15
0
0
15
6
101
10001
15
0
5
10
8
101
10001
10
15
0
25
9
101
10002
25
0
0
25
10
101
10002
25
0
10
15
11
101
10002
15
15
0
30

Answer 1

You can use recursive subquery factoring for that purpose like below. You need to rank your data as you have some gaps between IDs in your data. Column name = IS is not allowed, You should use "IS" enclosed by ".
with t1 ( ID, WAREHOUSEID, PRODUCTID, OP, RE, "IS", RNB, rnb_per_wh_prod) as (
select ID, WAREHOUSEID, PRODUCTID, OP, RE, "IS"
, row_number()over(order by WAREHOUSEID, PRODUCTID, ID) rnb
, row_number()over(partition by WAREHOUSEID, PRODUCTID order by ID) rnb_per_wh_prod
from Your_table t
), cte (ID, WAREHOUSEID, PRODUCTID, OP, RE, "IS", Total, RNB) as (
select ID, WAREHOUSEID, PRODUCTID, OP, RE, "IS", OP + RE - "IS", RNB
from t1
where rnb_per_wh_prod = 1
union all
select t1.ID
, t1.WAREHOUSEID
, t1.PRODUCTID
, case when t1.op = 0 then c.OP + c.RE - c."IS" else t1.OP end as OP
, t1.RE
, t1."IS"
, case when t1.op = 0 then c.OP + c.RE - c."IS" else t1.OP end + t1.RE - t1."IS" total
, t1.RNB
from cte c
join t1 on (t1.RNB = c.RNB + 1
and c.WAREHOUSEID = t1.WAREHOUSEID
and c.PRODUCTID = t1.PRODUCTID)
)
select ID, WAREHOUSEID, PRODUCTID, OP, RE, "IS", TOTAL
from cte
order by id
;

Answer 2

If I understand the problem correctly, "every 3 row" is a coincidence in your data; in fact, the computation must be done separately for each product in each warehouse, no matter how many rows there are for each distinct combination. And the "id" column is in reality some sort of timestamp - ordering is by "id".
If so, you can do it all in a single query using analytic sum(). Instead of creating a table for testing, I included all the sample data in a WITH clause at the top of the query itself; you can remove the WITH clause, and use your actual table and column names. I also changed the column name is to is_ since is is a reserved keyword, it can't be a column name.
Note also that I am ignoring your existing total column completely (I didn't even include it in the sample data); I assume it doesn't exist in your real-life data, and instead it is part of your attempt at a solution. You don't need it - not in the way you have it in your question.
with
sample_data (id, warehouseid, productid, op, re, is_) as (
select 1, 100, 10000, 10, 0, 0 from dual union all
select 2, 100, 10000, 0, 0, 5 from dual union all
select 4, 100, 10000, 0, 15, 0 from dual union all
select 5, 101, 10001, 15, 0, 0 from dual union all
select 6, 101, 10001, 0, 0, 5 from dual union all
select 8, 101, 10001, 0, 15, 0 from dual union all
select 9, 101, 10002, 25, 0, 0 from dual union all
select 10, 101, 10002, 0, 0, 10 from dual union all
select 11, 101, 10002, 0, 15, 0 from dual
)
select id, warehouseid, productid,
nvl(sum(op + re - is_) over (partition by warehouseid, productid
order by id rows between unbounded preceding and 1 preceding),
op) as op,
re, is_,
sum(op + re - is_) over
(partition by warehouseid, productid order by id) as total
from sample_data
;
ID WAREHOUSEID PRODUCTID OP RE IS_ TOTAL
------ ----------- ---------- ---------- ---------- ---------- ----------
1 100 10000 10 0 0 10
2 100 10000 10 0 5 5
4 100 10000 5 15 0 20
5 101 10001 15 0 0 15
6 101 10001 15 0 5 10
8 101 10001 10 15 0 25
9 101 10002 25 0 0 25
10 101 10002 25 0 10 15
11 101 10002 15 15 0 30